2025年九年级中考数学学业水平考解答题复习-旋转综合题(角度问题)

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2025年九年级中考数学学业水平考解答题复习

旋转综合题(角度问题)

 

 

1.综合与实践

如图,正方形eqId411b38a18046fea8e9fab1f9f9b80a5f和正方形eqIda8d0e8404f347a0eb4c76f4d25d9bdac有公共顶点eqId5963abe8f421bd99a2aaa94831a951e9,将正方形eqIda8d0e8404f347a0eb4c76f4d25d9bdac绕点eqId5963abe8f421bd99a2aaa94831a951e9按顺时针方向旋转,记旋转角eqId71384f5f186d2426503726ea7acfe42b,其中eqId6c0fa40c1c5420535d4e6c01568de380,连接eqIdd004d2d115b477ade6af7ddb93db0df8,eqId274cf35acb4a1748d15c39d15a9bea7b.

@@@f6794143-0b52-4469-a5af-60a87ade3946

(1)如图1,当eqIdea2c2b311c6907abe242bb0a3ee519e1时,求证:eqId8182e8ed3ee96372ee39a77faea9b0d3;

(2)请你画出除图1外,满足eqId8182e8ed3ee96372ee39a77faea9b0d3的其它图形,并写出eqIde170f206fdbbd834aad7580c727e2cc6的度数;

(3)旋转过程中,eqId9251dff989f7d60db751b73033dee269________时,eqIdd004d2d115b477ade6af7ddb93db0df8最大,eqId9251dff989f7d60db751b73033dee269________时,eqId274cf35acb4a1748d15c39d15a9bea7b最小;

(4)旋转过程中,判断eqIdd004d2d115b477ade6af7ddb93db0df8与eqId274cf35acb4a1748d15c39d15a9bea7b的大小关系,并写出对应的eqIde170f206fdbbd834aad7580c727e2cc6的范围.

2.如图,在平面直角坐标系中,eqId15c0dbe3c080c4c4636c64803e5c1f76三个顶点的坐标分别为eqId48459fcff7af81f603f4a4311691c214,eqId9412b2f37124a6f9c10d29623e3725d3,eqId2e6cba121862eb114460e4e67e7274db.

@@@c45afc09-3711-41d8-b4e4-5f7fd343fc2c

(1)①以点B为旋转中心,画出将eqId15c0dbe3c080c4c4636c64803e5c1f76按顺时针方向旋转eqIdc02b54dc6b3e1bb6544f47d4c8743fcf后的eqId7988923407b9abb78ef8ab45829678fa;

②以原点O为旋转中心,画出将eqId15c0dbe3c080c4c4636c64803e5c1f76按逆时针方向旋转eqIdbfe639eab78eafd2d40ea70aa5d3f21d后的eqId828dc8dc7259c510b6d63abf40f60e90;

(2)在(1)的条件下,eqId828dc8dc7259c510b6d63abf40f60e90可以由eqId7988923407b9abb78ef8ab45829678fa绕某点按顺时针方向旋转得到,则该点坐标为 ,旋转角的度数为 .

(3)eqId15c0dbe3c080c4c4636c64803e5c1f76的外接圆半径长 .

3.已知正方形eqId411b38a18046fea8e9fab1f9f9b80a5f,一等腰直角三角板的一个锐角顶点与eqId5963abe8f421bd99a2aaa94831a951e9重合,将此三角板绕eqId5963abe8f421bd99a2aaa94831a951e9点旋转时,两边分别交直线eqIda20cb2c77ea29b6eabbc477bc3743859于eqIde6670479a0083dd2dfd5ad55b47b1ab6.page number 0

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@@@6ae5cda6-99b7-4176-912d-fbb451714b74

(1)当eqIde6670479a0083dd2dfd5ad55b47b1ab6分别在边eqIda20cb2c77ea29b6eabbc477bc3743859上时(如图1),将eqId9eda61683bb1d4d62441f0625097b477绕eqId5963abe8f421bd99a2aaa94831a951e9点顺时针旋转eqIdc02b54dc6b3e1bb6544f47d4c8743fcf至eqIde742966e3711cfa53dce04022acf4bcc,求证:eqId2519c65ca5090d8cd448cab633ea1a1b;

(2)当eqIde6670479a0083dd2dfd5ad55b47b1ab6分别在边eqIda20cb2c77ea29b6eabbc477bc3743859所在的直线上时(如图2),线段eqId6efab4e70c12746740d011a9461b13fc之间又有怎样的数量关系,并证明你的结论:

(3)在图3中,作直线eqIdd40b319212a7e7528b053e1c7097e966交直线eqId6b14fa212bbddd28310d463fcdef7e62于eqIda5b1b15a4605fce993cb13aefbf40360两点,在(2)的条件下,若eqId5b02c51ce96d326f33c430cc884ea00b,eqIdfe14b7ecc401749db077e8965c25d161,求eqId20a541b81584a032f571159ea152c85a的长.

