2025年中考数学总复习全等三角形模型的应用

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2025年中考数学总复习

 全等三角形模型的应用

 

 

1.如图,在正方形eqId411b38a18046fea8e9fab1f9f9b80a5f中,eqId3d2c15801fee2405573677484f5dcfa4,点eqIddad2a36927223bd70f426ba06aea4b45为正方形eqId411b38a18046fea8e9fab1f9f9b80a5f的对角线eqId60ef95894ceebaf236170e8832dcf7e3上一动点.

@@@a7822b6d-d9e8-4bc7-b13e-7cbe4abb2e5e

(1)如图①,过点eqIddad2a36927223bd70f426ba06aea4b45作eqId079feb0028639798bba5e205149a7601交边eqId9e52a8f07834cbbbe4224962672fbbb2于点eqId2a30f3a8b673cc28bd90c50cf1a35281.当点eqId2a30f3a8b673cc28bd90c50cf1a35281在边eqId9d78abbad68bbbf12af10cd40ef4c353上时,求证:eqIdaa1330569b47697ad0897ff9fcabc590;

(2)如图②,在(1)的条件下,过点eqId2a30f3a8b673cc28bd90c50cf1a35281作eqIddcb3ea779c9f0edb28aa521056831852,垂足为点eqIda0ed1ec316bc54c37c4286c208f55667,在点eqIddad2a36927223bd70f426ba06aea4b45的运动过程中,eqId4fb26d84907c923278ac4626a9d58947的长度是否发生变化?若不变,求出这个不变的值;若变化,试说明理由.

(3)如图③,若点eqIdacc290b44635265137fdf13146b6a6d9是射线eqId9d78abbad68bbbf12af10cd40ef4c353上的一个动点,连接eqId2cdba1337ec85fa9722cb4b320a82ae6,eqIdcb6ede9761b5b90f8dc137708e1ee90f,且始终满足eqId481542d5155de6160742b6ab1f9ea176,设eqId342323fd7396b3ae6c06879505089677,求eqId36a1b09c653185842513e24ebba60bb3的最小值.

2.综合与实践

【问题呈现】

(1)如图1,eqId15c0dbe3c080c4c4636c64803e5c1f76和eqIda25c28359f8d8da9eaf4672a6cf8ae4f都是等边三角形,连接eqIdd40b319212a7e7528b053e1c7097e966,eqId4eedae8d316c76e3d0b451256de03fb9.求证:eqId421291381be28da4bd16560fd383b4a9.

【类比探究】

(2)如图2,eqId15c0dbe3c080c4c4636c64803e5c1f76和eqIda25c28359f8d8da9eaf4672a6cf8ae4f都是等腰直角三角形,eqId21c2425db34d83dbe44f3ee3d2c5439b,连接eqIdd40b319212a7e7528b053e1c7097e966,eqId4eedae8d316c76e3d0b451256de03fb9,则eqId7d698ee39cd00a9b6384e0c4897a055a

【拓展提升】

(3)如图3,eqId67061e6fa526d1e082bed7b01c819982,eqId21c2425db34d83dbe44f3ee3d2c5439b,连接eqIdd40b319212a7e7528b053e1c7097e966,eqId4eedae8d316c76e3d0b451256de03fb9,若eqId8271a355c420aea6cad85beffd8ddac7.

①求eqIda9af91834644b94e1b023b33e15a0644的值;

②延长eqId4eedae8d316c76e3d0b451256de03fb9交eqIdd40b319212a7e7528b053e1c7097e966于点eqIda0ed1ec316bc54c37c4286c208f55667,则eqId95177426dca6af19b63dad1505811fe3 .

@@@a9b2fe50-89e9-4ce4-9567-7f03bde183bd

3.如图1,eqId90b40c2b0ab8e1cfe5112d428b4b829f和eqId3a0acc93490a6a784eb62201d93dd93d均为等边三角形,点A,D,E在同一直线上,连接eqId85c4bdfb0db1e31e8459df1d15f9ab55.

