内容正文:
20.
!
:(1)
3&
= 4a
3
3b( )2
2
· -32a
-2( )b3=16a69b4· -27b
3
8a( )6
=-6b.
(2)
3&
= 1
2pq3
÷ - 58p2q( )4 = 12pq3· -8p
2q4( )5
=-45pq.
21.
!
:∵3m=127,( )12
n
=16,∴3m=3-3,2-n=24,
∴
m=-3,
-n=4{ ,!0 m=-3,n=-4{ .∴mn=(-3)-4=181.
22.
!
:(1)∵m+m-1=3,
cd¨a
,
0
m2+2+m-2=9,
∴m2+m-2=7.
(2)
;
m2+m-2=7,
cd¨a
,
0
m4+2+m-4=49,
∴m4+m-4=47.
(3)∵(m-m-1)2=m2-2+m-2=7-2=5,
∴m-m-1 槡=±5.
[\K
]^#$_`/NRXab
1.
!
:
=
x
2=
y
3=
z
4=k(k≠0),*x=2k,y=3k,z=4k,
∴
3&
=2k+2×3k-4k2×2k-3k+4k=
4k
5k=
4
5.
2.
!
:
;
a2+ab-6b2=0
©
(a+3b)(a-2b)=0,
∴a+3b=0̀ a-2b=0,
∴a=-3b̀ a=2b.
1
a=-3b
2
,
3&
=-3b-b-3b+b=2;
1
a=2b
2
,
3&
=2b-b2b+b=
1
3.
∴a-ba+b-./ 2̀
1
3.
3.
!
:
3&
=c 1a+
1
b+
1( )c -1+b 1c+1a+1( )b -1+
a 1b+
1
c+
1( )a -1
= 1a+
1
b+
1( )c (c+b+a)-3.
∵a+b+c=0,∴
3&
=-3.
4.
!
:
3&
= a-2a(a+2)-
a-1
(a+2)[ ]2 ·a+2a-4
=(a-2)(a+2)-a(a-1)
a(a+2)2
·
a+2
a-4
= a-4
a(a+2)2
·
a+2
a-4
= 1a(a+2)=
1
a2+2a
.
∵a2+2a-1=0,∴a2+2a=1,
∴
3&
=1.
5.
!
:∵ x-1( )x
2
=( )32
2
,∴x2-2+1
x2
=94,
∴x2+1
x2
=174.
6.
!
:∵x
2+4x+3
x+1 =x+3=0,
∴
3&
=(x+3)(x-3)x-3 =x+3=0.
7.
!
:
3&
=- 2
a2-4
.
1
a=-3
2
,
3&
=-25.
8.
!
:
3&
= acabc+ac+c+
b
bc+b+1+
bc
abc+bc+b
= abcb+1+bc+
b
bc+b+1+
bc
1+bc+b
=1+b+bcbc+b+1=1.
[\c
#$NOXde$/fg
1.
!
:(1)
=ª«B¬J#
x
,
pq<(
,
0
600
x+40=
360
x,!0x=60.
rgh
,x=60
83%&ab-!
.
∴x+40=100.
u
:
A¬-F/
100
,
B¬-F/
60
.
(2)
=®¯°±²
2000
,
jª
m
«A¬
,
*
ªB¬
(30-m)
«
,
pq<(
,
0
100m+60(30-m)≤2000,!0m≤5.
u
:
4³jª
5
«A¬
.
2.
!
:(1)
=´µ«
A
¶·´n¸IJ¹º/
x
»
,
*´µ
«
B
¶·´n¸IJ¹º/
(x+25)
»
,
pq<
(
,
0
400
x=
500
x+25,!0x=100.
rgh
,x=100
83%&ab-!
,∴x+25=125.
u
:́
µ«
A
¶·´n¸IJ¹º8
100
»
.
(2)
=¼½´µ
A
¶·´n¸
m
«
,
*´µ
B
¶·´n
¸
(40-m)
«
,
pq<(
,
0
100m+125(40-m)≤4400,!0m≥24.
u
:
¼½´µ
A
¶·´n¸
24
«
.
3.
!
:(1)
=BEFGkl¾n¿ÀJ
x
K
,
*AEFGkl¾
n¿ÀJ
(x+10)
K
,
pq<(
,
0
45
x+10=
30
x,!0x=20.
rgh
,x=20
83%&ab-!
.
∴x+10=30.
u
:
AEFGkl¾n¿ÀJ
30
K
,
BEFGkl¾
n¿ÀJ
20
K
.
(2)
=AEÁFGÂo
a
K
,
pq<(
,
0
3
30+
2a
30≥2×
3
20,!0a≥3.
∴
AEÁFGÂo
3
K
.
4.
!
:(1)
=BobE
Kkl-ÃQÄÅ/
ẍ
aÆ
,
*A
obE
Kkl-ÃQÄÅ/
2ẍ
aÆ
.
pq<
(
,
0
400
x-
400
2x=4,!