数列讲义二-2025届高三数学一轮复习

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2025高考--数列(一轮复习)课时二

知识点一  根据规律填写数列中的某项,数列求和的其他方法,数列新定义  

典例1、对于项数为eqId294f5ba74cdf695fc9a8a8e52f421328的有穷数列eqId83cf38189d5cbf627d2b82ac0eb76006,设eqId686ece75006ad358f23314dc8a246e11为eqId332a51673c2ae8b003e5f31b71579617中的最大值,称数列eqId034ba25825c13725931c483aa47c9363是eqId83cf38189d5cbf627d2b82ac0eb76006的控制数列.例如数列3,5,4,7的控制数列是3,5,5,7.

(1)若各项均为正整数的数列eqId83cf38189d5cbf627d2b82ac0eb76006的控制数列是2,3,4,6,6,写出所有的eqId83cf38189d5cbf627d2b82ac0eb76006;

(2)设eqId034ba25825c13725931c483aa47c9363是eqId83cf38189d5cbf627d2b82ac0eb76006的控制数列,满足eqId4c8a59672f406ba5b297ecabbba62bbf(eqIdc5db41a1f31d6baee7c69990811edb9f为常数,eqIdb2156cba674f50d2c546502b4a2ed929).证明:eqIdbdf0bd1c527c68be985fa95ff6354fe0.

(3)考虑正整数eqIde5aa2de6deb84e4a63b9797d47033a66的所有排列,将每种排列都视为一个有穷数列eqId57ef6d44448092ebdb9e4a49d866a749.是否存在数列eqId57ef6d44448092ebdb9e4a49d866a749,使它的控制数列为等差数列?若存在,求出满足条件的数列eqId57ef6d44448092ebdb9e4a49d866a749的个数;若不存在,请说明理由.

 

 

 

 

 

 

 

随堂练习:给定整数eqIdb6a24198bd04c29321ae5dc5a28fe421(eqIdf5818ede14d21f6df9ef9c2bfe09286c),设集合eqIdf0e53e63811f83121eba1ca9efb17515,记集合eqIdc54d41b965c7b1771c84fabb87ae6258.

(1)若eqId3f77cadcea108fc0b1f680a8840a274c,求集合eqId7f9e8449aad35c5d840a3395ea86df6d;

(2)若eqId9304e71a623c4412188a800046a970d0构成以eqIde72adb45c60c2f63b46e65ff787302bf为首项,eqId5c02bc0c74292b1e8f395f90935d3174(eqIdc4ce64685821c3e55c07f151996ca8c3)为公差的等差数列,求证:集合eqId7f9e8449aad35c5d840a3395ea86df6d中的元素个数为eqId627a57cd9fdb1f586f35d9825b6bcc0b;

(3)若eqId9304e71a623c4412188a800046a970d0构成以eqId5ca7d1107389675d32b56ec097464c14为首项,eqId5ca7d1107389675d32b56ec097464c14为公比的等比数列,求集合eqId7f9e8449aad35c5d840a3395ea86df6d中元素的个数及所有元素之和.

 

 

 

 

 

 

 

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典例2、设数集eqIdcf231f8f86fb922df4ca0c87f044cec3满足:①任意eqId1c8647b00cc8c8f35555c7d78cf2812c,有eqIda6e2e79843faf62dde86bf858d1e0569;②任意x,eqId45c8b2714e2f6ddfdd6b05d3b4de1149,有eqId9b8e5872f45d4b878b0119997cb5bae2或eqId84734fbba70c0b45045fabf8090f810b,则称数集eqIdcf231f8f86fb922df4ca0c87f044cec3具有性质eqIddad2a36927223bd70f426ba06aea4b45.

(1)判断数集eqIdb2161a642b95463642adc3892850bc74和eqId6976dd6abc25367343e4c7157644483c是否具有性质eqIddad2a36927223bd70f426ba06aea4b45,并说明理由;

(2)若数集eqId19c812823ecb5cdc8d9384a167b4071a且eqIdd678c255575be87d0c8f2c7562355290具有性质eqIddad2a36927223bd70f426ba06aea4b45.

