内容正文:
练习13
整式的除法
同行学案学练测
计算高手
(难度等级:★★)
七年级数学下BS
基础通关
(5)(3a2b)°.(-9ab)-(-2ab)
1.计算.
(1)-12a3b2c÷3a2b=
(2)(10.xy3-y)÷y=
(3)(3ab+2b)÷(2b)=
(0-nm=
(6)a·a2·a3+(-2a3)2-(2a4)2÷a2
(5)-64x4y3÷(-2xy)3=.
(6(3a6)÷(-ga26)=
(7)(18a3-9a2-3a)÷3a=
(8a2.(-2a2)3÷7a=
([2mn(3m-3m)-m(a-3)]÷(-3m2)
2.计算.
(1)(9x2y3-27x3y2)÷(3xy)2
V能力通关
3.先化简,再求值.
(2)(2x2y)3·(-7xy2)÷14x4y3
(1)(4ab3-8a2b2)÷4ab+(2a+b)(2a-b),其
中a=2,b=1.
(3)[(2x+y)(x-y)+y2]÷2x
(2)[(x+3y)2-(x+y)(3x-2y)-11y2]÷
2,其中=号y=2
(4)[a3·a5+(3a4)2]÷a2
14·
练习14整式的乘除(1)
同行学案学练测
计算高手
(难度等级:★★)
七年级数学下BS
基础通关
(④)(-2m)2.(m2-5m-3)
1.计算.
()×(4)°=
2()}‘×()=。
(3(-3)1脑.(-3)w=
(4)(-1)2晒+(-号)厂-(3.14-)
(6(2分x2y2+3m)(-3m+2xy)
6(-22-2-(-号3)3-
(6)799×801-8002=
2.计算.
(1)(0.2x-0.3)(0.2x十0.3)
(6)(18.x3y2-12x2y3+x2y2)÷(-6x2y2)
(2)[(-a5)4÷a2]2·(-2a4)
(7)2x(x2-4x)-(x2+1)(2x-3)
(3)(-2ab)2.(-1ae2).2a26
(8)(4a+3b)(a-2b)-(3a-2b)·a
15·
(9)(a+b)(a2-ab+b2)-(a+b)3
能力通关
3.先化简,再求值.
(1)[(2x+3y)(2x-3y)-(2x-y)2]÷
(-2),其中x=1y=分
(10)(a-b+c-d)(c-a-d-b)
(13a+1D(-2a+1)(3a(3+a)
(2)(2+3x)(-2+3x)-5x(x-1)-(2x-1)2,
中一子
(12)(x+2y-x)(x-2y-之)-(x+y-x)2
.16·(3)-40a5b4+4a4b5-2a3b5(4)-a5b2-6a3
练习11整式的乘法(2)
5y-+y6-6y
1”②)y
(3)12x4yx2
(号-3r2+x4
(4)-9a7b8(5)2x2my6m(6)29ab-10a2-1062
3a-日y-是y(2)-6d6+3a8
2.(1)x6y6(2)6a8(3)-4mn3(4)-a2b2+ab
+2(5)-4a2+9a(6)6.x3-x2+2x+2
a)ir+2mW④-a6a8+0o
(0)-4a*6(8)125x-gy(9)6+:+
练习9多项式与多项式相乘
11t-5(10)5x3+8x2+12x+15
1.(1)2x2+5x-3(2)15x2+xy-2y2(3)-6m2
3.5x3+5.x2-20x-20
+m+2(4)6x4+x2y-2y2(5)x2+5.x
21)-m+号m2-是m+g
练习12平方差公式与完全平方公式
(2)7x4-
1.(1)4x2-1(2)25a2b2-1(3)m2n2+2mn+1
13x2y2-24y4(3)6a2-8b2(4)x3-3x2y+
(5)16x2-9y(6)4a2-9b2-6b-1
6xy2-8y3(5)6a3+7a2+8a(6)-
d-
+6.x2+6.x-4(7)13x2+6x
2.(11(2)3998
(3)1(4)5
3.(1)5a-6(2)22m-23(3)x2+18.x+72
3.(1)16b4-9a2(2)5a2-10ab+5b2(3)as-b