4.如图1,点eqId1dde8112e8eb968fd042418dd632759e是正方形eqId411b38a18046fea8e9fab1f9f9b80a5f两对角线的交点,分别延长eqId683c590673eece14fea3319c4fd5eb55到点eqId895dc3dc3a6606ff487a4c4863e18509,eqId828628c0876b45381c9a0edeb0fec236到点eqId2a30f3a8b673cc28bd90c50cf1a35281,使eqId4e16ead7fdee4751e871187dd85843e1,eqId9bab4646c1695b78fc09d8287d3453c8,然后以eqId307bd991211ec79b47a4be52933bb8e7、eqIda299d2b999568e80be8005565ba209a4为邻边作正方形eqIdb670c6d27ce68f17ac12c4efa1933db1,连接eqId77a7e4a6765ce78b05ee97764771e01f,eqIde6e490f703eb6c9bb1278c78ebc2d661.

@@@a1cdd942-1fbd-4b4f-88c8-1b255e66bdb9@@@564e9081-3219-4d8b-9de3-7558da6bb697

(1)求证:eqIdfbd99874843902d155f3f9dc26b924f1;

(2)如图2,正方形eqId411b38a18046fea8e9fab1f9f9b80a5f固定,将正方形eqIdb670c6d27ce68f17ac12c4efa1933db1绕点eqId1dde8112e8eb968fd042418dd632759e逆时针旋转eqIde170f206fdbbd834aad7580c727e2cc6角(eqId783d872617eed2bbd474035156b6caaf),得到正方形eqId9e837d949ac97755fb0d52b1837120f1;

①在旋转过程中,当eqId5d3010872e39c34cb5fe799a44eb850b是直角时,求eqIde170f206fdbbd834aad7580c727e2cc6的度数;

②若正方形eqId411b38a18046fea8e9fab1f9f9b80a5f的边长为2,在旋转过程中,eqIdcad0a19415e796564f30906f2e7dbf76长的最大值为______.

5.如图,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId21958ecce9a9fcccc2998d2ba7990c78,点D为平面上一点,连接eqId03902478df1a55bc99703210bccab910,将eqId03902478df1a55bc99703210bccab910绕着点A逆时针旋转eqId0efc7b22d85ff04a0ac89743f0bea1f2得到线段eqId68a83fdd2ba72a2dba0b6b10bb3e06b9,连接eqIde6e490f703eb6c9bb1278c78ebc2d661,取eqIde6e490f703eb6c9bb1278c78ebc2d661的中点F,取eqId0dc5c9827dfd0be5a9c85962d6ccbfb1的中点G,连接eqId9e52a8f07834cbbbe4224962672fbbb2,取eqId9e52a8f07834cbbbe4224962672fbbb2的中点M,连接eqId2273ae1ee99cec9c1304323bc9ebf75f.

     @@@e221b008-ab68-4e4a-93c9-5b2571f17c7a

(1)依题意补全图形;

(2)猜想eqIdaea869b465b92ca404a71fe84467cd35的度数(用含α的式子表示),并证明.

6.如图,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqIdb27e47690ed332c573186992b6d25654,eqIdb6b0a3fa475b24f57ecd79c681259561分别为eqId15c0dbe3c080c4c4636c64803e5c1f76的高.

@@@061d6031-10fb-486d-8414-0b6a7dcec500

(1)如图1,若eqIdbf9ad150cb1e4cd8977d4cc3d99be17c,eqIdcd946dad8b716592833a7bc14045a6d8,连接eqIde6e490f703eb6c9bb1278c78ebc2d661,求eqIde6e490f703eb6c9bb1278c78ebc2d661的长;

(2)如图2,连接eqIde6e490f703eb6c9bb1278c78ebc2d661,将eqIde6e490f703eb6c9bb1278c78ebc2d661绕点E逆时针旋转eqIdc02b54dc6b3e1bb6544f47d4c8743fcf到eqId49b50357a6545cae8348e3059312f520,连接eqIdd004d2d115b477ade6af7ddb93db0df8,G为线段eqIdd004d2d115b477ade6af7ddb93db0df8上一点,连接eqIdabf80148409afb32ced0b4f59f1ba709.若eqId2839d69901cbaa0346130931090ceb24,求证:eqIdca7c766967cd1549d874dcb9cddb4cb9;page number 1

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(3)如图3,若eqId53c5e845e9cdb524965853eaec87e15b,P是线段eqId03902478df1a55bc99703210bccab910上一动点,将线段eqId63a253c7fdf589ee3dece13d5b5b5732绕着点C逆时针旋转eqIdbe6a6301878fed2a01413020b27310a5至线段eqIdf53330c107f8245290a5a42c3d356acd,连接eqId30daf5241e554a4fc148e73e28ceb317.当eqId3525ddc5153fada64eaf14e50b536542取得最小值时,请直接写出eqIdd5fa7dd60b071d132afbfdaf170c1020的面积.