@@@0e8f442b-f538-4a51-9199-b9152c8ed260

(1)求证:eqIdc503e29373e8d87134bdb46bd3912910;

(2)求eqId1a55a1a244f81097e05e715b69580faa的度数;

(3)如图2,若eqId90b40c2b0ab8e1cfe5112d428b4b829f和eqId3a0acc93490a6a784eb62201d93dd93d均为等腰直角三角形,eqId0fc75953bf5dcfa4af308c34bf9952d3,点A,D,E在同一直线上,eqIde5e687e5dd7c9e8922070bcfb8176590于点page number 0

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M,连接eqId85c4bdfb0db1e31e8459df1d15f9ab55.试判断线段eqId99e5499314fc663cc84784273c31ebb6之间的数量关系,并说明理由.

4.在正方形eqId5cb3f9a5da641be35117fd35ba07a6aa中,点eqIdac047e91852b91af639feec23a9598b2,eqId2a30f3a8b673cc28bd90c50cf1a35281,分别是eqIdb79dd200766db27fb90d6bd1992cf658,eqId88929f4ba0851730d5f941d426b87548边上一动点(不与A,B,D点重合),连接eqId80f30cb81835298cb612a828f355060a,eqId80f30cb81835298cb612a828f355060a的延长线交eqId971b23e3ee827018557d6c88edd5369a的延长线于点eqId54a5d7d3b6b63fe5c24c3907b7a8eaa3.

@@@9f188355-5f35-4a71-aa39-b2e3494a40dc

(1)如图1.当eqIdab999690a7689b4f8113f16930e71fa7时,若eqId5805aa8e3ec016f65b15ab4b987a78af,求eqIdaa29fe6cd9eb51c184f6299d437375cb的长;

(2)如图2,过点A作eqId8b3d2cec6cdd4b16be38e6898b96d61c于点G,连接eqId999a995a6d07c561ce64e8952994160a,有eqIde748ebeb0e3167ab8fb26a9c5537b8f6,求证:eqId3bccb356d636d7466293ee5e24f77d0e.

(3)如图3,eqIdbbd78358a372a82609ea40081e3e55f9,将eqId21786fe6fbbd671ba5158f4a920b8884沿直线eqId80f30cb81835298cb612a828f355060a折叠,得到eqId563bcd0e827b0627c1ab69b339dd0f26.过点eqId2a30f3a8b673cc28bd90c50cf1a35281做eqId179f83b6490ae006ae5a536bd8b63db6交eqId764509115979e9958101808383672ec0于点eqId73465a1f9aa03481295bf6bd3c6903ac,连接eqIdf0a36775168095280f72504478345bce并延长交线段eqIdb79dd200766db27fb90d6bd1992cf658于点eqIddad2a36927223bd70f426ba06aea4b45,连接eqIdaf6cd332590b9eb4032b51a39134d219,当eqIdaf6cd332590b9eb4032b51a39134d219最大时,直接写出eqId80672dda9430cb42b3136bcb1b67bbad的值.

5.如图,点C在线段eqIdb3182db896bc2462331796e2a6108363上,eqId695a0ff0d56a064079961fc22293c064,eqIdd5adc18ca424552b35ab939e9d57943e.

@@@2e02a05c-18a4-4ca4-9cde-07bda6fa7298

(1)如图1,求证:eqId4d0c31fd3121ab5c4db372f691ceef99;

(2)如图2,连接eqIdb9f79d7939c88e9702962e5917cad290,点eqIdac047e91852b91af639feec23a9598b2为eqId68a83fdd2ba72a2dba0b6b10bb3e06b9中点.连eqIde69d2b798744645af88a4fa411344a83,eqId15a424b50eaeafa6f302ffd95476cb86,分别交eqId60ef95894ceebaf236170e8832dcf7e3,eqId4eedae8d316c76e3d0b451256de03fb9于eqId895dc3dc3a6606ff487a4c4863e18509.eqId73465a1f9aa03481295bf6bd3c6903ac,猜想eqId2f0e65e147b109f2bbfd3a3f502bbc3a与eqId2ef9d0784478511736255074b9395fae关系,并加以证明;

(3)如图3,在(2)的条件下,连接eqIdcafbe2751f4f4c5a8e676818195e9111;求证:eqIde16fbd5bfc57ca62b0f1b5a8eee04aca.

6.通过类比联想、引申拓展研究典型题目,可达到解一题知一类的目的.下面是一个案例,请补充完整.

