内容正文:
5 、平方差公式
第1课时 平方差公式的认识
复习回顾
1、整式乘法中,多项式乘多项式的乘法法则
(m+b)(n+a)=mn+ma+bn+ba
2、计算下列各题
(1)(x+2)(x-2)
(2)(1+3a)(1-3a)
(3)(x+5y)(x-5y)
(4)(2y+z)(2y-z)
新课探究
(1)(x+2)(x-2)=x²-2x+2x-4=x²-4=x²-2²
(2)(1+3a)(1-3a)=1-3a+3a-9a²=1-9a²=1²-(3a)²
(3)(x+5y)(x-5y)=x²-5xy+5xy-25y²=x²-25y²=x²-(5y)²
(4)(2y+z)(2y-z)=4y²-2yz+2yz-z²=4y²-z²=(2y)²-z²
观察以上算式及其运算结果, 你有什么发现? 再举两例验证你的发现.
(a + b)(a - b) = a2 - b2
(1)(3m + 1)(3m - 1); (2)(x2 + y)(x2 - y).
= 9m2 - 3m + 3m - 1
=9m2 - 1.
= x4 - x2y + yx2 - y2
= x4 - y2.
(a + b)(a – b)= a2 – b2
两数和与这两数差的积,等于它们的平方差.
平方差公式
(1)(5 + 6x)(5 – 6x);
(2)(x – 2y)(x + 2y);
(3)(– m + n)(– m – n);
例
利用平方差公式计算:
解(1)(5 + 6x)(5 – 6x)
= 52 –(6x)2
= 25 – 36x2
(2)(x – 2y)(x + 2y)
= x2 –(2y)2
= x2 – 4y2
(3)(– m + n)(– m – n)
= (– m)2 – n2
= m2 – n2
(1)(3x + 2)( 3x – 2) ;
(2)(b + 2a)(2a – b).
练习
想一想
(a – b)(– a – b)= ?等于什么?
(a – b)(– a – b)
= –(a – b) (a + b)
= –(a2 – b2)
= b2 – a2
拓展
(1)(an + b)(an – b)
解(1)(an + b)(an – b)
=(an)2 – b2
= a2n – b2
(2)(a + 1)(a – 1)(a2 + 1)
解(2)(a + 1)(a – 1)(a2 + 1)
= (a2 – 1)(a2 + 1)
=(a2)2 – 1
= a4 – 1
1. 下列式子能用平方差公式计算吗?
① (– 3x + 3)(3x – 3) ② (b + 2a)(2a – b)
③ (– x + 2y)(– x – 2y) ④ (– 2x + y)(2x – y)
能,x2 – 4y2
随堂演练
不能
能,4a2 – b2
不能
2.下列计算结果正确的是( )
A.(x + 2)(x – 2) = x2 – 2
B.(x + 2)(3x – 2) = 3x2 – 4
C.(ab – c)(ab + c) = a2b2 – c2
D.(– x – y)(x + y) = x2 – y2
C
(a + b)(a – b)= a2 – b2
两数和与这两数差的积,等于它们的平方差.
平方差公式
课堂小结
1.完成课本P21页的练习,
2.完成练习册本课时的习题.
作业
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