2.11 有理数的乘方 同步练习-2023-2024学年华东师大版七年级 数学上册

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2.11 有理数的乘方

一、单选题(每小题3分,共30分)

1.如果eqId0a6936d370d6a238a608ca56f87198de的倒数是eqIdacbc6a613224461ade69362d46550474,那eqIdc4776c5753e83a4e7033d3bb322d0fc6等于(    )

A.1 B.eqIdacbc6a613224461ade69362d46550474 C.2023 D.eqIdeeb10bc4abf30c687aee08b43708a15d

2.下列算式中,结果与eqIdf31f4bb041929b56b13ca6df65496228相等的是(      )

A.eqIdeccdb617ccece1942529f9cb87493226 B.eqId333d1ef634554e938639f65bd0d83447 C.eqId6a6e1ad99952f2f89519a1a335d447ed D.eqId085a73c2b8fb60fa810642040b599a5b

3.若一个数的平方等于eqId2b7073684723741238b95b3b9d3b5301,则这个数是@@@b28b5458cf3149bda2dba49970f6657b(        )

A.eqIde8d02ea8c4988c5c28ab93f0d70fb55a B.eqId2b7073684723741238b95b3b9d3b5301 C.eqIdb4b09c353126088902e6476dfe4e7735 D.eqIddab76dc75e249530e5ff939dc1135cff

4.比较(-4)3和-43,下列说法正确的是(      )

A.它们底数相同,指数也相同 B.它们底数相同,但指数不相同

C.虽然它们底数不同,但运算结果相同 D.它们所表示的意义相同,但运算结果不相同

5.关于乘方的说法正确的是(     )

A.eqIdf6f88d1d254194cd51b351c5003c0c6e的底数是-2 B.eqIdd848c07b9d60145f5904d3b31827fcc3表示-5乘以6的积

C.负数的任意次幂都是负数 D.eqIdbd6a8d2b35977000c07fa630fd99d45d

6.若eqId7326ea56be82bd616fec7e6aa3c884c8,则a,eqIdc8cc0b4997cae4d8aec791a1d3923314,eqIda2c70fcaa661df4fbcad820b439accda从小到大排列为(    )

A.a,eqIdc8cc0b4997cae4d8aec791a1d3923314,eqIda2c70fcaa661df4fbcad820b439accda B.a,eqIda2c70fcaa661df4fbcad820b439accda,eqIdc8cc0b4997cae4d8aec791a1d3923314 C.eqIda2c70fcaa661df4fbcad820b439accda,eqIdc8cc0b4997cae4d8aec791a1d3923314,a D.eqIdc8cc0b4997cae4d8aec791a1d3923314,a,eqIda2c70fcaa661df4fbcad820b439accda

7.已知x,y为有理数,且eqIde3f9ba50fb453d39640aae19a6391899,则eqId763e3f7c13047b2e100573f2f5877a7b的值为(    )

A.1 B.eqIdacbc6a613224461ade69362d46550474 C.2022 D.eqId128f5b3bd63bc1508211d032cafa5526

8.观察算式:31=3,32=9,33=27,34=81,35=243,36=729,37=2187,38=6561,….通过观察,用你所发现的规律确定32021的个位数字是(  )

A.3 B.9 C.7 D.1

9.已知n表示正整数,则eqIda2b1d13591f4e58d286d0e33e72a545c的值是(    )

A.0 B.1 C.1或0 D.以上答案都不对

10.一组数1,3,7,15,31…按下列分组.第一组eqId572ccd87e9a09449d963ef5fdf4d4b1f,第二组eqIda840bf42dcc7faf67e9db284877c73e4,第三组eqId1e2d4f0296b098805b8efb8e6309f7a6,…按此规律排列,则第10组所有数之和为(   )

A.eqId3717beb3801177e2e0f451ba4600c190 B.eqId7773099d92ef663f45e6ed5894332a4d C.eqIdb4710518d10685dbf46c8eef3d0a6b14 D.eqId5918dee292ffaebc8c0ac60686c0371a

二、填空题(每小题3分,共30分)

11.式子“eqId7cf07ee046070362e85dc5aec584510d”读作____________.