@@@af4c94e4-e269-4ce3-8689-f3e582a11594     @@@1017a9b0-1ffb-4ae6-a3d9-739b72a7cc59

原题:如图1,点eqId2a30f3a8b673cc28bd90c50cf1a35281、eqIda0ed1ec316bc54c37c4286c208f55667分别在正方形eqId411b38a18046fea8e9fab1f9f9b80a5f的边eqId0dc5c9827dfd0be5a9c85962d6ccbfb1、eqId9d78abbad68bbbf12af10cd40ef4c353上,eqId192155e6a3aade305b76b1eb7c75e30c,连接,

证明:eqId7c9af98a1a048b1e2f7c71e83c33498c.

(1)思路梳理

∵eqId2e735a28578ba191da6d4f3b0f8e8729,∴把eqIde742966e3711cfa53dce04022acf4bcc绕点A逆时针旋转eqIdc02b54dc6b3e1bb6544f47d4c8743fcf至eqId3bbd6f0a0412d0f43ce1f7c1d530e56e,使eqIdf52a58fbaf4fea03567e88a9f0f6e37e与eqId03902478df1a55bc99703210bccab910重合.

∵eqId5406da6da56fab36d73d59cdb6237fc9,∴eqId09b786297e18a79a55cfb976a1435ec7,点F、D、G共线,

证明eqId94cb21b1fcfa6e188e0ba5161edd1c92得eqId7c9af98a1a048b1e2f7c71e83c33498c.

请按此思路证明原题中eqId7c9af98a1a048b1e2f7c71e83c33498c.

(2)类比引申

如图2,在四边形eqId411b38a18046fea8e9fab1f9f9b80a5f中,eqId2e735a28578ba191da6d4f3b0f8e8729,eqIdce0d7095ddd69d6ceaf1065b1bc2c79d,点E、F分别在边eqIda20cb2c77ea29b6eabbc477bc3743859上,eqId192155e6a3aade305b76b1eb7c75e30c.若eqIdcb5b8de60ccfc78eb7707d1e22ca0de1都不是直角,则当eqIdfebc9a89d0d1c97b88c0f4acd32b4e67与eqId0c543c3ddc3723fde6bbfca3ea3b921b满足怎样的关系时,仍有eqId7c9af98a1a048b1e2f7c71e83c33498c,请说明理由.page number 1

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7.问题提出

(1)如图1,四边形eqId411b38a18046fea8e9fab1f9f9b80a5f是正方形,eqId41db498f025052df2dbb1e50ab672675______;

问题探究:

(2)如图2,四边形eqId411b38a18046fea8e9fab1f9f9b80a5f是正方形,点eqIdad056c25c0fdcbcc765eb5cbc6093f2b分别在eqId2c825d34ab4d4c221fca9e000d5d155f的延长线上,eqId345c91c9e67e6ee00a872078ab17f094,若eqIdb7cbfaec1d9dcaaf159b060163436113,eqIdfaffe3765c15f53305516895aa595a9b,求正方形eqId411b38a18046fea8e9fab1f9f9b80a5f的边长;

问题解决:

(3)如图3是某生态保护区示意图,eqId294f5ba74cdf695fc9a8a8e52f421328和eqIdb6a24198bd04c29321ae5dc5a28fe421是两条互相垂直的河流,交点为eqId1dde8112e8eb968fd042418dd632759e.现计划修建科研基地eqIddad2a36927223bd70f426ba06aea4b45和四个建在河边的监测站eqId7702b23146e75e38f54b023d5eae26bc,按照技术要求,点eqId01c74a907dda6bb7d9d56d009d9df253分别在线段eqId1d79eb551b8051aea9beeed2ce16f18f上,eqId22fe44c186dc85e0d9f820a79b83b38c.并且规划把eqIdb14aeac55d519010de23642ac22cfb0b区域建设成为观光旅游区,eqId866b81a8384cce4f24867baca2e6820c区域建设为生态科普基地.若规划的观光旅游区的面积为9平方千米,那么生态科普基地的面积是否存在最大值?若存在请求出最大值,若不存在,请说明理由.

