2.4 用因式分解法求解一元二次方程 同步练习 2024-2025学年北师大版数学九年级上册

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2.4用因式分解法求解一元二次方程培优提升训练2024-2025学年北师大版数学九年级上册

一、选择题

1.关于x的方程eqId64b3c6822b2d5454d2c060d0148d8ed9的解是(   )

A.eqId707ea658f3a9359f5740d5aab48f7948 B.eqId6c65d84aefe159aebc850cc339a06053 C.eqIdd4049b329e8cf711663e050e0dc9cdea D.eqIdd70bd347c9149626acd45115ba278c1e

2.已知eqId15c0dbe3c080c4c4636c64803e5c1f76三边分别为a、b、c,其中eqId36e15cbd7c42d7b15d7ba8d2b28ab8df,eqId82986ab38a4ae58593191ccae2a44f62,c是一元二次方程eqId87d10fe168089df2c652ef4f99ba2b00的一个根,则eqId15c0dbe3c080c4c4636c64803e5c1f76的面积是(    ).

A.12或eqIda46fd58e40935064129c4676ec310791 B.24或eqId588c3822b7812e711b4ad86647b15dc1 C.24或eqIda46fd58e40935064129c4676ec310791 D.12或eqId588c3822b7812e711b4ad86647b15dc1

3.已知实数x满足eqId2a481903fca1073531bfd363fdbbadba,那么eqId13f40c24c64bbb0645fcf585f4e66872的值为(   )

A.eqId274a9dc37509f01c2606fb3086a46f4f B.eqIdacbc6a613224461ade69362d46550474 C.1 D.eqId274a9dc37509f01c2606fb3086a46f4f或1

4.已知关于x的一元二次方程eqIdbdb2d6c85141c595c22ebd713b42086d的解是eqIdc736f93460b2978d60e26746b2266808,eqIdb502795b6bd7b8cce18de8ea5dbc3db1,则另一个关于x的方程eqId119a0465858f15c195aabf33665712a7的解是(   )

A.eqId6f249379827788a294f5961601002c8d,eqIdd91d01db320460a6d3fc8c106ee18f0f B.eqIdb60b1538fdee8f163a0ee8f897588ad9,eqId99bb8ea00f1ca41327a7232238f5347c

C.eqId9ca37e9671dbc610488a1be71542df96,eqId05e3f6dcca1226f9658d36baa952e039 D.eqIdc736f93460b2978d60e26746b2266808,eqIdb502795b6bd7b8cce18de8ea5dbc3db1

5.已知m是关于x的一元二次方程eqIda2b18774d64e490ff43f79b046ee92a3的一个实数根,且满足eqIdeca279c775a1d051f355f20405f3a915,则a的值为(   ).

A.eqId81fb134b2b48acc99213fff6ccfee65f B.1 C.eqId81fb134b2b48acc99213fff6ccfee65f或eqIdacbc6a613224461ade69362d46550474 D.eqId81fb134b2b48acc99213fff6ccfee65f或1

6.关于eqId81dea63b8ce3e51adf66cf7b9982a248的一元二次方程eqId1ee40b9771ad39f3c09a7479081d7ba1的一个解是0,则eqId294f5ba74cdf695fc9a8a8e52f421328的值为(    )

A.0 B.eqId9e0262791cc14598c6fc5ed0937d0124 C.1 D.eqIdacbc6a613224461ade69362d46550474

7.方程eqId6a5bfa882b231bed16b3355ca4286210解的个数(   )

A.eqIdbdaa19de263700a15fcf213d64a8cd57 B.eqId61128ab996360a038e6e64d82fcba004 C.eqId5ca7d1107389675d32b56ec097464c14 D.eqIdb8860d9787671b53b1ab68b3d526f5ca

8.对于实数eqId632244ea6931507f8656e1cc3437d392,定义一种新运算“eqIde2ad8dc4e4f2b4fb9ded49afec4da261”:当eqId1132de2e8913dba9c5cc2396ecb09fcf时,eqId283cc179f349329dfd0e1a76d98a09ba;当eqIdc6a46e678bf9d2df5ad4c782b3dc22f5时,eqIde4778104adc6a91c6fe19869b89cf199.若eqIdc0d99611530e21a7ab0fb465eb9b278a,则实数eqId380bbacf854e30e2e747fc286d2b9997(  )

A.10 B.4 C.4或eqId01317332a203c898536b1d0459f51d23 D.4或eqId01317332a203c898536b1d0459f51d23或10

二、填空题

9.关于eqId81dea63b8ce3e51adf66cf7b9982a248的方程eqId1852448a8b56a2ff23d1a797de43502e的解是eqIdecb245da3e564531457a7acada5cb691(eqId29497c81efb133646bc2aae15a7ecf48为常数,eqId20849c00c47cbdc43f18d53341b6c4e5),则方程eqIdb4b9f9eba6f2e9557d198de27907c089的解是            .

10.已知等腰eqId15c0dbe3c080c4c4636c64803e5c1f76的一边eqId07160f14b3b453bebb64cb2bf96dc85a,而eqId15c0dbe3c080c4c4636c64803e5c1f76另外两边的边长恰好是关于eqId81dea63b8ce3e51adf66cf7b9982a248的一元二次方程eqId036d918f29bd75ce3f31da9af5e18f70的两实数根eqId8ce7ae90d808f05e86ea063238e4b2f9,则这个三角形的周长为           .

