广西玉林市第一中学2025-2026学年高二下学期数学周测试题(3月6日)

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玉林市第一中学高二数学周测(2026年3月6日)

一、单选题

1.抛一颗均匀的正方体骰子三次,则向上的面的点数依次成公差为eqIdbdaa19de263700a15fcf213d64a8cd57的等差数列的概率是(   )

A.eqId100cad7b3fbe0f4c65aecee93c590185 B.eqId3c921b2ca2d7e54227cd8e069391a1a5 C.eqId158b045c6172c4178d7aa52083e1489f D.eqId451295d74bed9dbbf5ceb9c75a22fc21

2.若曲线eqIdc904567c3b3734e1eca8d042ef7a7b2d的切线方程为eqId02ebce8b2a915356ed39f36c5bad2ebe,则eqIddd707b69a11f8de5566f23c1a2a9ff5a(    ).

A.eqIdacbc6a613224461ade69362d46550474 B.1 C.eqId81fb134b2b48acc99213fff6ccfee65f D.3

3.函数 eqIdfaa7a5f65470cbdbbd5a0661e279d1e8的单调递减区间为(   )

A.eqIdab1242ec96ac54e2fd418988d5190a88 B.eqId22b419a704616921ef37f2b4cf9e582b C.eqId4e01ad7f831f316285c47ce66235df57 D.eqIdab1242ec96ac54e2fd418988d5190a88和eqIdf27e49b10fcceb2e4b0726772b434ec7

4.当eqId36d71f015144ffaf1faec94a259b4a06时,函数eqId23742f7be7be158c04b912bfced21fc7取得最小值,则eqIda6c57bbef89a37f1a3808c0ceeac0c22(    )

A.eqIdbf31876698721a199c7c53c6b320aa86 B.1 C.eqIda4b8503f4706b8321e4e79a87eadea84 D.2

@@@13e4d534-0a3d-4bff-aca9-2e48aa4254825.已知定义域为eqId8ca6d68f1de3e70696f1d5d60affe6ef的函数eqIdd275fbb3ee5cd1177ca5a2ceecbbef0f的导函数为eqId090a91e4f3c8930674f98a9fa527709b,eqIde35022f82a22ac117807acdf52591649,且eqId090a91e4f3c8930674f98a9fa527709b的图象如图所示,则eqIdd275fbb3ee5cd1177ca5a2ceecbbef0f的值域为(    )

 

A.eqId5e9ac4511ce8d3b86c6cc9b46dc76e73 B.eqIdded23a9ed5304fbf53da97d540b46dd8 C.eqId748ea083b32de93f96d8d157d3b4b583 D.eqId6c6a3c71551940e1383199634068d2a8

6.“eqIdfc329b32ecf0f0532d09a8a21343e8cb”是“函数eqIdd1922b089dcc036d83b0ff5404bd1d1d在区间eqIdaeb49dbba01c4ff5f686ffc8828351b2单调递增”的

A.充分不必要条件 B.必要不充分条件

C.充要条件 D.既不充分也不必要条件

7.定义在eqId6ab5e0524def52baf53480b8726784ed上的函数eqId09f86f37ec8e15846bd731ab4fcdbacd,若对于任意eqId81dea63b8ce3e51adf66cf7b9982a248都有eqIdef8aa8265d0a0fecf4419ecb89ac914a且eqId3471484b64504fc545398f52be830010则不等式eqId261992f0891faaa6c7a57b0299e93e2e的解集是

A.eqId7160d93f92089ef36f3dab809d3114b8 B.eqId9e4a226feca9d9095b0f68191245ed22 C.eqId5265d99095b635f62c7915298ec0e963 D.eqId84a7a4a037a4dfe973f1eb683d93d799

二、多选题

8.(多选)下列求导正确的有(   )

A.eqId0e4abb1cde6159e295b0e7d43c88a6e6 B.eqId5b37c2c7b0384df4a930cd529c009649

C.eqIdb5f4ecf290c8a01c5cace3331d27b578 D.eqId0f1e0df6cb178cce9ddbb278308460a5

9.过点eqId530e5817131adf2c05b99ff18eb9060f且与曲线eqIdabf6bdc4b64d976e4cdf96d068d110b8相切的直线的方程为(    )

A.eqId1f3a0818e00713e00473de1396427c07 B.eqId08e7af1cf125b9dd519aa07226f482bd C.eqId19556a290cd4e98e84b584d30f466614 D.eqId764551064af30b542042b5e501e7e57dpage number 0

