内容正文:
专题7 程序的一般流程和嵌套
浙江省单独招生 计算机类 《计算机语言基础》
考纲讲练测
编写说明:本专辑为浙江省(单独招生)计算机类《计算机语言基础考纲讲练测》,严格依据浙江省普通高校单独招生考试大纲(专业课)计算机类考试范围及要求编写,精准对标考纲,兼顾考点覆盖与实战应用。每套讲练测提供讲义、课件、练习三大配套教学文件,贯穿九大核心环节:考点解读、思维导图、知识梳理、背诵环节、常考题、高考真题、课堂练习、课堂小结及课后测验,形成“讲-练-测-评”闭环式教学与复习逻辑,助力考生夯实基础、突破重难点。
311066
考点解读
1.了解程序的一般流程
2掌握流程嵌套
思维导图
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知识梳理
(1)顺序流程
从上到下,一行接一行依次执行,没有跳转、没有判断。
特点:代码写在哪行,就按行运行
例子:
print("第一步")
print("第二步")
print("第三步")
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知识梳理
(2)选择流程
三种写法:
①单分支(if)
if条件:
满足才执行
②双分支(if…else)
if 条件:
满足执行else:
不满足执行
③多分支(if…elif…else)
if 条件1:
执行1elif 条件2:
执行2else
都不满足执行
特点:只会走一条路,不会同时执行多个分支
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知识梳理
(3)循环流程:
满足条件就反复执行一段代码,直到条件不成立。
两种循环:
①for 循环固定次数、遍历列表 / 字符串
for i in range(5):
重复执行
②while 循环按条件循环,次数不确定
while 条件:
满足就重复
循环控制:
break:立刻结束整个循环
continue:跳过本次,继续下一次循环
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知识梳理
嵌套结构
嵌套结构等于一个流程里面“套”另一个流程,就是大流程包小流程,Python 最常用的是:选择嵌套、循环嵌套、循环里套选择。
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知识梳理
(1)选择结构嵌套
在一个 if/else 里面再写一个 if 判断。
age = 25
if age >= 18:
if age <= 30:
print("青年")
else:
print("壮年")
else:
print("未成年")
三大嵌套类型
(2)循环嵌套(for/while 套循环)
外层循环转一圈,内层循环跑全套。
# 打印 2 行 3 列星星
for i in range(2):
# 外层:控制行数
for j in range(3):
# 内层:控制列数
print("*", end="")
print()
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知识梳理
(3)循环里套选择(最实用)
循环遍历,每一项都做判断。
heights = [1.8,1.15,1.62,1.1]
n = 0
for h in heights: # 循环套判断
if h <= 1.2:
n = n + 1print("符合条件人数:", n)
这是枚举算法的标准写法。
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知识梳理
s = "Hello Python Python"
# 1. len() 求长度
print("长度:", len(s))
# 2. find() 查找
print("查找Python位置:", s.find("Python"))
# 3. replace() 替换
new_s = s.replace("Python", "Java")
print("替换后:", new_s)
# 4. upper() 转大写
print("转大写:", s.upper())
# 5. lower() 转小写
print("转小写:", s.lower())
# 6. count() 统计次数
print("Python出现次数:", s.count("Python"))
# 7. split() 分割
print("按空格分割:", s.split(" "))
# 8. join() 连接
函数用法
背诵环节
1.枚举算法的标准写法。
【答案】
for 变量 in 所有可能范围:
筛选符合要求的 if 满足条件:
处理结果 result = result + 1# 计数 / 累加 / 记录
输出结果 print(result)
背诵环节
2.简述顺序流程特点。
【答案】从上到下,一行接一行依次执行,没有跳转、没有判断。
特点:代码写在哪行,就按行运行
3.简述嵌套结构的概念。
【答案】嵌套结构等于一个流程里面“套”另一个流程,就是大流程包小流程,Python 最常用的是:选择嵌套、循环嵌套、循环里套选择。
U2FsdGVkX18nW9FGSj7OCgRdj+mqFJSpNYcs+cIxU+5vj9S/VlldliL8ypIE4YbxWTqf5U9dpAN5bKoDpptO/JyZO5/wz8pniArRjroHSGlL0vnhD1g1134KzJCBpw+MTR0VIU9fqz7AUH7WGhr1ThPqRc88TJEUQ6h0upDkjhjcxMeCyXDTEBtd1bHJ6mpfnDXLZmIUPsK6uZtO5RUOimIkrSJtDB8nSv88CBuEAZpz4sFmJ+8Zy86B2V5IKUTvJ8IKe+O4JKDGWJDbRs6ye2WbPaUNTin/kfF06AX6MgVLMUTf/pI1pFVSXedEcklmlAOQTMcrpcjET4G8QuZkVxuu7bnlUot1c13T2TWAB73GEDov5iq9/PRMWWSNWY/n1hW6hjx2uX818buykvhWERNSt动力 传动 执行KYaMDEwkv+47aL52rDTkKQXQ05gPwK3xo5pysBsWR42xnMT1TQr4cHOYd6DTpKUfbsG3ggROJtvFPKb4DpobgNeLSwn5UwmK/sRS2pYs02jB2Ow9tN62A8RaG+QkTEy8NiFcuGxe9xLHSGByIysdIrrMN+G5f5jlFeH61vI/xT8s1URsdd+sCrZPIl5F9ntdIjiBt8kaMBPHJQgyu2Y+x2llrXgricQwlNErlvxJYP0IRxGJkABVox939xc8THnmsFChUzCN/YkjwDx0drGiJoNgyIl8WR1BQc+P3IFnOlMPwc4vibN+AUV4P/Urw==
常考题
1.以下关于顺序流程说法正确的是( )
A.可以跳转执行代码
B.从上到下逐行依次执行,无判断、无跳转
C.满足条件才会执行
D.可以重复执行代码
【答案】B
【答案】A
2.对于 if…else if…else 多分支选择结构,下列说法正确的是( )
A.只会执行其中一个匹配的分支 B.满足多个条件时,所有分支都会执行
C.必须所有条件都满足才执行’ D.至少执行两个分支
单选题
U2FsdGVkX18nW9FGSj7OCgRdj+mqFJSpNYcs+cIxU+5vj9S/VlldliL8ypIE4YbxWTqf5U9dpAN5bKoDpptO/JyZO5/wz8pniArRjroHSGlL0vnhD1g1134KzJCBpw+MTR0VIU9fqz7AUH7WGhr1ThPqRc88TJEUQ6h0upDkjhjcxMeCyXDTEBtd1bHJ6mpfnDXLZmIUPsK6uZtO5RUOimIkrSJtDB8nSv88CBuEAZpz4sFmJ+8Zy86B2V5IKUTvJ8IKe+O4JKDGWJDbRs6ye2WbPaUNTin/kfF06AX6MgVLMUTf/pI1pFVSXedEcklmlAOQTMcrpcjET4G8QuZkVxuu7bnlUot1c13T2TWAB73GEDov5iq9/PRMWWSNWY/n1hW6hjx2uX818buykvhWERNSt动力 传动 执行KYaMDEwkv+47aL52rDTkKQXQ05gPwK3xo5pysBsWR42xnMT1TQr4cHOYd6DTpKUfbsG3ggROJtvFPKb4DpobgNeLSwn5UwmK/sRS2pYs02jB2Ow9tN62A8RaG+QkTEy8NiFcuGxe9xLHSGByIysdIrrMN+G5f5jlFeH61vI/xT8s1URsdd+sCrZPIl5F9ntdIjiBt8kaMBPHJQgyu2Y+x2llrXgricQwlNErlvxJYP0IRxGJkABVox939xc8THnmsFChUzCN/YkjwDx0drGiJoNgyIl8WR1BQc+P3IFnOlMPwc4vibN+AUV4P/Urw==
【答案】D
3.想要固定循环次数、遍历字符串或列表,适合使用哪种循环( )
A.if循环 B.while循环
C.elif循环 D.for循环
单选题
4.下列关于 break 和 continue 描述正确的是( )
A.break 只跳过本次循环,继续下一次
