2025年九年级中考数学学业水平考解答题复习-旋转综合题(线段问题)

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2025年九年级学业水平考解答题复习

旋转综合题(线段问题)

 

 

1.在平面直角坐标系中,点eqId32366143230ca122894a4bada7c7b96d,点eqId7f9e8449aad35c5d840a3395ea86df6d在x轴的负半轴上,eqId70b449b1b22749f6efd914f26b1f71ad.将eqId3fe95f656b98b53f71a9d72bf0c9a4b9绕点eqId1dde8112e8eb968fd042418dd632759e顺时针旋转,得eqIdb17feedef8b38275d0b9bf982a5478ec,点eqId01c74a907dda6bb7d9d56d009d9df253旋转后的对应点为eqIdd77993759b8615ef0b42cb56ef027ff0.记旋转角为eqIde170f206fdbbd834aad7580c727e2cc6.

@@@0ed7b092-c4d1-4866-9786-4e94cc021bb8  

(1)如图①,当eqIdb6c96cb3ac8290e09c55d4eb336a8608时,求eqId17cf8e6bfbe3b365f8e9278cc469d2b1与eqIdf52a58fbaf4fea03567e88a9f0f6e37e的交点eqIdc5db41a1f31d6baee7c69990811edb9f的坐标;

(2)如图②,连接eqIde663220a66eff19da6a71e46b397db2e,当eqId7bb0628cecbfc98d390e5447d52414e8经过点A时,求eqIde663220a66eff19da6a71e46b397db2e的长;

(3)设线段eqIde663220a66eff19da6a71e46b397db2e的中点为eqIdac047e91852b91af639feec23a9598b2,连接eqId83f00d88b9f850dea09aa8c682b9d610,求线段eqId83f00d88b9f850dea09aa8c682b9d610的长的取值范围(直接写出结果即可).

2.综合与实践

将正方形eqId411b38a18046fea8e9fab1f9f9b80a5f的边eqIdf52a58fbaf4fea03567e88a9f0f6e37e绕点eqId5963abe8f421bd99a2aaa94831a951e9逆时针旋转至eqId943712a5e96b16cc15d775cc4687237e,记旋转角为eqIde170f206fdbbd834aad7580c727e2cc6.连接eqId6655cc150ddc9deba2254780984d0024,过点eqId8455657dde27aabe6adb7b188e031c11作eqIde6e490f703eb6c9bb1278c78ebc2d661垂直于直线eqId6655cc150ddc9deba2254780984d0024,垂足为点eqId2a30f3a8b673cc28bd90c50cf1a35281,连接eqIdda650ee630c36fd5ce9abb4fb826df7b,eqId4eedae8d316c76e3d0b451256de03fb9,

@@@17cd2f41-c0f1-43a1-aa9f-fa0430beffae

(1)如图1,当eqId97cf714ffb3fd5917a76b191640b55fe时,eqId9c4851109ebad7d40fd6e8c0ed91cde6的形状为_______,连接eqIdd40b319212a7e7528b053e1c7097e966,可求出eqIdfbaeec6b78ac2dce4b20c3fee0139bc6的值为______;

(2)当eqId783d872617eed2bbd474035156b6caaf且eqIdd15b7c09aac2543b8615aca6b62ee36d时.

①(1)中的两个结论是否仍然成立?如果成立,请仅就图2的情形进行证明;如果不成立,请说明理由;

②当以点eqId3953cec61ac602ce5eb59b7912352179,eqId2a30f3a8b673cc28bd90c50cf1a35281,eqIdc5db41a1f31d6baee7c69990811edb9f,eqId8455657dde27aabe6adb7b188e031c11为顶点的四边形是平行四边形时,求eqId4c760e281e60a91cd39ffad6852d09dd的值,若eqId04725e51b4870658f74de79403e3898f,请直接写出此时点eqId2a30f3a8b673cc28bd90c50cf1a35281到eqId9d78abbad68bbbf12af10cd40ef4c353的距离.