(4)5.x4-3x3-14x2+3.x(5)2a6
练习10整式的乘法(1)
(0m2+4mm(5)x2-x+2y(62y-7
1.(1)-6x3y3(2)-3x4y3(3)-x4y7
(7)1844-726(8)0(9)25-58m
1
(0音y2(5)3x+7z+2
(6)2x3y-6x3y3(7)-12x3y3+20x2y3
3x-4y2+1(2)9y2-x2+2xx2
14x2一2x1
2.1)-2y2+21ry2(254a6-8130
-z4(3)x4-2x2y2+y4(4)9y2-6yz+z2-
4x2-4x-1
(a-ab+4ob-16ab-+a-4o"p
练习13
整式的除法
(5)-x2-10x+5
1.(1)-4abc(2)10y2-1(3)
2a+1
3.-9r2y-xy@a8-1a8+ga8
(4)
(3)a4b5+8a5b4+3a4b
2m2n(5)8x(6)-b
(7)6a2-3a-1(8)-16a8
(5)3x2-4a.x-3x(6)x2m-4y2m+4y”-1
2.1y-3x2-4y2(3x-2
27
(④1a6)2a6《0a(⑦3-号-1
3解:1①原式=4红一,当x=一2,y=号时,原
3.獬:(1)原式=4a2-2ab,当a=2,b=1时,原式
式=-10.(2)原式=5ab-b2-3,当a=-
5’
=12,(2)原式=-x+.当x=号y=2
b=2时,原式=一9.
时,原式=2
5
4.解:原式=(x+1)(x-1)(x2+1)(x4十1)×…×
(x28+1)=(x2-1)(x2+1)(x4+1)×…×
练习14整式的乘除(1)
(x208+1)=(x4-1)(x4+1)X…X(x2048+1)=
18
2号926是
(6)-1
(x8-1)X…X(x208+1)=x4096-1.
2.(1)0.04x2-0.09(2)-2a20(3)-2a7b3c2
练习16整式的乘除(3)
(④m-20m8-12m2(6)是y-9m2
1.(1)-a(2)x13y3(3)-1(4)2x8y12
0-x+2y-日
(5写a26-a6(60》音g(⑦)6-9a2
(7)-5.x2-2x+3
(8)-(x-y)2
(8)a2-3ab-6b2(9)-3a2b-3ab2
2.(1)-3y3+2xy2+4(2)-8ab3-8a9
(10)c2+b2+d2+2bd-2bc-2cd-a2
(3)-2xz(4)-2a(5)9x2-y2+4y-4
1112-a12-5y2-2zy+2y
(6)-6a4+7a3+11a2-a-2(7)-15x2-y2
+10.xy(8)-8x2+99y2(9)-y2
3.解:(1)原式=20y-8x,当x=1,y=2时,原式=
(10)-2x4+9x3-9x2+13x-3(11)2x3m-2
2(2)原式=9x-5,当x=-号时,原式-
(12)24x2n-15
3.解:(1).m-n=4,mn=-3,∴.m2+n2=(m
-8.
n)2+2mn=42+2×(-3)=16-6=10.
练习15整式的乘除(2)
(2)(m2-4)(n2-4)=(mn)2-4(m2+n2)+16.
1.(1)-2m(2)-4x8y4(3)9a4(4)-a4
mm=-3,m2+n2=10,∴.原式=(-3)2-4×
(6)2女2-2y2(64
10+16=9-40+16=-15.(3)8m·32m÷
2.(1)4x2-12x(2)-5ab3(3)-2xy
4m+2n=(23)m·(25)n÷(22)m+2m=23m·25m÷
(4)4n'n6-
8mn0(5)-40m+15m-1
22m+4n=23m+5n÷22m+4n=23m+5n-2m-4n=
2m+"..m-n=4,mn=-3,∴.(m+n)2=(m
(6)2m+8(7)4b2(8)-2xy2+3y-1
n)2+4mn=42+4×(-3)=16-12=4,∴.m+n
(9)-12x3y+24x2y2+3xy3
(10)-8y2+4xy+2x-2
=2或-22=4或是
.28·