11.菱形eqId411b38a18046fea8e9fab1f9f9b80a5f的两条对角线相交于点O,若菱形的边长是eqIde9939dc0caf74052757f2eec44bb0662的一个根,且eqId4494a85de0be0b97a69348115aef8513,该菱形的面积是        .page number 0

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12.若等腰eqId15c0dbe3c080c4c4636c64803e5c1f76的一边长为eqIdb8860d9787671b53b1ab68b3d526f5ca,另外两边eqId0fd9675c7c6dd0a2dc1ebbdae3a2e45c恰好是关于eqId81dea63b8ce3e51adf66cf7b9982a248的方程eqIdab197de377150e61fe393464aca9724b的两个实数根,则eqId15c0dbe3c080c4c4636c64803e5c1f76的周长是      .

三、解答题

13.用适当的方法解下列方程

(1)eqId42485aa3d10c6453650799559a7cc8ea

(2)eqId1a851a3e3785282b0017fdb6a48ffbc9

(3)eqId08c9b680e2a61a10dff8110c794fa606

 

 

 

 

 

 

 

 

 

14.阅读下面的材料:

解方程eqIda7cc00bb1a852a334bbf2e0a4ae82432这是一个一元四次方程,根据该方程的特点,它的解法通常是:设eqId52ad7c068b9b7c0fd764cf7746407079,则eqId8b02034e1538d11e67f0caecf8ed9dbd,∴原方程可化为eqIdd8327e46f9dc74cc07d68be4d91a4140,解得eqIdd5a0dbe52422c7eab65ba1c2c237ff1c,当eqIdc9355031ea0b2dc9cef3777621bc6d38时, eqId2a42ca7d20adfde72258987186494557,当eqIdde72a5190834f5dbe895596656c038b3时,eqId6fd25d76d722aa236ca4145a3792c0c4.∴原方程有四个根是: eqId7fba0f69d58014f6ecf09a602976e468, eqIdbe1d26787e79bcd89c9338528308650b,eqId5b0fa6f890328c5a34e51c50ecffe1e0,以上方法叫换元法,达到了降次的目的,体现了数学的转化思想,运用上述方法解答下列问题.

(1)解方程:eqId3c024614e374026a19e0b442deee6195.

(2)已知实数a,b满足eqId37f47fcb3c113f7a53af327b42f92d31,试求eqIdc925be255ca736a53b24d13ddede1a86的值.

 

 

 

 

 

15.已知eqIdbd8ca3aa2d1ba52e82613d0d65d800e7是一元二次方程eqIdf3f0e6ab9561981a4b97cbe19340e84b的两个实数根.

(1)求eqIdf0a532e15e232cb4b99a8d4d07c89575的取值范围.

(2)若eqId87a60302649eb940748da818199e55da,求eqIdf0a532e15e232cb4b99a8d4d07c89575的值及方程的另一根eqIdaec19b68e3add9d5bfcc6269a1855b87.

 

 

 

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16.关于 x 的一元二次方程eqId5baba5ec7875ef8d7db9fabb9e99ab8a有实数根.

(1)求 k 的取值范围;

(2)如果k是符合条件的最大整数,且一元二次方程eqIdb024254f9450d3f0996dd3fbd9b56bbd与方程eqId69dd3d03decd8efffcc795cc80a79bb7有一个相同的根,求此时 m 的值.

 

 

 

 

 

 

 

 

17.关于eqId81dea63b8ce3e51adf66cf7b9982a248的一元二次方程eqId92b800b7d6a688abf8a3018c133cec9e经过适当变形可以写成eqId3c4475f5b2a737ad1bc5811b95687a86的形式eqId54e1d0f65817ba32a732040518f41440现列表探究eqIde52e3adabfbf5ca5dd77e1dbbbf0686e的变形:

变形

eqId294f5ba74cdf695fc9a8a8e52f421328

eqIdb6a24198bd04c29321ae5dc5a28fe421

eqIdb1010846eeec6c9da29640f5aa3f8738

eqIdd7016a699b286cc25a633567c738a510

eqIdacbc6a613224461ade69362d46550474

eqIdd91e07104b699c4012be2d26160976a2

eqId274a9dc37509f01c2606fb3086a46f4f

eqId74226571753eb07c7de0e21aea49dc0d

eqIdc95b6be4554f03bf496092f1acdfbb89

eqIdb8860d9787671b53b1ab68b3d526f5ca

eqId5ca7d1107389675d32b56ec097464c14

eqIdfcd46ea501dc8eaff811509c68dd5b1d

eqIdbdaa19de263700a15fcf213d64a8cd57

eqId36a1b09c653185842513e24ebba60bb3

eqId6f8c4c029e552954bd493b49aeab82d5

eqIdebb79973b239022905265b54fda9f5c6

eqId61128ab996360a038e6e64d82fcba004

eqId61128ab996360a038e6e64d82fcba004

eqId8b06e95b57b7a81cd81d05557a11fa92

【观察】表格中eqId36a1b09c653185842513e24ebba60bb3的值为______,eqId294f5ba74cdf695fc9a8a8e52f421328与eqIdb6a24198bd04c29321ae5dc5a28fe421满足的等量关系为______,eqIdb1010846eeec6c9da29640f5aa3f8738的值随eqId64da75a02173c2a5eb40f4c68d0f4f36值的增大而______(填“增大”或“减小”);

【尝试】若一元二次方程eqIde52e3adabfbf5ca5dd77e1dbbbf0686e变形为eqIdd56687a566b4944556833df72ddab6e4,求eqId294f5ba74cdf695fc9a8a8e52f421328、eqIdb6a24198bd04c29321ae5dc5a28fe421的值;

【拓展】若一元二次方程eqId92b800b7d6a688abf8a3018c133cec9e经过变形可写成eqId3c4475f5b2a737ad1bc5811b95687a86,则eqIdb1010846eeec6c9da29640f5aa3f8738的最大值为______(用含有eqId2c94bb12cee76221e13f9ef955b0aab1、eqId071a7e733d466949ac935b4b8ee8d183的代数式表示).

 

 

 

 

 

 

 

 

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