内容正文:
课时分层作业(五) 诱导公式与对称
诱导公式与旋转
(建议用时:40分钟)
一、选择题
1.已知sin的值等于( )
,则cos=
A.-
B.
C.-
D.
A [cos.]=-=-sin=sin=sin
2.若sin(θ+π)<0,cos(θ-π)>0,则θ在( )
A.第一象限
B.第二象限
C.第三象限
D.第四象限
B [∵sin(θ+π)=-sin θ<0,∴sin θ>0.
∵cos(θ-π)=cos(π-θ)=-cos θ>0,∴cos θ<0,∴θ为第二象限角.]
3.已知sin的值为( )
,则cos=
A.-
B.
C.
D.-
D [cos.]=-=-sin=cos
4.若sin(π+α)+cos+2sin(2π-α)的值为( )
=-m,则cos
A.-
B.
C.-
D.
C [∵sin(π+α)+cos.=-sin α-sin α=-m,∴sin α=
故cosm.]+2sin(2π-α)=-sin α-2sin α=-3sin α=-
5.已知sin的值为( )
,则sin=
A.
B.-
C.
D.-
D [sin.]=-=-sin=sin=sin
二、填空题
6.cos 660°=________.
.] [cos 660°=cos(360°+300°)=cos 300°=cos(180°+120°)=-cos 120°=-cos(180°-60°)=cos 60°=
7.cos 1°+cos 2°+cos 3°+…+cos 179°+cos 180°=________.
-1 [cos 179°=cos(180°-1°)=-cos 1°,
cos 178°=cos(180°-2°)=-cos 2°,
……
cos 91°=cos(180°-89°)=-cos 89°,
∴原式=(cos 1°+cos 179°)+(cos 2°+cos 178°)+…+(cos 89°+cos 91°)+(cos 90°+cos 180°)
=cos 90°+cos 180°=0+(-1)=-1.]
8.已知f(x)=asin(πx+α)+bcos(πx+β)+2,其中a、b、α、β为常数.若f(2)=1,则f(2020)=________.
1 [∵f(2)=asin(2π+α)+bcos(2π+β)+2=asin α+bcos β+2=1,
∴asin α+bcos β=-1.
f(2 020)=asin(2 020π+α)+bcos(2 020π+β)+2=asin α+bcos β+2=-1+2=1.]
三、解答题
9.已知角α终边经过点P(-4,3),求的值.
[解] ∵角α终边经过点P(-4,3),
∴sin α=,,cos α=-
∴.=-=
10.求证:.
=
[证明] ∵左边==
==右边.===
∴原式成立.
11.若cos(π+α)=-π<α<2π,则sin(2π+α)等于( )
,
A.
B.±
C.
D.-
D [由cos(π+α)=-,,得cos α=
∵.π<α<2π,∴α=
故sin(2π+α)=sin α=sin (α为第四象限角).]=-=-sin
12.(多选)在△ABC中,给出下列四个式子:①sin(A+B)+sin C;②cos(A+B)+cos C;③sin(2A+2B)+sin 2C;④cos(2A+2B)+cos 2C.
其中为常数的是( )
A.①
B.②
C.③
D.④
BC [①sin(A+B)+sin C=2sin C;
②cos(A+B)+cos C=-cos C+cos C=0;
③sin(2A+2B)+sin 2C=sin[2(π-C)]+sin 2C
=-sin 2C+sin 2C=0;
④cos(2A+2B)+cos 2C=cos[2(π-C)]+cos 2C
=cos 2C+cos 2C=2cos 2C.故选BC.]
13.已知cos(75°+α)=,则sin(α-15°)+cos(105°-α)的值是( )
A.
B.
C.-
D.-
D [sin(α-15°)+cos(105°-α)
=sin[(75°+α)-90°]+cos[180°-(75°+α)]
=-sin[90°-(75°+α)]-cos(75°+α)
=-cos(75°+α)-cos(75°+α)
=-2cos(75°+α)=-.]
14.已知f(x)==________.
+f则f
-2 [f,==sin =sin
f-2-2=sin-1=f=f
=-,
∴f=-2.]-=+f
15.化简:(k∈Z).
[解] 当k=2n(n∈Z)时,
原式=
==-1;=
当k=2n+1(n∈Z)时,
原式=
==-1.=
综上,原式=-1.
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