内容正文:
一、选择题(每小题 3 分,共 30 分)
题 号 1 2 3 4 5 6 7 8 9 10
选 项 B A D C B D C A A D
二、填空题(每小题 3 分,共 15 分)
11. -2 12. 云冈石窟 13. 16-4π %%%%%14. 3n+1 15. -2
三、解答题(本大题共 8 个小题,共 75 分)
16. 解:(1)原式=2×(-27)-(-12)+17 %%% %%%%%%%%%%%%%%%%%% 2 分
%%=-54+12+17 %%%% %%%%%%%%%%%%%%%%%%%%%% 4 分
%%=-25. %%%%%%%%%%%%%%%%%%%%%%%% 5 分
(2)原式=-8- 1
6
×5- 1
6
×(-9) %%%%%%%%%%%%%%%%%%% 6 分
%%%=-8- 1
6
×(5-9) % %%%%%%%%%%%%%%%%%%%%% 7 分
%%%=-8- 1
6
×(-4) %% %%%%%%%%%%%%%%%%%%%%%% 8 分
%%%=-8+ 2
3
% %%%%%%%%%%%%%%%%%%%%%%%%% 9 分
%%%=- 22
3
. %%%%%%%%%%%%%%%%%%%%%%% 10 分
17. 解:(1)第五个等式:112-4×52=21. % %%%%%%%%%%%%%%%%% 3 分
(2)第 n 个等式:(2n+1)2-4n2=4n+1. %%%%%%%%%%%%%%%% 7 分
18. 解:整数集合: -12,(-6)2,0,- 217
,, ,… ; %%%%%%%%%%%%%% 2 分
分数集合: -3.5,5.4,- - 355113 ,, ,… ; %%%%%%%%%%%%%%%% 4 分
正有理数集合:,5.4,(-6)2,…,; %%%%%%%%%%%%%%%%%% 6 分
负有理数集合: -3.5,-12,- - 355113 ,-
21
7
,, ,… . %%%%%%%%% 8 分
19. 解:(1)这个长方体包装盒的体积为:a2h cm3. %%%%%%%%%%%% 2 分
(2)(a-b)+c2. %%%%%%%%%%%%%%%%%%%%%%%%%% 4 分
(3)船逆水行驶的速度为:(v-2.5)km/h. %%%%%%%%%%%%%% 6 分
(4)张叔叔的身体质量指数为: w
h2
. %%%%%%%%%%%%%%%% 8 分
20. 解:根据题意,得
25+(-0.10×2)+(-0.15)×2+0×3+0.10×3
10 %%%%%%%%%%%%%%
3 分
=25+ -0.2-0.30+0.30
10 %%%%%%%%%%%%%%%%%%%%%%
6 分
=25-0.02 %%%%%%%%%%%%%%%%%%%%%%%%%%%% 7 分
=24.98(kg). % %%%%%%%%%%%%%%%%%%%%%%%%%%% 8 分
答:这十袋面粉的平均质量是 24.98 kg. %%%%%%%%%%%%%% 9 分
21. 解:(1)2100. %%%%%%%%%%%%%%%%%%%%%%%%%% 3 分
(2)(60x+30y)元. %%%%%%%%%%%%%%%%%%%%%%% 6 分
(3)当教师有 a 人时,那么学生有 6a 人. %%%%%%%%%%%%%% 7 分
买单程火车票共需
60a+30×6a=60a+180a(元). %%%%%%%%%%%%%%%%%%%% 8 分
当学生有 b 人时,那么教师有1
6
b 人. %%%%%%%%%%%%%%%% 9 分
买单程火车票共需
60× 1
6
b+30b=10b+30b(元). %%%%%%%%%%%%%%%%%%% 10 分
22. 解:(1)第一种摆放方式:只有一张桌子时能坐 6 人,后边每多一张桌子多坐 4 人.
即有 n 张桌子时,能坐顾客(4n+2)人. %%%%%%%%%%%%%%%% 3 分
第二种摆放方式:只有一张桌子时能坐 6 人,后边每多一张桌子多坐 2 人,
即有 n 张桌子时,能坐顾客(2n+4)人. %%%%%%%%%%%%%%%% 6 分
(2)打算用第一种摆放方式来摆放餐桌. %%%%%%%%%%%%%%% 7 分
理由:当 n=8 时,
第一种摆放方式:4×8+2=34>30; %%%%%%%%%%%%%%%%%% 8 分
第二种摆放方式:2×8+4=20<30; %%%%%%%%%%%%%%%%%% 9 分
所以,选用第一种摆放方式. %%%%%%%%%%%%%%%%%%% 10 分
23. 解:(1)点 A 和点 B 之间的距离是 3; %%%%%%%%%%%%%%%% 1 分
点 A 和点 C 之间的距离是 7;