生活情景折叠问题常考考点 预测练 2025年中考数学三轮复习备考

| 50页
| 142人阅读
| 4人下载

 

学科网 zxxk.com学科网 zxxk.com

生活情景折叠问题常考考点      预测练 

     2025年中考数学三轮复习备考

一、单选题

1.在一次数学实践课上,老师拿出一张三角形纸片eqId787ac5e13622afab5e9f8603afe42356,他问学生:通过一次折叠,一定能折出三角形的中线、高线、角平分线中的哪些线?班里四个同学给出不同答案:小高说:高线和中线;小雪说:中线和角平分线;小琪说:高线和角平分线;小嘉说:高线、中线和角平分线都可以.他们答案正确的是(    )

A.小高 B.小雪 C.小琪 D.小嘉

2.如图,在菱形纸片ABCD中,E是BC边上一点,将eqIde742966e3711cfa53dce04022acf4bcc沿直线AE翻折,使点B落在eqId3953cec61ac602ce5eb59b7912352179上,连接eqIdda650ee630c36fd5ce9abb4fb826df7b,已知eqIdbec9d84a3d9cf7443833f131986510bd,则eqIdf44303c7fa9fd275b9a4ce690e42cf85的度数为(   )

@@@7ed2431a-d8b0-4d3f-bce5-42e8a7c1d227

A.eqId2fb94bd9eb80fb9f5f02f518bb8f2211 B.eqIdbe6a6301878fed2a01413020b27310a5 C.eqIdc02b54dc6b3e1bb6544f47d4c8743fcf D.eqId391479c151307826c9765a47a5f10503

3.如图是一张三角形纸片,其中eqIdfccba2739e2feea6ff73a3290038838b,按如下步骤折纸:

第一步:将该纸片对折,点B 与点C 重合,折痕为eqId03902478df1a55bc99703210bccab910;

第二步:展开后,再将该纸片折叠;折痕为eqId85c4bdfb0db1e31e8459df1d15f9ab55,点A的对称点eqIde7c314398e26ffc7164b82946eeb4273恰好落在eqId60ef95894ceebaf236170e8832dcf7e3上

根据以上折纸过程,可以求出折痕eqId85c4bdfb0db1e31e8459df1d15f9ab55的长度为(   )

@@@7eb64ee9-bac2-446b-a1ca-f264ecdba33d

A.10 B.eqId20e27c4f3a7010a54c4b729b9e618dd4 C.eqIdcb4287b5b49d2e72fac87fee4cc626d1 D.eqId1bd7f6174d048177f092ae1a2f5af76a

4.如图,在平行四边形纸片eqId411b38a18046fea8e9fab1f9f9b80a5f中,对角线eqId989c75a3fd02e4971cab421c88de92f1交于点eqId1dde8112e8eb968fd042418dd632759e,将点eqId7f9e8449aad35c5d840a3395ea86df6d与点eqId5963abe8f421bd99a2aaa94831a951e9重叠对折,得折痕eqId49b50357a6545cae8348e3059312f520,点eqId2a30f3a8b673cc28bd90c50cf1a35281在eqIdf52a58fbaf4fea03567e88a9f0f6e37e边上,展开后连接eqId4eedae8d316c76e3d0b451256de03fb9交eqIdd40b319212a7e7528b053e1c7097e966于点eqId895dc3dc3a6606ff487a4c4863e18509,若eqId0bc1b68f13fed987f5209197de7bc8b4面积为2,则四边形eqId8df4437ed8be04615d252257b30a3a38的面积为page number 0

学科网 zxxk.com学科网 zxxk.com学科网(北京)股份有限公司


 

学科网 zxxk.com学科网 zxxk.com

(    )

@@@858f2654-0645-4bec-9b84-49406acebc7a

A.4 B.5 C.6 D.7

5.如图,在正方形纸片eqId5cb3f9a5da641be35117fd35ba07a6aa中,M,N分别是eqId1dd5cbe1df06719c569e916cea573267的中点,将纸片沿过点C的直线折叠,使点D落在eqIdaa29fe6cd9eb51c184f6299d437375cb上的点E处,折痕eqIde8120f2eeb724c756b5f84a14c6df527交eqId88929f4ba0851730d5f941d426b87548于点F,连接eqId21002725043bdace95b3244d4c75dd74,若eqId18913fc0d7481827383858a842c66ac4,则eqIdfaee0268e5ede6318697e5a8509dd6f7的长为(    )

@@@287ba363-febf-4ac4-b183-8c4019442c2d

A.eqIda4b8503f4706b8321e4e79a87eadea84 B.eqIda7ffe8515ff6183c1c7775dc6f94bdb8 C.eqId4324f8b8e4f3dac696bd32eb8e28db42 D.eqId690da13b35bda33eb00bffd7c00ed2ce

6.如图, 一张扇形纸片eqIde4819c39c281427826e1b3f7a4c2b720,eqId9ff5c21185c13eae675906dabd3593c7,eqId434845564fd5765244f8d1aa9240fa39, 将这张扇形纸片折叠,使点A 与点O重合,折痕为eqId9d78abbad68bbbf12af10cd40ef4c353,则图中未重叠部分(即阴影部分)的面积为(     )

@@@353d54a9-610a-4536-b05b-018d6417e373

A.eqId604d037b88148502a5608e0285c76f35 B.eqId41f97608426e9a818c5d8f93644a774e C.eqIdcfa9b3dec96c473c096530e893022a9f D.eqId5d98e6b3deb4ca271095f78259cd0814

