内容正文:
.EF=BE+DE 10.3习题课(1) 3 1B2.C3B4B5.C67.8.6 9.号10. -2 a2b-a 1山.(1)原式=b6=, (2)原式=x千y)(x-y y(x-y) (2)如图,由(1)知,△ADE≌△ABE(SAS), (x+y)(x-y) ∴.AE=AE,∠DAE=BAE, xy-y-zy 3y2 设BE=x,DF=y, (x+y)(x-y)2之; .正方形ABCD的边长为1, (3)原式= 2p-3g+2p+3g 4p .CE=1-x,CF=1-y. 2p+3q)(2p-3q)4p-9g △CEF的周长为2, ∴.CE+CF+EF=2, (4)原式=a一_a2-11 a-1a-1a-i' .1-x+1-y+EF=2, 2 2(y-1) ..EF=x+y=BE+DF=DE'+DF=E'F. (5)原式=y+1)y-D(+DyD (AE=AE, y+1 -3y+3 3 在△E'AF和△EAF中,EF=EF, (y+1)(y-1)(y+1)(y-1)y+1 AF-AF, (6)原式=二2十+2 2x-2 .∴.△EAF≌△EAF(SSS), x(x-1) x(x-1) x(x-1) ∴.∠EAF=/EAF, x-2+x2+x-2x+2= ∴.∠DAE+∠DAF=∠BAE+∠DAF=∠EAF. ∠DAF+ZEAF+∠BAE-90°, x(x-1) x(-D-x-I 12.(1)② ./EAF=45°. (2)丢掉了分母 第10章分式 (3)原式= x-4 2(x-2) 10.1~10.2习题课 (.x+2)(x-2) -(x+2)(x-2) x-4-2.x+4 1.C2.A3.A4.A5.B6.D7.28.6.x2y2 (x+2)(x-2) (x+2)(x-2) 义专m器总 11.-1或-312.18 13.4)原式=+2)3=1- x+2 x+2 1B.1:分式2当没意义, (2)原式=2x-2+1_2(x+1)(x-1)+1=2(x+1)+ x-1 .x-1=0,解得x=1. x-1 1 (2:分式有意文, x-1 分式的值为整数,且x为整数, ∴.x一1≠0,即x≠1. .x一1=士1, (3):分式的值为0, x=2或0. 240解得x=-2. 10.3习题课(2) x1≠0, 1.原式=15-4-15=-1 H原式-a) 5a 5a 2.原式=c。+0+4,+4_20十0=2a: 把a=2,b=- 代入,原式 2+2×(-2)1 a十2 a十2 a十2 2a 1 2-2×(-2)3 3.原式=a+2a-2)-a+2=(a+2a-2 a-2 a+2 1 15.(1)工=h,y=a (a+2)(a-2)(a+2)(a-2)a-2 ac abe'be abci 2(x-1) x+5 3.x+3 2)2兰)20+, 4.x 4.原式= (x+1)(x-1)F(x+1)(x-1)-(x+1)(x-1) 3 x(x-3) x-1 2.x+6-2(x+3)(x-3) y(y一x) 4(m十+3) (3)m3-2(n十3)(m, x2-y2 x2-y2 y m-3 x十y 2(m+3)2(m+3)(m-3) 1 =x-1-x2+1 16.ab=1,bc1 ac 1 x(x一1) a+b3'b+c4'a+c=5’ -x(x-1) 0+=3,+-=4,+-5 x(x-1) =-1; 上述三式相加可得2+2+2=12, 7原式=-义 2x=1; at b c y-x y-xy-x .1++1=6, 8.原式= 2(.x+3) 12 2(x+3)(x-3) 2(x+3)(x-3) (x-1)(x-3)-x2+6x-9 (x-3)2 bcactab-6. 2(x+3)(.x-3)=2(x+3)(x-3)=-2(x+3)(x-3)= abc x-3 abc 一2(x+3) (.x-1)2 1x一11 9,原武(x十)-D十x市一++中中 97 10.原式=“a+2-2-a-2=a-2-a-2=-4.11.(1)原式==5, 10.4习题课(1) 1.原式=5+2≌+2=+ (2)原式=(a+3)(a-3+ζa+3(a-3- (a+3)(a-3)-a-33 2.原式=2”·a5C=24,(3)原式一”·“一器; 3.原式=45a+”,a+2(a-b=a=b4)原式=三2y)x+2y)。x+2=x-2ry (a+1)(a-) 4.原式=“·“aa=1)-=a=1+ 5.原式=“-1÷a^2+a-a∠a+1)(a-1). 12.(1)原式=α-1^个于+=1=x+Dx=D ―a―x+2x-p-x+Dα-p-x=1+ (a-1)(a+2)-a+2;(2)原式一x=1·x+2x-1)-x=x(x+1)- 6.原式=平上≌,三,y=2