内容正文:
14.1.4 整式的乘法(1)——单项式乘以单项式.
复习回顾
(1)同底数幂的乘法:底数不变,指数相加.式子表达:
(2)幂的乘方:底数不变,指数相乘.式子表达:
(3)积的乘方:等于把积的每一个因式分别乘方,再把所得的幂相乘.
式子表达: 注:以上 m,n 均为正整数.
(4) 单项式×单项式=( )( )( )
(5)= = = = = = =
= = = =
= = =
计算:1. 1.ac5•bc2 2. a2x5•(-3a3bx2)
3. (-4a2b)(-8a); 4. 2x2 ·5x3
5. 4y ·(-3xy2) 6. (5x)3(-2xy2)
7. (-2x)2 · 3x2 8. (-3a)3(-2a)2
9. 10.
练习2:判断正误
1. 4a2 •2a4 = 8a8 ( )
2. 6a3 •5a2=11a5 ( )
3. (-7a)•(-3a3)=-21a4 ( )
4. 3a2b•4a3=12a5 ( )
练习3:下面的计算对不对?不对的请改正
(1)3a3.2a2=6a6
(2) 2x2.3x2=6x4
⑶3x2·4x2 =12x2
⑷5y3·3y5=15y15
练习4:计算
(1) (-3ab)(-a2c)·6ab
(2) (-5x2y)·(-4x3y2)·(xy)2;
(3)(2x3y2)3·3yz2+4x4y3z2·(-6x5y4)
答案:
复习回顾
(1)同底数幂的乘法:底数不变,指数相加.式子表达:
(2)幂的乘方:底数不变,指数相乘.式子表达:
(3)积的乘方:等于把积的每一个因式分别乘方,再把所得的幂相乘.
式子表达: 注:以上 m,n 均为正整数.
(3) 单项式×单项式=(系数× 系数)( 同底数幂×同底数幂)( 单独的幂)
(4)
(5)= 4 = 8 = 16 = 32 = 64 = 128 = 256
= 9 = 27 = 81 =243
= 25 = 125 =625
计算: 1.ac5•bc2 =
2. a2x5•(-3a3bx2) ==
3.(-4a2b)(-8a) = =
4. 2x2 ·5x3 =
5.4y ·(-3xy2)=
6. (5x)3(-2xy2)==
7.(-2x)2 · 3x2 = =
8. (-3a)3(-2a)2
9.
10.
练习2:判断正误
1. 4a2 •2a4 = 8a8 ( × )
2. 6a3 •5a2=11a5 ( × )
3. (-7a)•(-3a3)=-21a4 ( × )
4. 3a2b•4a3=12a5 ( × )
练习3:下面的计算对不对?不对的请改正
(1)3a3.2a2=6a6 × 改正:原式=
(2) 2x2.3x2=6x4 √
⑶3x2·4x2 =12x2 × 改正:原式=
⑷5y3·3y5=15y15 × 改正:原式=
练习4:计算
(1)(-3ab)(-a2c)·6ab
(2)
(-5x2y)·(-4x3y2)·(xy)2
(3)(2x3y2)3·3yz2+4x4y3z2·(-6x5y4)
=0
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