(i)当eqIde45cf86650443d1b86c79b1e3edc7e5c时,求证:eqIde72adb45c60c2f63b46e65ff787302bf,eqId3e88093a749c0d46e0ee931ecfaff925,…,eqId96abfe2da27a63e6affb19a0c80236d9是等差数列;

(ii)当eqIde72adb45c60c2f63b46e65ff787302bf,eqId3e88093a749c0d46e0ee931ecfaff925,…,eqId96abfe2da27a63e6affb19a0c80236d9不是等差数列时,求eqIdb6a24198bd04c29321ae5dc5a28fe421的最大值.

 

 

 

 

 

 


随堂练习:已知项数为eqIdf469b44890fecc0a252667ac1a18d98a的有穷数列eqId83cf38189d5cbf627d2b82ac0eb76006满足如下两个性质,则称数列eqId83cf38189d5cbf627d2b82ac0eb76006具有性质P;

①eqIde1303d0ffccd6e56ce784bdf368c796c;②对任意的eqId2c05b9832b09731a574d4a4adf7448de、eqId1812f1d1e2e3efb01498a6652f14df10,eqIdabf9fc9e8c9940547678ff7934363f52与eqId4a9ba31f0ced977668623337671d7093至少有一个是数列eqId83cf38189d5cbf627d2b82ac0eb76006中的项.

(1)分别判断数列eqIdbdaa19de263700a15fcf213d64a8cd57、eqId61128ab996360a038e6e64d82fcba004、eqIdb8860d9787671b53b1ab68b3d526f5ca、eqId8c748e40ba21ac5063d3bccaa57ef278和eqId61128ab996360a038e6e64d82fcba004、eqIdb8860d9787671b53b1ab68b3d526f5ca、eqIdcd3304e23f3b0f9569c4140ca89b6498、eqId8c748e40ba21ac5063d3bccaa57ef278是否具有性质eqIddad2a36927223bd70f426ba06aea4b45,并说明理由;

(2)若数列eqId83cf38189d5cbf627d2b82ac0eb76006具有性质eqIddad2a36927223bd70f426ba06aea4b45,求证:eqId81405bfe8acd87c8755e1eabe49f06e3;

(3)若数列eqId83cf38189d5cbf627d2b82ac0eb76006具有性质eqIddad2a36927223bd70f426ba06aea4b45,且eqId83cf38189d5cbf627d2b82ac0eb76006不是等比数列,求eqIdf0a532e15e232cb4b99a8d4d07c89575的值.

 

 

 

 

 

 

 

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知识点二   由递推关系证明数列是等差数列,错位相减法求和  

典例3、已知eqId08eb71ecf8d733b6932f4680874dbbf3为数列eqId83cf38189d5cbf627d2b82ac0eb76006的前eqIdb6a24198bd04c29321ae5dc5a28fe421项和,eqId4922a6bf159673b8ade7f3ba04b9aedf.

(1)证明:数列eqIdad801eb3687b2a97af6b218f818a3836为等比数列;

(2)求数列eqId0496f142d8ae5acb06e83526eaa3ef87的前eqIdb6a24198bd04c29321ae5dc5a28fe421项和eqIdf1ae9a3b0b7aeb1545b65d91aa371b3c.

 

 

 

 

 

 

 

 

 

 


随堂练习:已知数列eqId83cf38189d5cbf627d2b82ac0eb76006中,eqId2cdf53108bee755f5aa9a34ea4d163e4,且满足eqIdfd336807786813def408ab356a7590a5.

(1)证明:数列eqId70e1c06829bf8a351bf0d2d29d2889f1为等比数列,并求数列eqId83cf38189d5cbf627d2b82ac0eb76006的通项公式;

(2)若eqId78b9e45762fdcd4560ae282d377f4158,求数列eqId034ba25825c13725931c483aa47c9363的前eqIdb6a24198bd04c29321ae5dc5a28fe421项和eqId08eb71ecf8d733b6932f4680874dbbf3.

 

 

 

 

 

 

 

 

 

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