内容正文:
!15"# 17/0(.*(2)
【
!"#$
】
K1I?JH1I
1.(1)(4犪4犫3犮+犪犫)÷犪犫#$%& (D )
A.4犪3犫2 B.4犪3犫2+1
C.4犪3犫2犮 D.4犪3犫2犮+1
(2)!":(6狔
2-2狓狔)÷(-2狔)#$%&
(A )
A.-3狔+狓 B.-3狔+2狓
C.-3狔-2狓 D.-3狔-2狓狔
(3)!":(8狓3-12狓2-4狓)÷(-4狓)= (B )
A.-2狓2+3狓 B.-2狓2+3狓+1
C.-2狓2+3狓-1 D.2狓2+3狓+1
(4)(-15犪3犫2+8犪2犫)÷( )=5犪
2犫-
8
3
犪,
P��QR
(B )
A.3犪犫 B.-3犪犫
C.3犪2犫 D.-3犪2犫
2.ßZ;#+".4犪2-6犪犫+2犪,/µ#6p
ß.2犪,0µ#ìß. (D )
A.4犪-3犫 B.8犪-6犫
C.4犪-3犫+1 D.8犪-6犫+2
3./ñ¶<&í�n�<,¶<&n�ö�<,
0î<.
(D )
A.í�n�< B.v�n�<
C.n�n�< D.z�n�<
4.!":
(1)(6狓2狔-2狓狔
2)÷2狓狔= 3狓-狔 ;
(2)(27犪狓狀+4-6犪2狓2狀+9犪3狓3狀)÷(3犪狓狀)=
9狓4-2犪狓狀+3犪2狓2狀;
(3)(12狓4狔
6-8狓2狔
5-16狓3狔
4)÷(-2狓狔)
2=
3狓
2
狔
4-2狔
3-4狓狔
2.
5.!":
(1)(4犿3-3犿2狀+2犿)÷2犿;
!
:
"#=2犿2-
3
2
犿狀+1;
(2)(15狓3狔
5-10狓4狔
4-20狓3狔
2)÷(5狓3狔
2);
!
:
"#=3狔
3-2狓狔
2-4;
(3)(6犪狀+1-9犪狀+1+3犪狀-1)÷3犪狀-1.
!
:
"#=(-3犪狀+1+3犪狀-1)÷3犪狀-1
=-犪2+1.
【
!"#,
】
DI*?)>.
6.'(H")*#& (A )
A.犿6÷犿2=犿4
B.(-2犪2犫犮)3=8犪6犫3犮3
C.(犿3)4=犿7
D.(2犪3+犪2)÷犪2=3犪3
7.!":
(1)[(2狓+1)(4狓+2)-2]÷(8狓);
!
:
"#=(8狓2+8狓+2-2)÷8狓
=(8狓2+8狓)÷8狓
=狓+1;
(2)[(狓+3狔)
2-(狓-3狔)
2]÷(2狓狔).
!
:
"#=[狓2+9狔
2+6狓狔-(狓
2+9狔
2-6狓狔)]÷(2狓狔)
=12狓狔÷(2狓狔)
=6.
8.¥|},¦=D:[(2犪犫-1)2+
1
3
(6犪犫-3)]
÷(-4犪犫),A?犪=3,犫=-
5
6
.
!
:
"#=(4犪2犫2+1-4犪犫+2犪犫-1)÷(-4犪犫)
=(4犪2犫2-2犪犫)÷(-4犪犫)
=-犪犫+
1
2
,
.犪=3,犫=-
5
6
5
,
"#=-3×(-
5
6
)+
1
2
=3.
·92·
9.�犪,犫&ï9,EF#6�H"V':
犪犫=(犪+犫)
2-(犪-犫)2,0'($T:
①犪犫=犫犪;②/犪犫=0,0犪=0q
犫=0;③/犪犫=(-犪)犫,0犪=0�
犫=0;④犪(犫+犮)=犪犫+犪c.A?)*
#79&
(C )
A.1 B.2 C.3 D.4
10.!":
(1)[2(犪-犫)2+4(犪-犫)4+8犪(犪-犫)3]÷2
(犪-犫)2= 1+6犪
2-8犪犫+2犫2 ;
(2)[(犪+犫)(犪-犫)-(犪-犫)2+2犫(犪-犫)]÷4犫
= 犪-犫 ;
(3)[犪2-2犪犫+犫2-2犪+2犫]÷(犪-犫)= 犪-犫-2 ;
(4)(3狀+3-35×3狀)÷(3×3狀+2)= -8 .
11.V�,vp;犃犅犆犇 Jvp;犆犈犉犌 �&
)Z;
,
q犅,犆,犈nð�§t6É�Ë�,
45犅犇,犇犉,犅犉,�犅犆=6�,△犇犅犉#
+". 18 .
12.ñò��*Vñò#óÇô(i,U&§õ
öñò#�÷êiÈøõö.úùZ N
úÈø.øúõöû5®Z
,
5®Z®�ø
úhYøüÛ.Nú.BC��Èø�0
V�I¦
,
�úùZú`犪=2,犫=4,0Yø
hNú#D
:犿= 40 ,狀= 3 .
13.(1)¥|},¦=D:(4犪犫3-8犪2犫2)÷4犪犫+
(2犪+犫)(2犪-犫),A?犪=2,犫=1.
!
:
"#=犫2-2犪犫+4犪2-犫2=4犪2-2犪犫,
.犪=2,犫=15,
"#=4×22-2×2×1
=16-4
=12.