福建省厦门第二中学2026-2027学年第一学期高三11月期中考数学试卷

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厦门二中2026-2027学年第一学期高三年段11月期中考 数学 学科试卷

本试卷共4页,满分150分,考试时间120分钟。

班级:____________座号:___________姓名:__________

一、单选题:本题共8小题,每小题5分,共40分.在每小题给出的四个选项中,只有一项是符合题目要求的.

1.若集合eqId4a6cf2d9ee943dd7868e8b70cd12cded,eqId387d901a914a7479d40f7b8420d04fd1,则eqId1336d38741aab2255a35c26612bbd7cc                                      (  )

A.eqId9a837165ca03f9e4ea8964979c95e3bb B.eqId007dc6716142aac90e47d90d26f23402 C.eqId3b92392b0ab8b10ff2ab318644425a8b D.eqIdfed3b031adee59eb93193c3941eebffd

2.设eqId2fc8e8ba454743f3949f1cb1b88ba55d,eqId7e544864c2711e8cb7cfc899ebddb3c9,eqId675509cf2021c8206ee0fa5f6aa57cdf,则a,b,c的大小关系为                                 (  )

A.eqId8b73abfe4bc26b1ded680d7abb1a2cac B.eqId131bbb874be8760c7347004fd276e514 C.eqIdb1a6057ebfd4a316d82d5cd0bb9b09c0 D.eqId3c64d5fc60309e1920b076171a9df469

3.空间四边形eqId3241d7fedd89d85711acd7a2635298af中,eqId14390e9b6b44472bdc7a131133ab39b1,eqId87cd14dfc0024459f9d8e594c95c5106,eqIde07dcf0b16163e0e0e0c0f248466ee7e,点eqIdac047e91852b91af639feec23a9598b2在线段eqIdef4113c492885ba7c47fe42ac792578f上,且eqIdebe72d1b634f1e89d8699e605e7d46af,点eqId54a5d7d3b6b63fe5c24c3907b7a8eaa3为eqId0dc5c9827dfd0be5a9c85962d6ccbfb1的中点,

则eqId8926ddd0b69d714c7310cc5bf23d199d                                                                                    (  )  

A.eqId429b31f2db737924ec878e0871a2e6d5   B.eqId8c53a24f4af1fb649221bf3fb94bba18        C.eqId497cd6de340d019092e758ef04d29fc0       D.eqId47d38cd216eb36afc1481a695a9bae2d

4.曲线eqId951f1decb2f552ae386ed78e753001a7在点eqId4848a0f1326eef03a92ec09a9a75c6ae处的切线方程为                                             (  )

A.eqIdf129d441ab39d195cb2580c46065d0fb B.eqIdfcfc6b5b7ae63a330f0cd8593ee47338 C.eqId260d9a9e5329ad68090d2f442c635bcc D.eqIdd2297db3c14c256b9691fbb8e5bba978

5.角eqIde170f206fdbbd834aad7580c727e2cc6以eqIdc3e5af20b2f8c1fba4470f9650989e51为始边,它的终边与单位圆eqId1dde8112e8eb968fd042418dd632759e相交于点eqIddad2a36927223bd70f426ba06aea4b45,且点eqIddad2a36927223bd70f426ba06aea4b45的纵坐标为eqId4dac452fbb5ef6dd653e7fbbef639484,则eqId8553cd25d8ee28d714109d82d857e5f6的值为 (  )

A.eqIdf328c4df1fb60727c7c29bd6d3a92561 B.eqId0f97421e30101db5633d27a48482abc2 C.eqId8a4e6eb3663870ed202cc208eaf239dc D.eqIde8aa9d34edce01c84460ccf875b0f2a4