B.continue 直接终止整个循环
C.break 立刻结束整个循环,continue 跳过本次进入下一次
D.两者作用完全一样
【答案】C
常考题
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
常考题
5.关于流程嵌套的核心规则,说法正确的是( )
A.内层执行一次,外层完整跑一遍 B.外层执行一次,内层完整跑完一整轮
C.外层和内层同时执行 D.嵌套不能循环套选择
【答案】B
6.顺序流程代码可以打乱行号跳跃执行( )
【答案】×
7.if…elif…else 多分支结构,有可能同时执行两个分支( )
【答案】×
单选题
判断题
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
常考题
8.while 循环适合不确定循环次数,按条件重复执行的场景。( )
【答案】√
9.continue 语句的作用是直接终止整个循环( )
【答案】×
10.嵌套结构的规律是:外层执行一次,内层完整运行一遍。( )
【答案】√
判断题
高考真题
单项选择题
有如下代码请你根据代码完成1-5选择题
count = 0
for i in range(3):
for j in range(2):
if i + j >= 3:
count += 1
print(count)
高考真题
单项选择题
1.这段代码用到的结构是( )
A.顺序结构 B.循环嵌套 + 选择结构嵌套
C.仅单分支 if D.仅 while 循环
【答案】D
2.外层循环 for i in range(3) 一共执行( )次
A.2
B.6
C.4
D.3
【答案】B
高考真题
单项选择题
3.内层循环 for j in range(2) 每轮外层循环要执行( )次
A.1 B.2 C.3 D.4\
4.代码中 if i + j >= 3 总共满足条件有( )次
A.1 B.2 C.3 D.4
5.程序最终打印输出的 count 值( )
A.0 B.2 C.1 D.3
【答案】B
【答案】A
【答案】C
高考真题
单选题、判断题
6.选择结构嵌套时,内层 if 可以不缩进,和外层写同一行也能正常运行。( )
【答案】×
7.循环里套 if 属于嵌套结构,每循环一轮都会重新进行条件判断。( )
【答案】√
8.多分支 if…elif…else 中,else 只能放在所有 elif 最后面。( )
【答案】√
课堂练习
单项选择题
有如下代码请你根据代码完成1-5选择题
res = 0
for x in range(2):
for y in range(4):
if y % 2 == 0:
res += y
print(res)
课堂练习
单项选择题
1.该代码包含的结构的是( )
A.仅顺序结构 B.循环嵌套 + 循环内套 if 选择
C.只有 if 嵌套 D.只有 while 循环
【答案】B
2.外层循环 range(2) 总共循环次数是( )
A. 2 B.1
C. 3 D.4
【答案】A
课堂练习
单项选择题
3.内层循环 range(4) 每次外层循环要执行几次( )
A.2 B.3 C.4 D.6
【答案】C
4.条件 y % 2 == 0 含义是( )
A.y 是奇数 B.y 是偶数
C.y 能除以 3 D.y 小于 2
【答案】B
5.程序最终输出 res 的值为( )
A.4 B.6 C.8 D.10
【答案】A
课堂练习
单项选择题
5.程序最终输出 res 的值为( )
A.4 B.6 C.8 D.10
有以下代码,请你根据代码完成6-10题
num = 0
i = 1
while i <= 3:
j = 1
while j <= i:
num += 1
j += 1 ;i += 1
print(num)
课堂练习
单项选择题
【答案】B
6.这段代码使用的嵌套类型是( )
A.if套if B.while循环嵌套
C.for嵌套 if D.顺序嵌套
7.外层 while 循环一共执行几次( )
A.2 B.5 C.4 D.3
【答案】D
8.当 i=3 时,内层 while 循环执行( )次
A.1 B.2 C.3 D.4
【答案】C
课堂练习
单项选择题
【答案】B
9.内层循环 j <= i 说法正确的是( )
A.j固定循环3次 B.内层循环次数随i变大而变多
C.j永远等于i D.是死循环
10.程序最后打印 num 的结果是( )
A.6 B.5 C.3 D.9
【答案】A
课堂小结
一、一般流程
1.顺序流程
2.选择流程
3.循环流程
二、嵌套结构
1.嵌套特点
2.嵌套用法
感谢观看
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