内容正文:
广东中考解答题题型突破
突破一 实数的运算和化简求值
1. (2024·临夏州)计算:-+2 0250.
-3+1
=2-3+1
=0.
实数的运算
2. (2024·大庆)计算:-(2 024+π)0+tan 60°.
=1.
3. (2024·济南)计算:-(π-3.14)0++-2cos 30°.
=6.
4. (2024·北京)计算:(π-5)0+-2sin 30°+.
.
5. (2024·内蒙古)计算:-+tan 60°++(π-2 024)0.
+1
=11.
6. (2024·遂宁)计算:sin 45°+++.
+2+2 021
=2 024.
1. (2024·济宁)先化简,再求值:x(y-4x)+(2x+y)(2x-y),其中x=,y=2.
解:原式=(xy-4x2)+(4x2-y2)
=xy-4x2+4x2-y2
=xy-y2.
×2-22=1-4=-3.
化简求值
2. (2024·甘肃改编)先化简,再求值:[(2a-b)2-(2a+b)(2a-b)]÷2b,其中a=,b=.
解:原式=[4a2-4ab+b2-(4a2-b2)]÷2b
=(4a2-4ab+b2-4a2+b2)÷2b
=(-4ab+2b2)÷2b
=-2a+b.
=0.
3. (2024·宿迁)先化简,再求值:(1+)·,其中x=+3.
.
.
4. (2024·青海)先化简,再求值:(-)÷(-),其中x=2-y.
.
.
5. (2024·牡丹江)先化简,再求值:,并从-1,0,1,2,3中选一个合适的数代入求值.
.
∵x≠0且x≠3,∴x=-1或x=1或x=2.
. (答案不唯一)
6. (2023·西宁)先化简,再求值:(-)÷,其中a,b是方程x2+x-6=0的两个根.
·a(a-b)
·a(a-b)
.
∵a,b是方程x2+x-6=0的两个根,
=6.
$$