内容正文:
— —162 R
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y≤11212,∵y8FG,
∴y
X[Z
=112.
)
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112
÷
.
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1.C 2.B 3.A 4.B 5.45°
9
135° 6.AC=DB 7.4
8.
æÚ
:∵AD=BC,
∴AC=BD.
^△ACE4△BDFK,
AC=BD,
AE=BF,
CE=DF
{
,
∴△ACE≌△BDF(SSS).
∴∠A=∠B.∴AE∥BF.
9.
æÚ
:∵∠ABC+∠3=180°,
∠ABD+∠4=180°,
°∠3=∠4,
∴∠ABD=∠ABC.
^△ADB4△ACBK,
∠2=∠1,
AB=AB,
∠ABD=∠ABC
{
,
∴△ADB≌△ACB(ASA).∴BC=BD.
10.
æÚ
:
¥!Ý
,
(
AB=AC,
∵BD,CE
'23/+t.Kc
,
∴AD=12AC,AE=
1
2AB,∴AD=AE.
^△ABD4△ACEK,
AB=AC,
∠A=∠A,
AD=AE
{
,
∴△ABD≌△ACE(SAS).∴BD=CE.
11.(1)
æÚ
:∵CE⊥CD,
∴∠DCE=90°.
∴∠ACB=90°,
∴∠BCD=90°-∠ACD=∠FCE.
^△BCD4△FCEK,
CB=CF,
∠BCD=∠FCE,
CD=CE
{
,
∴△BCD≌△FCE(SAS).
(2)́ :
¥
(1)
Å;
,△BCD≌△FCE,
∴∠BDC=∠E.
∴EF∥CD,
∴∠E=180°-∠DCE=90°.
∴∠BDC=90°.
12.(1)
æÚ
:∵∠1=∠C+∠CBE,∠ABC=∠2+
∠CBE,∠1=∠ABC,
∴∠2=∠C.
(2)́ :∵AF
m'∠BAE,
∴∠BAF=∠DAF.
∴FD∥BC,∴∠ADF=∠C=∠2.
^△ABF4△ADFK,
∠2=∠ADF,
∠BAF=∠DAF,
AF=AF
{
,
∴△ABF≌△ADF(AAS).
∴AD=AB=5.∴DC=AC-AD=8-5=3.
13.(1)́ :∵∠ABC=60°,
∴∠BAC+∠ACB=180°-60°=120°.
∴AD,CE
'2m'∠BAC4∠ACB,
∴∠OAC=12∠BAC,∠OCA=
1
2∠ACB,
∴∠OAC+∠OCA=12(∠BAC+∠ACB)
=12×120°
=60°.
^△AOCK,∠AOC=180°-(∠OAC+∠OCA)=
180°-60°=120°.
(2)
æÚ
:
\]
,̂ AC
t|M
AF=AE,
{S
OF.
∴AD
m'∠BAC,
∴∠BAD=∠CAD.
^△AOE4△AOFK,
AE=AF,
∠EAO=∠FAO,
AO=AO
{
,
∴△AOE≌△AOF(SAS).∴∠AOE=∠AOF.
∵∠AOC=120°,∴∠AOE=180°-120°=60°.
∴∠AOF=∠AOE=60°.
∴∠COF=∠AOC-∠AOF=120°-60°=60°.
∴∠COD=∠AOE=60°,
∴∠COD=∠COF.
∴CE
m'∠ACB,∴∠ACE=∠BCE.
^△COD4△COFK,
∠DCO=∠FCO,
CO=CO,
∠COD=∠COF
{
,
∴△COD≌△COF(ASA).∴CD=CF.
∴AC=AF+CF,∴AC=AE+CD.
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R— —163
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11.́ :(1)
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(2)
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(3)A1(2,3),A2(-2,-1).
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\]ab
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A′(5,-1),B′(5,-4),C′(2,-5);
(2)
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1.C 2.D 3.A 4.A 5.D 6.45° 7.4 8.24°
9.3
9
25
3 10.4
11.
æÚ
:∵AB=AC,
∴∠ABC=∠C.
¿
∵AD
3
BC
0t.Kc
,
∴AD⊥BC,∴∠ADB=90°,
∴∠BAD+∠ABC=