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八年级数学答案 第 1 页(共 3 页)
2018—2019 学年第二学期教学质量检测
八年级数学参考答案及评分意见
一、选择题(每小题 3 分,共 30 分)
1.B 2.B 3.B 4.A 5.D 6.C. 7.A 8.A 9.D 10.C
二、填空题(每小题 3 分,共 15 分)
11.166 cm 12.1 13.2 14.12 15. 17 cm 或 2 2 cm
三、解答题(本大题 8 小题,共 75 分)
16.(1)解:原式=
2 2
5 3 . ······································································ 2 分
=5-3 ··············································································· 3 分
=2. ················································································· 4 分
(2)解:原式=
1
2 2 2 6 2 3 4 2
2
················································· 2 分
= 4 2 3 2 12 2 ····························································· 3 分
=13 2 . ·········································································· 4 分
17.证明:如图连接 AC 交 EF 于点 O, ··························································· 1 分
∵ 四边形 ABCD 是平行四边形,
∴ AO=CO, BO=DO. ········································································· 3 分
又 BE = DF,
∴ BO+BE=DO+DF.
∴ EO=FO. ······················································································· 7 分
∴ 四边形 AECF 是平行四边形. ····························································· 8 分
18.解:(1)将公司 25 名员工月收入数据由小到大排列,处于中间位置的数据为 3000,因
此公司员工月收入中位数为 3000; ··························································· 3 分
(2)用所求平均数反映公司全体员工月收入水平不合适;
这个公司员工月收入平均数为 6080 元,但在 25 名员工中,仅有 3 名员工的收入在平均
数以上,而另有 22 名员工收入在平均数以下,因此,用平均数反映所有员工的月收入
不合适,利用中位数更好. ····································································· 8 分
19.解:(1)令 y=0 代入解析式可得:x=4,
O B
D
CF
EA
八年级数学答案 第 2 页(共 3 页)
所以 A(4,0). ··················································································· 2 分
令 x=0 代入解析式可得:y=3.
所以 B(0,3). ··················································································· 4 分
(2)由勾股定理,得 BA= 543 22 . ············································ 5 分