内容正文:
第2章 一元二次方程
2.2一元二次方程的解法
第4课时 一元二次方程的解法
初中数学浙教版(2024)八年级下册
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1.经历并理解一元二次方程求根公式的推导过程,会用公式法解一元二次
方程.
2.理解并会计算一元二次方程根的判别式,会用判别式判断一元二次方程
的根的情况.
学习目标
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2
配方法解方程的基本步骤:
1. 移项:将常数项移到等号右边,含未知数的项移到等号左边.
2.二次项系数化为1 :如果二次项系数不是1,将方程两边同时除以二次项系数.
3.配方:方程两边同时加上一次项系数一半的平方.
4.写成的形式.
5.用开平方法求解.
用配方法解一元二次方程的基本步骤是什么?
知识回顾
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思考:任何一个一元二次方程都可以写成一般形式ax2+bx+c=0①,你能否用配方法
得出①的解?
填空:
方程的两边同除以____,得=0.
移项,得=_____________.
方程的两边同加上_____________,得 +_______= _______.
a
新知探究
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即(x+_______)2=,
若≥0,
可得 = ,或 =,
∴,或,
我们也可以简单地表示为.
新知探究
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5
对于一元二次方程ax2+bx+c=0(a≠0), 如果≥0,那么方程的两个根
为.
这个公式叫作一元二次方程的求根公式.利用求根公式,我们可以由一元二
次方程的系数a,b,c的值,直接求得方程的根.这种解一元二次方程的方法叫
作公式法.
新知探究
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从一元二次方程ax2+bx+c=0(a≠0)的求根公式的推导过程中不难看出,方程的根的
情况由代数式的值来决定.因此叫作一元二次方程的根的判别式,
通常用希腊字母“”表示,即= .
它的值与一元二次方程的根的关系是:
>0方程ax2+bx+c=0(a≠0)有两个不相等的实数根;
0方程ax2+bx+c=0(a≠0)有两个相等的实数根;
<0方程ax2+bx+c=0(a≠0)没有实数根.
思考:方程ax2+bx+c=0(a≠0)的根的情况由什么决定?
新知探究
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7
例1 用公式法解下列一 元二次方程:
(1) 2x2x=0. (2) 4x2=x. (3) x2=0.
解:(1) 对方程2x2x=0,
a=2,b=,c=3, =3=1,
∴ =,
∴ x1 == , x2 =.
例题精讲
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例1 用公式法解下列一 元二次方程:
(1) 2x2x=0. (2) 4x2=x. (3) x2=0.
解:(2) 移项,得方程4x2x =0,
则a=4,b=,c=1, ==0,
∴ =,
∴ x1 =x2 =.
例题精讲
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9
例1 用公式法解下列一 元二次方程:
(1) 2x2x=0. (2) 4x2=x. (3) x2=0.
解:(3) 方程的两边同乘4,得3x2x=0,
则a=3,b=,c=, ==88,
∴ = ,
∴ x1 = , x2 = .
例题精讲
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公式法解方程的基本步骤:
1.将方程化为一般形式.
2.确定a,b,c的值.
3.计算.
4. >0:方程ax2+bx+c=0(a≠0)有两个不相等的实数根;
0:方程ax2+bx+c=0(a≠0)有两个相等的实数根;
<0:方程ax2+bx+c=0(a≠0)没有实数根.
新知探究
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11
例2 解方程:.
解:去括号,得x2x= x2x+4,
化简,得x2x+4= 0,
方程的两边同乘2,得x2x=0,
则a=1,b=,c=8, ==4,
∴ = ,
∴ x1 = =4, x2 = .
你能用因式分解法
解该方程吗?
例题精讲
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例2 解方程:.
解:由原方程,得,
移项,得,
∴ =0,
=0 ,
∴ ,或,
解得x1 =4, x2 .
例题精讲
因式分解法
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1.一元二次方程x23x=1中,的值为( )
A. 5 B.13 C. 13 D. 5
B
随堂练习
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2.一元二次方程x2-7x-2=0的实数根的情况是( )
A.有两个不相等的实数根
B.有两个相等的实数根
C.没有实数根
D.不能确定
A
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3.用公式法解方程5x2﹣6=7x,下列代入公式正确的是( )
A.
B.
C.
D.
B
随堂练习
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4.下列一元二次方程没有实数根的是( )
A.-2x2+x+1=0
B.x2+2x+3=0
C.x2-x-1=0
D.x2+2x-3=0
B
随堂练习
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5.用公式法解-x2+3x=1时,先求出a,b,c的值,则a,b,c的值依次为( )
A. -1,3,-1
B. 1,-3,-1
C. -1,-3,-1
D. -1,3,1
A
随堂练习
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6.用公式法解下列方程:
(1)3x2-2x-5=0. (2)2x2-5x+3=0.
解:(1)对方程3x2-2x-5=0,
有a=3,b=,c= -5, ==64>0,
∴ = ,
∴ x1 = = , x2 =.
随堂练习
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6.用公式法解下列方程:
(1)3x2-2x-5=0. (2)2x2-5x+3=0.
解:(2)对方程2x2-5x+3=0,
有a=2,b=,c= 3, ==1>0,
∴ = ,
∴ x1 = =, x2 = .
随堂练习
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课堂小结
公式法解方程的基本步骤
1.将方程化为一般形式.
2.确定a,b,c的值.
3.计算.
4. >0:方程ax2+bx+c=0(a≠0)有两个不相等的实数根;
0:方程ax2+bx+c=0(a≠0)有两个相等的实数根;
0:方程ax2+bx+c=0(a≠0)没有实数根.
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谢谢
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