@@@775f68ad-b3da-4f8a-b6a4-d33addf234c3

8.【问题发现】

(1)如图eqIdbdaa19de263700a15fcf213d64a8cd57,eqId15c0dbe3c080c4c4636c64803e5c1f76和eqIda25c28359f8d8da9eaf4672a6cf8ae4f均为等边三角形,点eqId7f9e8449aad35c5d840a3395ea86df6d,eqId8455657dde27aabe6adb7b188e031c11,eqId2a30f3a8b673cc28bd90c50cf1a35281在同一条直线上,连接eqId4eedae8d316c76e3d0b451256de03fb9,容易发现:eqIdca85984ac3628e78fb2de5dba1951f81线段eqIdd40b319212a7e7528b053e1c7097e966,eqId4eedae8d316c76e3d0b451256de03fb9之间的数量关系为______;eqId93ce3efd4d44c7928f3ee0f3deccd6b8eqId6282292819434a8905a212427613fd85的度数为______.

【类比探究】

(2)如图eqId61128ab996360a038e6e64d82fcba004,eqId15c0dbe3c080c4c4636c64803e5c1f76和eqIda25c28359f8d8da9eaf4672a6cf8ae4f均为等腰直角三角形,eqId26813466e2ee49a493881a4384fc8748,点eqId7f9e8449aad35c5d840a3395ea86df6d,eqId8455657dde27aabe6adb7b188e031c11,eqId2a30f3a8b673cc28bd90c50cf1a35281在同一条直线上,连接eqId4eedae8d316c76e3d0b451256de03fb9.试探究线段eqId85c4bdfb0db1e31e8459df1d15f9ab55,eqId4eedae8d316c76e3d0b451256de03fb9,eqIde6e490f703eb6c9bb1278c78ebc2d661之间的数量关系及eqId6282292819434a8905a212427613fd85的度数,并说明理由.

【问题解决】

(3)如图eqId5ca7d1107389675d32b56ec097464c14,eqIdfac1f0cd4f6ced6e310a71121dbf0c54,eqId1ff8ae0d9dec5c5ac41e4906c07dbae7,eqId214d99ce9f50286dcff41db85083c979,eqId047dc9795efa99b6fb9fdf9778085dab,请直接写出eqIde7dd37bdc8ebd0561555e698ee7f1bc6的值.

@@@052f34be-418e-4f2d-9a2e-1d92d11dac5d

9.如图,等边eqId15c0dbe3c080c4c4636c64803e5c1f76的边长为2,过点eqId5963abe8f421bd99a2aaa94831a951e9作直线eqId3c1dc52a8ba9f389800eb92dbd145bf5,点eqIddad2a36927223bd70f426ba06aea4b45在直线eqId411461db15ee8086332c531e086c40c7上,连接eqId2cdba1337ec85fa9722cb4b320a82ae6,将eqId2cdba1337ec85fa9722cb4b320a82ae6绕点eqId7f9e8449aad35c5d840a3395ea86df6d顺时针旋转eqIdc02b54dc6b3e1bb6544f47d4c8743fcf得到eqIdcb6ede9761b5b90f8dc137708e1ee90f,连接eqIdf53330c107f8245290a5a42c3d356acd,eqId7a5f1641947153c80b987320885a2b57.

@@@59397411-d1c4-4333-8552-6006b9f410ed

(1)如图1,当点eqIdacc290b44635265137fdf13146b6a6d9在eqId0dc5c9827dfd0be5a9c85962d6ccbfb1边上时,求eqIdf53330c107f8245290a5a42c3d356acd的长.

(2)将线段eqIdcb6ede9761b5b90f8dc137708e1ee90f沿着射线eqId0dc5c9827dfd0be5a9c85962d6ccbfb1方向平移,使点eqId7f9e8449aad35c5d840a3395ea86df6d与点eqIdc5db41a1f31d6baee7c69990811edb9f重合,点eqIdacc290b44635265137fdf13146b6a6d9的对应点为点eqId73465a1f9aa03481295bf6bd3c6903ac,得到线段eqIda6655e2fa64a32cd12fe0279afd65d73,连接eqId35d58f9019097bd05037aefd5c322916,eqIda5bdbbd3084ddc946e12d530d2192522.

①如图2,当eqId7a855335176fc36a15017f50a8561348是等边三角形时,求证:四边形eqIdfd6e5bc47920872da10cf6217ed77b7f是菱形;page number 2

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