6.在无人机集群搜救中,目标区域的未覆盖面积eqIdcf231f8f86fb922df4ca0c87f044cec3(单位:eqId39d196b1e01a617b513e62fb710c8e87)与搜索时间eqId36a1b09c653185842513e24ebba60bb3(单位:eqId1933311c0c090e1138e4dd388b7adf8a)满足关系式eqId80f54de48cfde0fd2538d4d09e47c8f7,其中eqId54f562eb3c2a45d65cba066d712825a5为目标区域总面积,eqIdf0a532e15e232cb4b99a8d4d07c89575为常数.某次演练中,搜索eqId1b29f60fc3d32ca94740f0adf3fd0b53和eqIdc176558537cd011dec12c14ae91bd71b后的未覆盖面积分别为eqId8883e73e51212d5ad09d44b903617ec2和eqId9d13b6403b766d039adc8a2c4276585f.下表给出了不同地形条件下,演练目标区域总面积指标eqIdf00cdeec036e73d514b6ef772902b820的参考范围,则此次演练的地形属于                       (  )

地形复杂程度

高山峡谷

复杂山地

浅丘林地

平原水面

评判指标eqIdf00cdeec036e73d514b6ef772902b820

eqIdf0263ef44a71252277efc494b4641a1c

eqIdd23ff14a119c4290ec9eaf297317fe33

eqId1ea3c80cfbde34bf082aa217353aa4c1

eqIdd0187cd146d22cfa607672deaccfc363

参考数据:eqIdef98775e12ea3852135792e34526a519,eqId295fbcedb830aa9acb83aef417f07202.

A.高山峡谷 B.复杂山地 C.浅丘林地 D.平原水面

7.已知函数eqId03831c15cf1ebc9a4e671075b3bf2af5在eqId6a3f0956cea633f6d1c79ed3f838ee75上恰有两个零点,则eqId074c228ffc7b1e306f8410afe7bc4b5c的取值范围是               (  )

A.eqIdb150ce4d14ccb2a332dae05a138a2f50 B.eqId7103a282653031495095934166f6a14c C.eqId1977266993dc2c5dfbbd7df5c280e488 D.eqId96aa65a075e390894f8dca8f5478301d

8.设函数eqId5d327b9b7d70a9ab9e2c8a3210f35630,若eqId58196b9e63ec00aa1119052b6de6ae12恒成立,且eqIdd19bce4c604450307f40dcbd6a9ca6c9,则eqId9b37588b10a67d4739fd02bb043de8d4的最大值为                  (  )

A.eqId5e6486784415f3537c9a13556c05d893 B.eqIdbdaa19de263700a15fcf213d64a8cd57 C.eqId61128ab996360a038e6e64d82fcba004 D.eqId041a7c8fc017f596542c5e6ec7d1c40b

二、多选题:本题共3小题,每小题6分,共18分.在每小题给出的四个选项中,有多个选项符合题目要求,全部选对的得6分,部分选对得部分分,有选错的得0分.

9.若向量eqId64c5562bd4d1b54424330cb6329cd79d,eqIdb45ba716f03748c19b7ce2f99af536ab满足eqId498634e4ed9d425d5e619aa45d4b5366,eqIdc81ec2ce190ee800eb155673bab8d933,则                                                  (  )

A.eqIdc8c719ce746a77ce16aebd741e9b1383 B.eqId64c5562bd4d1b54424330cb6329cd79d与eqIdb45ba716f03748c19b7ce2f99af536ab的夹角为eqId037fb348109dc2063a268b10eb925a57

C.eqId3143307ad0ba4a631eac04e814993655在eqIdb45ba716f03748c19b7ce2f99af536ab上的投影向量为eqId51b6e92ee0b4a379a3521a0a4b94d861 D.eqId1a603069cf81f5ff7a40bc24e1be8be7

@@@b271d6e5-cf84-446a-b962-5971900ca6b210.已知函数eqId3929eb6a5a9bbe6e4ad7822ae61a294b的部分图象如图所示,则                       (  )

A.eqId8ce0dc28340738e090bd10d6d675d8ce       

B.函数eqIdd275fbb3ee5cd1177ca5a2ceecbbef0f在区间eqId7e1dd4c033b47bef89ae7232b94f5bf6上不单调