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10.已知函数eqId09f86f37ec8e15846bd731ab4fcdbacd的导函数为eqId724340d69477c0ec2418c392b22b1cab,且eqId57a063132b0f6fae1059857e78d9252d,eqIdc3d3767db1ce97724c69d64aa5c4216a,则(    )

A.eqId6057dac7eda87e481912e61e36f1cfba

B.eqId758b2476cdb1a0ba09af64a80911daf0

C.eqId09f86f37ec8e15846bd731ab4fcdbacd有两个极值点

D.当eqId0a856548b20797287df5b0f6de0511bd有两个根时,eqIde6ff4a26ccee2e6b74c257ccbe33557f

三、填空题

11.三名学生分别从计算机、英语两学科中选修一门课程,不同的选法有___________种.

12.若函数eqId2d4c3e6fcfe0f58e9c361f4b975e5ba4的单调递减区间是eqId66f3f52e531e51961c58d1da9b98315c,则其单调递增区间为______.实数eqId294f5ba74cdf695fc9a8a8e52f421328的值为______.

13.某生产厂家生产一种产品的固定成本为eqIdbdaa19de263700a15fcf213d64a8cd57万元,并且每生产eqIdbdaa19de263700a15fcf213d64a8cd57百台产品需增加投入eqId8ec818fc0754296163206e1e8870f9e6万元.已知销售收入eqId9966dfe9109671c587892bd32f0b6699(万元)满足eqId527d055b3a0a0d1e6b73a792b9185b4b(其中eqId81dea63b8ce3e51adf66cf7b9982a248是该产品的月产量,单位:百台,eqIdd7f8ba560b4cb459db3a0fdf333446c3),假定生产的产品都能卖掉,则当公司每月产量为______百台时,公司所获利润最大..

四、解答题

14.已知函数eqId3a136afa15ea25aba12111fd15f6340f

(1)若函数eqId09f86f37ec8e15846bd731ab4fcdbacd在eqId707ea658f3a9359f5740d5aab48f7948处的切线与直线eqId1b979396a703fb14715ba39232f5786a 垂直,求eqId0a6936d370d6a238a608ca56f87198de的值;

(2)求函数eqId09f86f37ec8e15846bd731ab4fcdbacd的单调区间;

(3)若函数eqId4fe7d5809da02c15a43a0e9a898b9086没有零点,求eqId0a6936d370d6a238a608ca56f87198de的取值范围.

 

 

15.已知函数f(x)=ex﹣mx,m∈R.

(1)若f(x)在(1,2)上不单调,求m的取值范围;

(2)当m>0时,若eqId134919ab1f60df29e5c7a6805ab841be对x∈R恒成立,求mn的最大值.

 

 

 

16.已知函数eqId65478ddc9f6aad7e8eed723ef06ace26,其中eqId168b3e4b1d6f04226fa2687a72a268b4是自然对数的底数,eqIdb4ebfef550eec07598671c5929259780.

(1)讨论eqId8f6bfdb24ecf5da863405c2b40936ff9在定义域内的单调性;

(2)设函数eqId8d3f621d3954735bb7de4f2899083861,当eqId3774aad147182f3b55a223a7590b1c4e时,证明:存在唯一eqId13eed78c0174f1cc1c8da7ee82a467aa,使eqId85925e968d1367bf589d85b5a42a49c8.

page number 1

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《高二数学自主练习(2026年3月6日)》参考答案

题号

1

2

3

4

5

6

7

8

9

10

答案

A

D

D

A

D

A

D

BCD

BC

AD

 

1.A  【详解】抛一颗均匀的正方体骰子三次,共有eqId821a4c53d8d4ed5205feb4758427b6c4 种情况,构成公差为eqIdbdaa19de263700a15fcf213d64a8cd57的等差数列只能是eqId543a24f0a442f3a542b3dcf4dc823810四种情况,因此由古典概型概率公式可得向上的面的点数依次成公差为eqIdbdaa19de263700a15fcf213d64a8cd57的等差数列的概率是eqId0374a39d3a4f3f34cb90f8c90948d2d2,故选A.

2.D  【详解】eqIdb6c8191420557159eaf4222f72e0f3f8,设切点为eqId23b4f86e48e2b0d63c1865c60ed1e4d1,则eqId29be5b4ba6b799ced0bafc20937b05e8解得eqId78bb61380fffb4a4297bcbcf8fe8446e, eqIdc861e3728c51f2f447c24880cb7f0f4d,

所以eqId367e788c32187ae2cc97aaa24da1d40d.故选:D.