3.[问题情境]如图1,eqId2a30f3a8b673cc28bd90c50cf1a35281为正方形eqId411b38a18046fea8e9fab1f9f9b80a5f内一点,eqIdedc5df62e8ac9c74a46462519b95479a,eqId662a9a633cdf3c5f19105025d69fc089,eqIdf1070d38d2fea1dc88c6eb31d320b763,将eqIdf1a3b94566843e92ce775ff6bdf386fb绕点eqId5963abe8f421bd99a2aaa94831a951e9按逆时针方向旋转eqId0a6936d370d6a238a608ca56f87198de度(eqIdd46f4e29fb0230e123d0f5c6ddd3fe2f),点eqId7f9e8449aad35c5d840a3395ea86df6d,eqId2a30f3a8b673cc28bd90c50cf1a35281的对应点分别为点eqId3953cec61ac602ce5eb59b7912352179,eqIdd3b1a5427d8ff23df0f3ec194756c84c.

[问题解决]page number 0

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@@@6628830c-57b6-4939-a968-ea426ca46649  

(1)如图2,在旋转的过程中,当点eqId3953cec61ac602ce5eb59b7912352179落在eqId60ef95894ceebaf236170e8832dcf7e3上时,求此时eqId7ffb952f86442845da723fd291564484的长;

(2)若eqId449d9e1077ec791367d36557259fbece,如图3,得到eqId80f3f4656a7cb49737734202bdcd460f(此时eqId3953cec61ac602ce5eb59b7912352179与eqId8455657dde27aabe6adb7b188e031c11重合),延长eqId85c4bdfb0db1e31e8459df1d15f9ab55交eqId45d30252720ff0a2b1f105523e9aa3b4于点eqIda0ed1ec316bc54c37c4286c208f55667,试判断四边形eqIdad947cf65a77b26316b3c867189b8123的形状,并说明理由;

(3)在eqIdf1a3b94566843e92ce775ff6bdf386fb绕点eqId5963abe8f421bd99a2aaa94831a951e9逆时针方向旋转的过程中,直接写出线段eqId84f0ae0d8e74c9ca1708ce83c36c94df长度的最大值.

4.问题情境:

“综合与实践”课上,老师提出如下问题:将图①中的矩形纸片沿对角线剪开,得到两个全等的三角形纸片,表示为eqId15c0dbe3c080c4c4636c64803e5c1f76和eqId72cb97395ebc5ee1b212afb7a97b985c,其中eqIddd3578471c9b37dee9cf3e6fd706d2e4,将eqId15c0dbe3c080c4c4636c64803e5c1f76和eqId72cb97395ebc5ee1b212afb7a97b985c按图②所示方式摆放,其中点B与点F重合(标记为点B).当eqId4f10327213a940d94a796ba0bb46d42a时,延长eqIde6e490f703eb6c9bb1278c78ebc2d661交eqId60ef95894ceebaf236170e8832dcf7e3于点G,则四边形eqId693cd6179b2a92f03153ce12a0e86b95的形状为  .

@@@ad6d96f3-d109-4b74-891c-bf2b7ad6fd8f  

深入探究:

老师将图②中的eqIdabe4bdc5d9e833b23a1b916c06fc1a35绕点B逆时针方向旋转,使点E落在eqId15c0dbe3c080c4c4636c64803e5c1f76内部,并让同学们提出新的问题.

(1)“巧思小组”提出问题:如图③,当eqIdbd9a666965db844e9000495b94124b60时,过点A作eqIdcd7e284eac4b90bfb327de768a7beef6交eqId85c4bdfb0db1e31e8459df1d15f9ab55的延长线于点eqId889696ca1742000a208a7c2f40c3768e与eqId60ef95894ceebaf236170e8832dcf7e3交于点N.试猜想线段eqIdd50703c46b6153945d718b198f03b4b5和eqId85c4bdfb0db1e31e8459df1d15f9ab55的数量关系,并加以证明.

(2)“聪慧小组”提出问题:如图④,当eqId61ba4c2b1162042e43e5081c7a2d3fda时,过点A作eqIdb23393d953a5bcb37b595caba358f34d于点H,若eqIdc37ad02c1055aa44d464b53901e3fc9b,则eqIde776314d1f1670d3a90f2a35125feb67  .

