3.2.1 第3课时函数的值域课件-2023-2024学年高一上学期数学人教A版（2019）必修第一册

3.2.1 第3课时函... text has been truncated due to evaluation version limitation. 例1、求下列函数... text has been truncated due to evaluation version limitation. (1) 函... text has been truncated due to evaluation version limitation. y＝x＋1，x∈[-1,2... text has been truncated due to evaluation version limitation.的值域为_... text has been truncated due to evaluation version limitation. (2)函数 的值域为_____... text has been truncated due to evaluation version limitation. 变1：函数 ,x∈... text has been truncated due to evaluation version limitation.________... text has been truncated due to evaluation version limitation. 变2:函数 ，x∈... text has been truncated due to evaluation version limitation._____... text has been truncated due to evaluation version limitation. 变3：函数 的值域为... text has been truncated due to evaluation version limitation. [0,3) y [ , ] 1、观察法： (0,1] 总结：观察... text has been truncated due to evaluation version limitation.. 2、分离常数... text has been truncated due to evaluation version limitation. 例2. 求函数 ... text has been truncated due to evaluation version limitation. ... text has been truncated due to evaluation version limitation. 解： 所以函数的... text has been truncated due to evaluation version limitation. 总结：形如 的值... text has been truncated due to evaluation version limitation. 函数 y＝的值域为 ____... text has been truncated due to evaluation version limitation._； ... text has been truncated due to evaluation version limitation. ... text has been truncated due to evaluation version limitation. y 3、图象法 例3.求函数y=|x+... text has been truncated due to evaluation version limitation.的值域. 解：将函数化为... text has been truncated due to evaluation version limitation. 由图象可知... text has been truncated due to evaluation version limitation. ［3 ， 采用“数形... text has been truncated due to evaluation version limitation. 直观图形求... text has been truncated due to evaluation version limitation.. 总结： 图象法 1. 函数 ,x∈[1,4]的值域为_____... text has been truncated due to eval