3.D  【详解】eqId0c41755cdea5ddc4b9057e1186f1ed0d,则eqId5a2fa9325f459f6572ee775afab9b8c5且eqId33a0e656a2de8d47b9001cc32b1316eb,令eqIdcc4ab6091a26cb23728e504453c57a9a或eqId4828766941e62846be183e99ab5aef7a,

所以函数eqId4fe7d5809da02c15a43a0e9a898b9086的单调减区间为eqIdab1242ec96ac54e2fd418988d5190a88和eqIdf27e49b10fcceb2e4b0726772b434ec7.故选:D

4.A  【详解】解:eqIde57ed3c989184b6ba3a7483c2061e543,

当eqIdc97cd5f39f4afc756388135374e1dd24时,eqIdb0c72d250a079379c5175693c165248c;当eqId78f6573de88741f41b078157e1ab421b时,eqId7667e3a020f9d2883ffbaaed15e271b1.所以函数eqId09f86f37ec8e15846bd731ab4fcdbacd在eqId64fcec77177443519207ffc6afb988d0上单调递减,在eqId78b603463669f21425b4940bf66c10bb上单调递增,所以当eqIdf1e8ebd7c4463e7311f7ab4d7cd7d241时,eqId09f86f37ec8e15846bd731ab4fcdbacd取得最小值.故选:A.

5.D  【详解】当eqId15f4ea58aad85d5d956a8a1abe3ae631时,eqId28881f4f67af228d31958ce1e6c5d6ae,eqIdd275fbb3ee5cd1177ca5a2ceecbbef0f单调递减,当eqId011934dd59e8fd43d1872eb769ca2d34时,eqIdf1edc2167ea27ee3314b4dc399d29219,eqIdd275fbb3ee5cd1177ca5a2ceecbbef0f单调递增,

则eqId031db59b90628d2cce14c337535c7eb5.因为eqIde35022f82a22ac117807acdf52591649,所以eqIdd275fbb3ee5cd1177ca5a2ceecbbef0f的值域为eqId6c6a3c71551940e1383199634068d2a8.故选:D.

6.A  【详解】eqId1d00738a51e70df45e4f15bb021a1834 ,∵若函数函数eqId30407dac1a5fb8678711d5a7dc537817在eqIde2dfaa0e63b9c720093ab80e2ed24c9d单调递增,

∴eqId988a2a940058869bb3832350f53fda33 在区间eqIde2dfaa0e63b9c720093ab80e2ed24c9d上恒成立.∴eqId8758c61721d7c812164f88db41791d6f ,而eqId0f42b2a9736c8943106472a7398d2892在区间eqIde2dfaa0e63b9c720093ab80e2ed24c9d上单调递减,

∴eqId2397df3279607612ea3cbef101ee0bf3.即“eqIdb3878d46c620ecbff2e7ae431f2fed57”是“函数eqId30407dac1a5fb8678711d5a7dc537817在eqIde2dfaa0e63b9c720093ab80e2ed24c9d单调递增”的充分不必要条件.  故选A..

7.D  【详解】令eqId6c1ead370568dd9c28a95dc52014f465则eqIddfc018f7f8e26e4e339b78fbdfa03bb2所以eqIdbe1ce3f01e2b6364f9a9fdaf197d5e29在eqId6ab5e0524def52baf53480b8726784ed上单调递增,又eqId7f17ae141a0439e6ec8cebc282ed6475 所以eqId2c56cea99d8ecb38764df18412204de8的解集eqId84a7a4a037a4dfe973f1eb683d93d799  故选D

8.BCD  【详解】选项A:eqId73a660a55f3ef6cbb888460d75b6e923,故A错误;选项B:eqId081f11965e678d36dcb0dedfe42bde93,故B正确;

选项C:eqIdfe84f271f0503390a31f3b155b9295f2,故C正确;选项D:eqIdc4a391f39e9d5aed64555c13afe63d19,故D正确;

9.BC  【详解】设过点eqId530e5817131adf2c05b99ff18eb9060f的切线与曲线eqId942c2141d01bde6b48210c56a17fc75e相切于点eqIde142d46a229340d34645869d87ccaee1,因为eqIdd8451296ce12ef36d28a689c84d7275b,则曲线eqId942c2141d01bde6b48210c56a17fc75epage number 2

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