5.在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId597ce705d3a2fe04d29de9e81ec6250d,以点eqId7f9e8449aad35c5d840a3395ea86df6d为中心,将eqId15c0dbe3c080c4c4636c64803e5c1f76顺时针旋转eqIde170f206fdbbd834aad7580c727e2cc6,得到eqId7988923407b9abb78ef8ab45829678fa;再以点eqIda18722354086c42e62334983fc50eb6a为中心,将eqId7988923407b9abb78ef8ab45829678fa顺时针旋转eqIde170f206fdbbd834aad7580c727e2cc6,得到eqId0bcbdc7c38b91bf5e82286affa7352a4;连结eqIdb470c4e195cf7a07b7a331ce4b436e03,

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@@@957af81d-6b2e-42e0-802c-1f348baaa613  

(1)如图eqIdbdaa19de263700a15fcf213d64a8cd57,若eqIdfcd0ced286a0fbc7e4862f8147264277,eqId33ac762a2899a58faa0d3ab44f1281fa,求eqIdb470c4e195cf7a07b7a331ce4b436e03的长;

(2)如图eqId61128ab996360a038e6e64d82fcba004,eqIdf177051ef03f708706c268cfaf78edfa,探究eqIdb470c4e195cf7a07b7a331ce4b436e03与eqIde26d9636ad77369535852c6e4493446a的位置关系,并说明理由.

6.如图1,将等腰eqIdc922cbd707131b52757c464804ca24f1绕正方形eqId411b38a18046fea8e9fab1f9f9b80a5f的顶点A逆时针方向旋转,其中eqIdd3430106c774bdc93033ccd85ff68a09,eqIdc0c78503bfdb97084776dfd2e677d972,连接eqId4cae70b8a9d2d2e96dea62c00ced04b9,点H为eqId4cae70b8a9d2d2e96dea62c00ced04b9的中点,连接eqIde3064b70f24e9bbcab76e0dc61274b9b,eqId0a16f5621716bfef7a056a3f2712feb4,eqIde6e490f703eb6c9bb1278c78ebc2d661,得到eqIdc029c9261c7b041e7008fe9c33f1c8a6.

@@@2a4eea4f-76f4-4131-a6e3-20d9dad3af98

(1)如图2,当点E恰好落在正方形eqId411b38a18046fea8e9fab1f9f9b80a5f的对角线eqId60ef95894ceebaf236170e8832dcf7e3上时,判断eqIdc029c9261c7b041e7008fe9c33f1c8a6的形状,并说明理由.

(2)如图3,当点E恰好落在正方形eqId411b38a18046fea8e9fab1f9f9b80a5f的边eqIdf52a58fbaf4fea03567e88a9f0f6e37e上时,(1)中的结论还成立吗?请说明理由;

(3)发现若连接eqId85c4bdfb0db1e31e8459df1d15f9ab55,在旋转eqIdc922cbd707131b52757c464804ca24f1的过程中,eqId3c06aa28f4e4ee00cdf3c8e7847225ed为定值,请你直接写出eqId3c06aa28f4e4ee00cdf3c8e7847225ed的值_______.

7.如图,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId9c06154cae3bf7a8ce5a1e97a7380875,eqId4c2e679d7b314ff58c284da08e8edbb3,eqId8b5f215a42c4b7078d8d65923eb9980e于点D.点G是射线AD上一点,过G作eqIde9c257b9502b7eda5fd2ff8b6fbc6c7d分别交AB、AC于点E、F:

@@@b8a665c4-3204-4863-8152-e775931f1f28  

(1)如图①所示,若点E,F分别在线段AB,AC上,当点G与点D重合时,求证:eqId82ef73f7abcfec2a095949321c34ef0b;

(2)如图②所示,当点G在线段AD外,且点E与点B重合时,猜想AE,AF与AG之间存在的数量关系并说明理由;

(3)当点G在线段AD上时,请直接写出eqId9f9c68466c946bb624071672f5e91891的最小值.

参考公式:eqId60921aa50c55ae8a3362ef55306fd6ff

8.在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqIded10df4140819d5451773a45de66201b,eqId8455657dde27aabe6adb7b188e031c11是eqId0dc5c9827dfd0be5a9c85962d6ccbfb1上一点.

@@@095c89f5-9d5a-47cb-ba52-f8c6ba3e63ee

(1)如图1,eqId2a30f3a8b673cc28bd90c50cf1a35281是eqIdf52a58fbaf4fea03567e88a9f0f6e37e中点,eqId6edcd7fc04ce1adb77a531171f375780,eqIdc8832c5450a61500ccbf73d95e16f449,eqIde980379b2be68ed3f8a042248c3adc3d,求线段eqIdd40b319212a7e7528b053e1c7097e966的长度;page number 2

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