内容正文:
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5.
xA
(x+3)(x-5)=x2-mx+n,
de
m= ,n= .
6.
mn
m+n=10,mn=24,
3
m2+n2= .
7.
mn
(a2+b2)4-8(a2+b2)2+16=0,
o
a2+b2
=p
.
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3
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8.
mn
a+b=5,ab=2,
qo
a2+3ab+b2
=p
.
9.
xA`j
x
=fçv
(3x2+2mx-x+1)+(2x2-mx+5)-(5x2-4mx-
6x)
=pÕ
x
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,
SeD}
m
=pg
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qo
m2+(4m-5)+m
=p
.
42
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3.(1)y y y2-4xy+4x2
(2)3m n 9m2+6mn+n2
4.D
5.
%
:(1)
45
=x2+6xy+9y2.
(2)
45
=x2-6x+9.
(3)
45
=9m2-12mn+4n2.
+
2
DE
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1.(a+b) c
a2+b2+c2+2ab+2ac+2bc
2.a2+b2-c2+2ab
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1.(1)2 2×1000×2 4000
(2)1 1 10201
2.D
3.
%
:(1)
45
=9801.
(2)
45
=1006009.
(3)
45
=10400.
(4)
45
=20002.
4.(1)52 25 (2)6m 6m+9
5.11
6.
%
:(1)
45
=20xy.
(2)
45
=3x+1.
(3)
45
=m2+4n2+4mn-1.
(4)
45
=24xy+28y2.
7.
%
:S=(3a+b)(2a+b)-(a+b)2
=5a2+3ab.
_
a=4,b=3̀ ,S=116m2.
7
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+
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1.-8 b3 b2 -43ab
2.B 3.C
4.
%
:(1)
45
=2a2bc.
(2)
45
=(x-y)2.
5.-24a3b4 -2a2
6.
%
:
45
=a3bc5.
+
2
DE
QP/2_OP/
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GHI
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1.6xy 5x 6y+5
2.15x2y 3x-2y 3.C
4.
%
:(1)
45
=2a-b.
(2)
45
=3x+1.
(3)
45
=-2-12cd
2.
(4)
45
=x+3.
5.
%
:
4LI5
=(8a4b-4a3+2a2)÷
1
2a=16a
3b-8a2+4a,
oNO,R
SM
(16a3b-8a2+4a)÷12a=
32a2b-16a+8.
`aNbc,
16T/0dF
1.1 1 2.B
3.
%
:(1)
45
=90000.
(2)
45
=3a3+2a2-12a.
(3)
45
=a16-1.
4.
%
:
45
=a2-2ac+c2-b2.
5.2 -15 6.52
7.
%
:a2+b2=2.
8.
%
:a2+3ab+b2=27.
701
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9.
%
:
45
=5mx+5x+6=x(5m+5)+6.
p245,qr
x
st
,
=>
5m+5=0,
=>
m=-1,
=>
m2+(4m-5)+m
=m2+4m-5+m
=(-1)2+4×(-1)-5-1
=-9.
+,-efNbc
1.-x9 2.m3n2 3.1017
4.4a2b6 5.18p3q4 6.D 7.C
8.
%
:(1)
45
=a8. (2)
45
=-x4.
9.-48a5 10.2mn2 11.-a4-a3+a
12.C
13.
%
:(1)
45
=x4.
(2)
45
=2a2+b4-3a2b.
(3)
45
=x3+1.
14.14b
2-a2 15.4x2+y2-z2+4xy
16.
%
:(1)
45
=4x2-16y2.
(2)
45
=a2+b2+c2-2ab+2bc-
2ac.
(3)
45
=n2-136m
2.
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hijBRkj
1
lmnj0opqr
+
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2.
HK
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3.
wx
#E
4.180°
#E
90°
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1.D
2.∠DOF ∠BOE ∠DOE ∠BOF
∠AOD
3.
yz{#E
4.B
5.
%
:
p2∠AOC=80°,∠1=30°,=>
∠COE=∠AOC-∠1=80°-30°=
5