内容正文:
第7课时 解决问题
圆柱与圆锥
3
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求下面各圆柱的体积。(只列式不计算)
(1)底面半径是3厘米,高是5厘米。
(2)底面直径是8米,高是10米。
(3)底面周长是25.12分米,高是2分米。
3.14×3²×5
3.14×(8÷2)²×10
3.14×(25.12÷3.14÷2)²×2
一
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一个内直径是8cm的瓶子里,水的高度是7cm,把瓶盖拧紧倒置放平,无水部分是圆柱形,高度是18cm。这个瓶子的容积是多少?
7cm
18cm
二
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这个瓶子不是一个完整的圆柱,无法直接计算容积。
阅读与理解
能不能转化成圆柱呢?
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瓶子里的水倒置后,水的体积没变。
18cm
水的体积加上18cm高圆柱的体积就
是瓶子的容积。
分析与解答
二
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也就是把瓶子的容积转化成了两个圆柱的体积。
7cm
18cm
答:这个瓶子的容积是1256mL。
瓶子的容积:3.14×(8÷2)2×7+3.14×(8÷2)2×18
=3.14×16×(7+18)
=3.14×16×25
=1256 (cm³ )
=1256(mL)
二
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你还能想到别的方法吗?
7cm
18cm
想一想
二
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7cm
18cm
1
2
图1中的空气与图2中的空气体积相等,把图2中的空气换到图1上,如下图,就能形成一个规则的圆柱。
二
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