7.如图,矩形纸片eqId411b38a18046fea8e9fab1f9f9b80a5f中,eqId3d2c15801fee2405573677484f5dcfa4,eqId267ace52b64e1e7dfc5211e033255b7d,点eqIddad2a36927223bd70f426ba06aea4b45是边eqId0dc5c9827dfd0be5a9c85962d6ccbfb1上的动点,现将纸片折叠,使点eqId5963abe8f421bd99a2aaa94831a951e9与点eqIddad2a36927223bd70f426ba06aea4b45重合,折痕与矩形边的交点分别为eqId2a30f3a8b673cc28bd90c50cf1a35281、eqIda0ed1ec316bc54c37c4286c208f55667,要使折痕始终与边eqIdf52a58fbaf4fea03567e88a9f0f6e37e、eqId03902478df1a55bc99703210bccab910有交点,则eqId2cdba1337ec85fa9722cb4b320a82ae6的取值范围是(    ).

@@@f31c6bec-86ac-481d-b6e2-70e1bb125925page number 1

学科网 zxxk.com学科网 zxxk.com学科网(北京)股份有限公司


 

学科网 zxxk.com学科网 zxxk.com

A.eqIdbaf5cc963d44442d374383373ed4ddbe B.eqId0a6af1a3251f65416a0c1961cb290a01 C.eqId4750caf95eb5c0a5d01332bfa7627338 D.eqIdade45b1cdf8a286b490f19fcb57a15a9

8.如图,已知平行四边形纸片eqId411b38a18046fea8e9fab1f9f9b80a5f,eqId3d2c15801fee2405573677484f5dcfa4,eqId07140f277a35733d8c97577ccdd4e3ab,eqId96251f9c30d745c1e6e3b60977722069.现将纸片作如下操作:第1步,沿折痕eqId85c4bdfb0db1e31e8459df1d15f9ab55折叠纸片,使点eqId5963abe8f421bd99a2aaa94831a951e9落在eqId0dc5c9827dfd0be5a9c85962d6ccbfb1边上;第2步,再沿折痕eqId5007d4aeb035e3081b8be1dd628e7565折叠纸片,使点eqId7f9e8449aad35c5d840a3395ea86df6d与点eqIdc5db41a1f31d6baee7c69990811edb9f重合.若eqIdc697c667e951df3f11503e1f4689c008,则eqId49b50357a6545cae8348e3059312f520的长为(     )

@@@a0d6060b-d705-4530-b58f-d4d34a644520

A.1 B.eqIdcaa585b9257ed0798213a9ae9b87d291 C.eqIda15aed058396d4cddf94125073da5f4a D.eqId9e2e332957bbfeb2e0643056b9aa1920

9.如图,对折等边eqId15c0dbe3c080c4c4636c64803e5c1f76纸片,展开铺平,折痕为eqIdc3407e83df0d037d628061f7a89b6b8a(如图1),再折叠纸片,使点eqId5963abe8f421bd99a2aaa94831a951e9,eqId7f9e8449aad35c5d840a3395ea86df6d都落在eqIdc3407e83df0d037d628061f7a89b6b8a上,且与点eqId8455657dde27aabe6adb7b188e031c11重合,折痕分别为eqId5481c3c38cf999b4dacada15ea517b8b和eqId7e3b37020a1975e5133c3971645f2849(如图2).在此基础上继续折叠,小聪和小明分别提供了以下两种方案:

小聪说:将纸片沿eqId0215e13a9fb5574d5194aeb9507a98aa向上折叠,使得点eqId73465a1f9aa03481295bf6bd3c6903ac落在点eqId895dc3dc3a6606ff487a4c4863e18509处.

小明说:将eqIdf067cc04f20977e65da4b15f2820e817对折,使得角两边eqId9171484a68c84cad91e4f2233392f600与eqId8946331b0a9d86e1a9c78797f3021455重合,折痕交eqIdc3407e83df0d037d628061f7a89b6b8a于点eqId895dc3dc3a6606ff487a4c4863e18509.

两种方案折叠后均展开铺平,连结eqIdfc8b62dc033d86ee9e561b8903796701,eqIdd87448e09eaa816e50ae92d111d5ded6,则以上方案中折出的四边形eqIdbd301516a8e0ab07f1e44022864d9b12为正方形的是(    )

@@@e7b70134-6ef4-4833-b1f9-f0ea21021efc

A.两个方案都能 B.小聪的方案

C.小明的方案两个方案都不能

10.如图,长方形纸片eqId411b38a18046fea8e9fab1f9f9b80a5f,点E、F分别在边eqIdf52a58fbaf4fea03567e88a9f0f6e37e、eqId9d78abbad68bbbf12af10cd40ef4c353上,连接eqId49b50357a6545cae8348e3059312f520.将eqIdea2ee75a234ac05a3225e49ddd8c5065对折,点B落在直线eqId49b50357a6545cae8348e3059312f520上的点eqId3953cec61ac602ce5eb59b7912352179处,得折痕eqId8b46c607b3deac746c0ef3389ad8f65c;将eqId1b6a23d521606a35298bbf147f7f830c对折,点A落在直线eqId49b50357a6545cae8348e3059312f520上的点eqIde7c314398e26ffc7164b82946eeb4273处,得折痕eqId6c4c865445dda4a59b6d5cb18fd74404,连接eqId274cf35acb4a1748d15c39d15a9bea7b.下列说法:page number 2

学科网 zxxk.com学科网 zxxk.com学科网(北京)股份有限公司


由于学科网是一个信息分享及获取的平台,不确保部分用户上传资料的 来源及知识产权归属。如您发现相关资料侵犯您的合法权益,请联系学科网,我们核实后将及时进行处理。