7.在eqIddd967903ed5a6f640a5b801ec8be0070中,eqIded10df4140819d5451773a45de66201b,eqId2fb01d2b57580731c8b807ac8cffc8ba,eqId7bb5b12692517a39c320f99a479eb055,将eqId15c0dbe3c080c4c4636c64803e5c1f76绕点B顺时针旋转一定的角度eqIde170f206fdbbd834aad7580c727e2cc6得到eqId321370fe42bc1216902ea19fbd2a5979,点A,C的对应点分别是D,E,连接eqId03902478df1a55bc99703210bccab910.

@@@1a51aa6e-5dc3-4678-b617-34d58450fd06

(1)如图1,当点E恰好在eqIdf52a58fbaf4fea03567e88a9f0f6e37e上时,求eqId23dc2d2dd56fcc67698c45a6e0e48f80的大小;

(2)如图2,若eqId97cf714ffb3fd5917a76b191640b55fe,点F是eqIdf52a58fbaf4fea03567e88a9f0f6e37e的中点,判断四边形eqIdaf045d2542c40f955a9de356b9b088c4的形状,并证明你的结论.

(3)如图3,若点F为eqId03902478df1a55bc99703210bccab910中点,直接写出eqId4cae70b8a9d2d2e96dea62c00ced04b9的最大值.

8.如图,eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId1b7d69c65b7427a60753ed6248e20d58,将eqId15c0dbe3c080c4c4636c64803e5c1f76绕点A逆时针方向旋转eqId3acc2ab8a03ec7d05f386c9ba2e49f8c得到eqIda25c28359f8d8da9eaf4672a6cf8ae4f,eqId0dc5c9827dfd0be5a9c85962d6ccbfb1与eqId39a0610d74da218154a7745619529101交于点G、F.

@@@e56089ab-67f8-42ac-a7bd-7454ce3003ae

(1)求eqId96dbf32210f81599fa2a02983ac84cac的度数;

(2)判断四边形eqId369eb8ad56da7dc1cdb7c43762be4bee的形状,并说明理由.

9.如图1,在eqIddd967903ed5a6f640a5b801ec8be0070中,eqId9ed8f7d3d7043d4b1eb98fc5c4e2fcd3,eqId4b10134e7a46e6f6f7cb9d5e2371727d,点eqId8455657dde27aabe6adb7b188e031c11为eqIdf52a58fbaf4fea03567e88a9f0f6e37e边上的一点,将eqId661ff55b5ebbadfb600989af3cfce2fd绕点eqIdc5db41a1f31d6baee7c69990811edb9f逆时针旋转eqIdc02b54dc6b3e1bb6544f47d4c8743fcf 得到eqIddcb49df05f2e31d005735c3f14a21d30,易得eqIdfe2c34a83631c3127ca5896e00cda297,连接eqId85c4bdfb0db1e31e8459df1d15f9ab55.

@@@a1d19bda-2407-4474-a532-cda4373a0db4

(1)求eqId6726c08ee7388500e560e89af08184be的度数;

(2)当eqId7788830ed1cb3b9c5988f70f43595f2e,eqId3d6bdfb0e1be5583e794ab614a8abe1b时,求eqId85c4bdfb0db1e31e8459df1d15f9ab55、eqId4eedae8d316c76e3d0b451256de03fb9的长;

(3)如图2,取eqId03902478df1a55bc99703210bccab910中点eqIda0ed1ec316bc54c37c4286c208f55667,连接eqId4cae70b8a9d2d2e96dea62c00ced04b9,交eqId85c4bdfb0db1e31e8459df1d15f9ab55于点eqId73465a1f9aa03481295bf6bd3c6903ac,试探究线段eqId85c4bdfb0db1e31e8459df1d15f9ab55、eqId4cae70b8a9d2d2e96dea62c00ced04b9的数量关系和位置关系,并说明理由.

10.将eqId56f3fbb2fdd9b947f14e047f3210d6ff按照如图所示位置放置在平面直角坐标系eqId7ee31829d0d4d5f779a957d7df8058ab中,eqId0dc5c9827dfd0be5a9c85962d6ccbfb1在x轴上方且与x轴平行,将eqId56f3fbb2fdd9b947f14e047f3210d6ff绕点B顺时针旋转一定的角度得到eqIdf98fb1fb0b83d88dc90952bcaae1548f.

@@@d2e451e1-166e-4573-8596-21ac64cc074e

(1)如图1,若点eqIde7c314398e26ffc7164b82946eeb4273落在eqIdef4113c492885ba7c47fe42ac792578f上,点eqIdb4c8a9c4957431681ddfc77895a88508恰好落在eqIdf52a58fbaf4fea03567e88a9f0f6e37e所在的直线上,求eqIda457b899731577bfe61dda594ae4eec4的度数.page number 2

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