1.1二次根式同步练习2024-2025学年 浙教版数学八年级下册

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1.1二次根式

学校:___________姓名:___________班级:___________考号:___________

 

一、单选题

1.下列判断正确的是eqIdfd995178601c2ad7b40f973d268c7bb7  eqId04582116cd765fcc5a52f44279ad6c94

A.带根号的式子一定是二次根式

B.eqId4bbd36c41ccb3cb078b4517bcc913c1f一定是二次根式

C.eqIdd34718b34eb7ad2171fd4b1d174765e5一定是二次根式

D.二次根式的值必定是无理数

2.无论eqId81dea63b8ce3e51adf66cf7b9982a248取何值,下列各式中一定有意义的是(  )

A.eqIdae270d1d4a21a0dd4cc2e1a69ea8ccc3 B.eqIda8990cf3e9ab0c8fad35d2432885728a C.eqIddc995a5f218ac8772f249835006571a6 D.eqIda10183e5c7f36b7ba2941e163475a2fd

3.计算(eqIdcf298f00799cbf34b4db26f5f63af92f﹣eqIda7ffe8515ff6183c1c7775dc6f94bdb8)+|eqIdcf298f00799cbf34b4db26f5f63af92f﹣eqIda7ffe8515ff6183c1c7775dc6f94bdb8|的结果是(  )

A.0 B.2eqIdcf298f00799cbf34b4db26f5f63af92f﹣2eqIda7ffe8515ff6183c1c7775dc6f94bdb8 C.2eqIda7ffe8515ff6183c1c7775dc6f94bdb8﹣2eqIdcf298f00799cbf34b4db26f5f63af92f D.2eqIdcf298f00799cbf34b4db26f5f63af92f

4.函数 eqIdd177704474d007d9ddbfb9ce41633af5的自变量eqId81dea63b8ce3e51adf66cf7b9982a248的取值范围是(  )

A.eqId6cbb5670ce289817b8fecd270fad20ad B.eqIda3d9c89d2cd1fb46b1e71ad10227c098且eqId6cbb5670ce289817b8fecd270fad20ad C.eqIda154aa77357cb73cbcd37275d873a324且eqId6cbb5670ce289817b8fecd270fad20ad D.eqId124f08242308abb1041a73231d9ad1dc且eqId6cbb5670ce289817b8fecd270fad20ad

5.如果代数式eqId6dd426eb35614a7b6999548f007e152c在实数范围内有意义,那么x的取值范围是(    )

A.eqId9c5e1d979b2058ddc7fb7f4974c9c6de B.eqId4fd699e5a3a2d8f5d9d5888383a12e17 C.eqId16032b7b386bb684e6e70c1932b57998 D.eqId3962f8ea88ff244b5a987df638556d38

6.有下列式子:eqId50690dab38f4512eb72e18b7f86cf6f6,eqIdd012d124f04963fb72a68af40d5f8f42+1,eqIdeab4db5aaca3ab9a91077958c6f3e49d,eqIde817a254bab307a293670f60f8c1ef4c,eqIda1ab7f3314e8ec1582bbe96dfdf46a0f,eqId8c2298721a6c96c6a0529917677d8dd4,eqIdb99a0c76b00312992059983e0c47bb74. 其中一定是二次根式的有(    )

A.4个 B.3个 C.2个 D.1个

7.已知eqIdb3ae696df8aad85131467cf9c24b0df2,若eqIdd464f6926d5666db5836843f3d73dd71,则b的取值范围是(    )

A.eqIdd7925a4d2592cb38bd92cd9d6b4e732b B.eqIdf9ab54eb516d7e04f6a15abe37cd90f5 C.eqId026c7058cbdafd57bfc1e101595c0d44 D.eqIdce9bf94b3517798ecd483a8302be2d6f

8.要使二次根式eqId8c8c47867c01db1f8c5842401284d683在实数范围内有意义,则x的取值范围是(  )

