专项代码2 常见代码合辑知识点梳理—2024届高考信息技术二轮复习知识点梳理

专项代码2 常见代码合辑 判断质数1 n = int(input("请输入一个数")) flag = True for i in range(2, n): if n%i==0: flag = False if flag: print(n, "是质数") else: print(str(n) + "不是质数") 判断质数2 import math n = int(input("请输入一个数")) flag = True for i in range(2, int(math.sqrt(n))+1): if n % i == 0: flag = False if flag: print(n, "是质数") else: print(str(n) + "不是质数") 求1-100之间范围内质数 import math for i in range(2, 101): flag = True x=int(math.sqrt(i)) + 1 for j in range(2,x ): if i % j == 0: flag = False if flag: print(i) 输出乘法口诀表 s="" for i in range(1, 10): for j in range(1, i + 1): s=str(j) + " * " + str(i) + " = " s=s+ str(i * j) print(s, end=" ") print() 表1.1 判断回文1 n = input() if n != n[::-1]: print("不是回文") else: print("是回文") 判断回文2 n = input() flag = True for i in range(0, len(n)//2): if n[i]!=n[len(n)-i-1]: flag = False if flag: print("是回文") else: print("不是回文") 2进制=>10进制方法1 n=input() res=0 for i in range(0,len(n)): res=res+int(n[i])*2**(len(n)-i-1) print(res) 2进制=>10进制方法2 n=input() res=0 for i in range(0,len(n)): res=res*2+int(n[i]) print(res) 10进制转2进制（原码） n=int(input()) res="" while n!=0: res=str(n%2)+res n=n//2 print(res) 10进制转16进制1 n = int(input()) res = "" while n != 0: if n % 16 > 9: res =chr(n % 16+55)+res else: res = str(n % 16)+res n = n // 16 print(res) 表1.2 10进制转16进制2（原码） n=int(input()) res="" root=["0","1","2","3","4","5","6","7", "8","9","A","B", "C","D","E","F"] while n!=0: res=root[n%16]+res n=n//16 print(res) 10进制转2进制（反码） 注: 例如30的原码是11110，反码00001 n=int(input()) res="" while n!=0: res=str(1-n%2)+res n=n//2 print(res) 求列表中最大值（不用Max函数版本）： ls = [] for i in range(1, 101): # 随机生成100个10-1000的随机数 ls.append(random.randint(10, 1000)) max1 = ls[0] for i in range(0, 100): # 因为ls下标从0开始 if ls[i] > max1: max1 = ls[i] print(max1) 求列表中最小值（不用Min函数版本）: ls = [] f