C.若eqId9366016d6603b2e02b650bd84e7f2984,则函数eqIdd275fbb3ee5cd1177ca5a2ceecbbef0f的值域是eqId239e37468595e7ecf95e21121a178637

D.eqId52e8eeec863770a4534a3f711148fee0图象可以由eqId0afb80007983e5b99dcdeebf87d18ff4图象向右平移eqId4d7ea65be0351e839d45d598dfb254b0个单位长度得到

@@@10e93d87-7004-4757-9d57-a3813369181011.正方体eqId6e09725691ee7851f54c0dee86b2bf55的棱长为eqId61128ab996360a038e6e64d82fcba004,eqId2a30f3a8b673cc28bd90c50cf1a35281,eqIda0ed1ec316bc54c37c4286c208f55667分别是eqId03902478df1a55bc99703210bccab910,eqId22adbc0da438220f9cace11b629d799b的中点,点eqIddad2a36927223bd70f426ba06aea4b45是底面eqId411b38a18046fea8e9fab1f9f9b80a5f内(含边界)一动点,则下列结论正确的为                                                                          (  )

    A.存在唯一的点eqIddad2a36927223bd70f426ba06aea4b45,使得eqIdeb3a99c3ef79e88a8ecbd6824fc7ae7f平面eqId679748eab882a6be0fefd2cc300349a4

B.过eqId7f9e8449aad35c5d840a3395ea86df6d,eqId2a30f3a8b673cc28bd90c50cf1a35281,eqIda0ed1ec316bc54c37c4286c208f55667三点的平面截正方体所得截面面积是eqId1c0874f019492261eb175bdcc08c189d

C.动点eqIddad2a36927223bd70f426ba06aea4b45到平面eqId87c0bfeadcf17b2a45896071f07a4a5a的距离的最大值为eqIdcf298f00799cbf34b4db26f5f63af92f

D.若直线eqIdb5c2293f93791a597bf0162411f3395f与平面eqId411b38a18046fea8e9fab1f9f9b80a5f所成角的正切值为eqId802e162b98c280720fcb909cf392fda3,则动点eqIddad2a36927223bd70f426ba06aea4b45的轨迹长度为eqIdfb18313a4e85155d2be9756e82853bf5

三、填空题:本题共3小题,每小题5分,共15分.

12.圆台的上底面半径长为2,下底面半径长为3,侧面展开图的面积等于eqIda8f64f3cf180549ad1f006994864399d,则圆台的体积为________.

13.已知函数eqIdbc2ef22a37c9286cc8f9e2780f34390a,则不等式eqIdbb0df7574169f99c7033f65e3a20e5c0的解集为__________.

14.已知eqId16192034243798a7adcc62f592431e1b,则eqId6369cd1db768436809404b1f3c4132c0的最小值为________.

四、解答题:共77分.解答应写出文字说明、证明过程或演算步骤.

15.(13分)

等差数列eqId83cf38189d5cbf627d2b82ac0eb76006的前eqIdb6a24198bd04c29321ae5dc5a28fe421项和为eqId08eb71ecf8d733b6932f4680874dbbf3,且eqIdf2fcd86b9ed6819116a261629f96fae1,eqId3e84584c6bb2d410db3da6d6e5c55896,数列eqId034ba25825c13725931c483aa47c9363满足eqId5b72ddd7de598464a37b10f03f67b904,eqIdf6b63bd128c2008f3ca992494e9e9ec7.

(1)求数列eqId83cf38189d5cbf627d2b82ac0eb76006的通项公式;

(2)证明:数列eqId23787abf446a4a81bf3c279defad2ec1是等比数列;

(3)求数列eqId83cf38189d5cbf627d2b82ac0eb76006的前eqIde2d51f9147b8265c0276c1f2c2659197项和eqIdfbd85b79372dc6e596d465f738c3c300.page number 0

 

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