12.在eqIde5ceba0cdaf1e312601c122e45a01a42中,底数是_______,指数是_______.

13.已知|x|=2,y2=9,且|x﹣y|=y﹣x,则x﹣y=_______.page number 0


14.若eqId7995be8424c2a4230e28d278d25feaa4,则eqId91bde66645c9abf9e847ea67854c14a6_______.

15.已知下列各数:eqId0a6936d370d6a238a608ca56f87198de,eqId2f8d40e257f9c446b8e30fa841b74bbd,eqIdc8cc0b4997cae4d8aec791a1d3923314,eqId1ad82fa37dff30a4c54465ff7ef9f7ec,eqId7c17c63e7642f30be29dc6d99bcf6aa9,其中一定不为负数的有_______个;

16.已知eqId0f3217e6d9c9d67b5c5e1742a1d89bc5,eqId877bf31d8335d5840a5aea372df18580,eqId7dd471cf50e6554b3a871c7c910e3bb1,eqId6f0b8928f649b14f344caf0c3432071e,用“eqId4ff7942da6c3fc4005256fb1458557c0”号把eqId0a6936d370d6a238a608ca56f87198de、eqId2c94bb12cee76221e13f9ef955b0aab1、eqId071a7e733d466949ac935b4b8ee8d183、eqId5c02bc0c74292b1e8f395f90935d3174连接起来:______________.

17.下列各数eqId97a2e25691e583a64819323ecd136962,eqId2db60f3d6a6fd64cd7b958bb8b1134d9,eqIdeda3fa0c6d265e30bf94e32370935bf4,eqId579271a2140f3d248e12be082feae211,eqId0e3b8dc5e7281f57865648a5915d7513,eqIdeb3528d985a77044680e3fb9bd49c8e3中,负数有_______个.

18.计算得:eqId97a8d2e5a71a80815b3454e2fe4140e3,eqId738317df2665c72d92812b7714675549,eqIda52685b77856d28af3beed027d725506,eqId14f48b3a441172a0073be2877988167b,eqId914832f3edf43812c7ffa2c7fea02620,…,则eqId5b8186078b02271ddc6274a5e9fdb1f3 的个位数字是_______.

19.若eqIdeca54bd921fdc3d3dc6383b57e3f5be6与eqId39ea1b9794f2565c3d2d743e5d1640c8的值互为相反数,则eqId6fb2f87452a6a5fe9dd73766b16d66bf_______.

20.计算:(﹣2)101+(﹣2)100﹣(﹣1)2n﹣(﹣1)2n+1=_______.(其中n为正整数)

三、解答题(每小题8分,共40分)

21.计算:(﹣10)2+[(﹣5)2﹣(﹣22)×2]

 

 

 

 

22.计算:[2832019+(-283)2019-10]eqId2468403b3eba9e40bfa36f464e927738(-2)eqId09052719a6d55df23d74d8e3956257eaeqId8cf7e6d70e535ceea32bf4a7c81df21feqId2468403b3eba9e40bfa36f464e927738(-1)2020

 

 

 

 

 

23.阅读下面材料并完成填空,你能比较两个数20072008和20082007的大小吗?为了解决这个问题,先把问题一般化,即比较nn+1和(n+1)n的大小(n≥1的整数),然后,从分析这些简单情形入手,从中发现规律,经过归纳,猜想出结论.

(1)通过计算,比较下列各组两个数的大小(在横线上填>、=、<号)

①1221; ②2332; ③3443; ④4554; ⑤5665;…

(2)从第(1)小题的结果经过归纳,可以猜想,nn+1和(n+1)n的大小关系是什么?

(3)根据上面归纳猜想得到的一般结论,可以猜想得到2007200820082007(填>、=、<).

 

 

 

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