21.2.1 配方法 第二课时 课件 2022--2023学年人教版九年级数学上册

第二十一章 一元二次方... text has been truncated due to evaluation version limitation. 21.2.1 解一元二次方... text has been truncated due to evaluation version limitation. - - 配方法 01 ｜ 掌握... text has been truncated due to evaluation version limitation. 方程的基本... text has been truncated due to evaluation version limitation. 02 在配方法求... text has been truncated due to evaluation version limitation. 学习目标 ｜ 复习旧知 1. 用直... text has been truncated due to evaluation version limitation. (1) 4x2 = 1； (2) (x－2)2 - 4=0. ∴x1=，x2=-. 解：x2= ∴x1=4，x2=0. 解：（x-... text has been truncated due to evaluation version limitation.2=4. ∵x-2=... text has been truncated due to evaluation version limitation. 2. 你还... text has been truncated due to evaluation version limitation. (1) a2 + 2ab + b2 = ( ... text has been truncated due to evaluation version limitation.)2； a + b a − b (2) a2 - 2ab + b2 = ( ... text has been truncated due to evaluation version limitation.)2. 新知探究 在下列等式... text has been truncated due to evaluation version limitation. （1）x2 +2x+(___)2=(x+___)2 ; ... text has been truncated due to evaluation version limitation. （2）x2 -6x+(___)2=(x-___)2 ; （1）x2 +3x+(___)2=(x+___)2 ; ... text has been truncated due to evaluation version limitation. （2）x2 - x+(___)2=(x-___)2 ; 1 1 3 3 观察一次项... text has been truncated due to evaluation version limitation.? 填一填： x2 + px + ( ... text has been truncated due to evaluation version limitation.2 = ( x + ... text has been truncated due to evaluation version limitation.2. 归纳总结 配方的关键: ... text has been truncated due to evaluation version limitation. 把握二次项... text has been truncated due to evaluation version limitation. 1 的完全平方... text has been truncated due to evaluation version limitation.常数项等于... text has been truncated due to evaluation version limitation.. 想一想: ... text has been truncated due to evaluation version limitation. 怎样... text has been truncated due to evaluation version limitation. x2 + 4x + 1 =