A.x=eqIdeac97e6740365c85ad857aff85cefbe5 B.x≠eqIdeac97e6740365c85ad857aff85cefbe5 C.x≥eqIdeac97e6740365c85ad857aff85cefbe5 D.x≤eqIdeac97e6740365c85ad857aff85cefbe5

9.若二次根式eqId9959b7c998b19e92f388eb786b14d513有意义,则eqId81dea63b8ce3e51adf66cf7b9982a248的取值范围是(   )page number 0

 

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A.eqIdea5728768d5529ac8ee72366adfa5d24 B.eqIdb0645a2b8ae0a35b464adef465a536b8 C.eqId1e30ce45b2850240ac4b9c94644f043c D.eqIdf61b0a90de287907093b6d08431034d5

10.下列各式中,是二次根式有(  )

①eqId619096595112f0340a43b756e114dd3d;②eqId053014eda208deb38781688e0a22a51f;③eqId30860dc6b833418e7176a82cddb0ad2e;④eqId5b03e214bb66c576e458ee857d346047(x≤3);⑤eqId63e2802c610dc0d223f8fc524653fee5;⑥eqId09a0cc0c7fb3ed18be02367238690f3c; ⑦eqId78d7009d4cbe7157d63ce50444443716(ab≥0).

A.2个 B.3个 C.4个 D.5个

11.二次根式eqId2278a454a02953092e089003fe5e9bb2中的x的取值范围是(  )

A.x<﹣2 B.x≤﹣2 C.x>﹣2 D.x≥﹣2

12.当a是怎样的实数时,eqId5e4995832d7b618c1ac628afb1717597在实数范围内有意义(    )

A.eqId89e485cdded5198809073308e8f5329c B.eqIde5765e0d2d3922b129cff04b1a0dd3a9 C.eqIdfab6c1ef7fc0a549b4d0261653c68e1c D.eqIdbb805329c2b3e315c8940be25720afbd

 

二、填空题

13.eqId5fe26e5673a3af533756977a52122a72的算术平方根是       .

14.函数y=eqIda8990cf3e9ab0c8fad35d2432885728a的自变量x的取值范围为            .

15.使eqId15400ae2379b885746d92a8742e67493在实数范围内有意义的x的取值范围是      .

16.若eqIdf978101ea18a18196bc110ec1e965b29在实数范围内有意义,则实数x的取值范围是         .

17.当     时,式子eqIdf46934b057a0bfb8d5d100a7c620344b有意义.

 

三、解答题

18.求下列函数中自变量的取值范围:

(1)eqId031074c021f3bd60f9bf55a9d05046cf;

(2)y=eqIdd5565e05d772e1659f789b12291f3115;

(3)eqId6beb61aca7bd7053df541a808aac2b4d.

 

 

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19.已知eqId5b971a4b8059460920b6ac2761bff569求eqId6e5b66b06fbb44e77676d5e858d0b6f6的四次方根.

 

 

 

 

 

 

 

 

20.(体验探究题)   

(1)eqId7257666089e146a2924f207ece1db271 不是二次根式,原因是________;   

(2)eqIdd012d124f04963fb72a68af40d5f8f42 不是二次根式,原因是________;   

(3)eqId8b5a1a7a04d4c10e7a45714482bfb58d是二次根式吗?________(填“是”或“不是”);   

(4)根据(1),(2),(3)的提示,下列各式是二次根式的是________.  ①eqId4d83cf1b93420c07725ee688529cbd46② eqIda5b1625d21fa2fb85cf8c02d8e99f175③eqId39f3fae1304b36c0aa24d98d4ae0508b④eqId95ff338c867dcf59771d66989a29c93e⑤eqIdec686724bdc9ab59b3ec5dc68c5294c0⑥eqId5146bea4e7586be7f0424786b3debb26

 

 

 

 

 

 

 

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