内容正文:
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1.
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A.16 B.24 C.8 D.4
2.
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2x2-槡5x-3=0*-., ( )
A.x=槡5±槡112 B.x=
槡5±槡29
4
C.x=-槡5±槡292 D.x=
-槡5±槡29
4
3.
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2x2-5x+3=0
*.*/0,
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A.
1-234*56.
B.
1-2734*56.
C.
856.
D.
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4.
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1
2 <a<1
C.1<a< 32 D.
3
2 <a<2
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b,c
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2-槡3x+1=0.
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4.D; 5.B; 6.D.
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8.
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AC=
BD; 9.5013; 10.13;
11.2.4;
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ABCD
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6 7
BC = DC,∠BCP =
∠DCP=45°.,-PC=PC,
67 △PBC≌ △PDC.67
∠PBC=∠PDC.,- PB=
PE,
67∠PBE=∠PEB.6
7 ∠PEB = ∠PDC.6 7
∠PEB+∠PEC=∠PDC+
∠PEC=180°.67∠DPE=
180°-90°=90°.
67
PE⊥
PD.
14.
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15.
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ABCD
-
9"
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67
AC⊥ BD,OA=
OC,OB=OD.
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AC=8,
BD=6,
67
OA=4,OD=3.
67
AD=5.
,-
DE⊥BD,
67
DE∥OA.,-O-BD:
;
,
67
A
-
BE
:;
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67
DE
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67
△ADE<=> =8+5+5=
18.
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ABCD
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67
AB∥CD.
67 ∠OAE =∠OCF,
∠OEA=∠OFC.
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AE=CF,
67△AEO
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OF.
(2)60°.
17.(1)
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ABCD
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67
BA=BC=CD
=BE=CE,∠ABC=∠BCD
=90°,∠EBC = ∠ECB =
60°.
67 ∠ABE=∠ECD=
30°.
A △ABEB △DCE:,
AB=DC
∠ABE=∠DCE,{
BE=CE
6 7
△ABE≌△DCE(SAS).
(2)∠AED=150°.
&
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*+
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O
0
AC
:;
,
67
AO=OC.
,-
OE=OD,
67./"
ADCE
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AD
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,
67∠ADC=90°.67.
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ADCE
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(2)
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AD
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△ABCF/BCG<H,BC=
16,AB=17,
67
BD=CD=
8,
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6
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AD
×DC=15×8=120.
19.(1)
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BC,AB
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DE∥AC,AC=2DE.,-
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