内容正文:
代数计算
一、有理数的计算
1.计算:
(10(-3)十(-4)=:
(20+3.2)+(-43)=:
(3(-5)-(-8)=:
(4-8)×(-2)=:
(⑤12÷(-3)=:
(⑥-22=1
2
(T)ls4 alcol(一f3》=
(8114-lmww4aco1(+2f340)=
(9(-3)÷6=
(10)alvs fahcol(-f(1524))laivs-fahco1(-f(56))=
2.计算:
(1)12-(-18+(-7)-15:
(2)alvsalcol(f(78))-laivsfahcoI(-5(12))Hawsalcol((1))-318:
(3)47×(-12)+47X32-47×6:
(4(-81)÷214 Klalvs-fahcol(-y/49)÷(-8:
(⑤(-3)×2+1-4-(-2y:
3
(0-32-42÷|-6+8 XiavsAalcol(-/02):
(70(-1)22+(-3×-f19)-42÷(-2月
二、整式的计算
3.计算:
(1)3a+2h-5a-b:
(2)5a-3b+5(a-2b):
(3)30r+39-0一2):
(43(32-2ab-242-ab.
4.化简求值:32一x2+(2x一月一c2+3内,其中x=一3,y=2.
5.已知x十y=-3,求4r十8y-2rc)0als4 ahcol(x+3-)的值.
2
6.已知a-2引+laivs-nalco1b十/12》=0,求5m2b-2㎡2h-(ah2-2m㎡2b)-4-2ab2的值.
7.已知4=22+3ab-2a十5,B=2+ah-2
(1)当a=2,b=1时,求A一2B的值:
(2)若A一2B的值与a的取值无关,求b的值.