内容正文:
2023-2024学年七年级数学上学期复习备考高分秘籍【人教版】
专题2.5整式的加减及化简求值大题培优专练
班级:_____________ 姓名:_____________ 得分:_____________
一.解答题(共30小题)
1.化简:
(1)5m﹣7n﹣8p+5n﹣9m﹣p;
(2)(5x2y﹣7xy2)﹣(xy2﹣3x2y);
(3)2a﹣5b﹣3a+b;
(4)2x+(5x﹣3y)﹣2(3x+y);
(5)5ab2﹣3[2a2b﹣2(a2b﹣2ab2)];
(6)3(﹣3a2﹣2a)﹣[a2﹣2(5a﹣4a2+1)﹣3a].
2.化简并求值:
(1)(2x3﹣3x2﹣3)﹣(﹣x3+4x2),其中x=﹣1;
(2)已知,求5a2b﹣[2a2b﹣(ab2﹣2a2b)﹣4]﹣2ab2的值;
(3)已知a﹣b=2,求多项式的值;
(4)若0.5x|a|y4与是同类项,且a>b,求的值.
3.先化简再求值:
(1)(5ab+3a2﹣6b2)﹣(10ab﹣2a2+6b2),其中a=1,b.
(2)(2x﹣3y﹣4xy)﹣(x﹣4y+2xy),其中x+y=5,xy=﹣3.
(3)3(2x2y﹣3xy2)﹣(xy2﹣3x2y),其中x,y=﹣1.
4.先化简,再求值:
(1)5a2﹣4a2+a﹣9a﹣3a2﹣4+4a,其中a;
(2)5aba2ba2bab﹣a2b﹣5,其中a=1,b=﹣2;
(3)2a2﹣3ab+b2﹣a2+ab﹣2b2,其中a2﹣b2=2,ab=﹣3.
5.先去括号,再合并同类项:
﹣2n﹣(3n﹣1);
a﹣(5a﹣3b)+(2b﹣a);
﹣3(2a﹣5)+6a;
1﹣(2a﹣1)﹣(3a+3);
3(﹣ab+2a)﹣(3a﹣b);
14(abc﹣2a)+3(6a﹣2abc).
6.先去括号,再合并同类项:
6a2﹣2ab﹣2(3a2ab);
2(2a﹣b)﹣[4b﹣(﹣2a+b)];
9a3﹣[﹣6a2+2(a3a2)];
2t﹣[t﹣(t2﹣t﹣3)﹣2]+(2t2﹣3t+1).
7.将下列各式去括号,并合并同类项.
(1)(7y﹣2x)﹣(7x﹣4y)
(2)(﹣b+3a)﹣(a﹣b)
(3)(2x﹣5y)﹣(3x﹣5y+1)
(4)2(2﹣7x)﹣3(6x+5)
(5)(﹣8x2+6x)﹣5(x2x)
(6)(3a2+2a﹣1)﹣2(a2﹣3a﹣5)
8.先去括号,后合并同类项:
(1)x+[﹣x﹣2(x﹣2y)];
(2)a﹣(ab2)+3(ab2);
(3)2a﹣(5a﹣3b)+3(2a﹣b);
(4)﹣3{﹣3[﹣3(2x+x2)﹣3(x﹣x2)﹣3]}.
9.先去括号,再合并同类项;
(1)(3x2+4﹣5x3)﹣(x3﹣3+3x2)
(2)(3x2﹣xy﹣2y2)﹣2(x2+xy﹣2y2)
(3)2x﹣[2(x+3y)﹣3(x﹣2y)]
(4)(a+b)2(a+b)(a+b)2+(﹣3)2(a+b).
10.先去括号,再合并同类项:
(1)(x+y﹣z)+(x﹣y+z)﹣(x﹣y﹣z);
(2)3(2x2﹣y2)﹣2(3y2﹣2x2).
11.去括号,并合并同类项:
(1)2x2﹣(7+x)﹣x(3+4x);
(2)﹣(3a2﹣2a+1)+(a2﹣5a+7);
(3)4(a+b)﹣5(a﹣b)﹣6(a﹣b)+7(a+b)
12.先去括号,再合并同类项:
(1)(x+3)﹣(y﹣2x)+(2y﹣1);
(2)4(x+2x2﹣5)﹣2(2x﹣x2+1);
(3)3a+(a2﹣a﹣2)﹣(1﹣3a﹣a2);
(4)﹣5(x2﹣3)﹣2(3x2+5);
(5)3(ab﹣b2)﹣2(ab+3a2﹣2ab)﹣6(ab﹣b2)
13.去括号:
(1)4a﹣2(b﹣3c);
(2)﹣5a(4x﹣6);
(3)3x+[4y﹣(7z+3)];
(4)﹣3a3﹣[2x2﹣(5x+1)].
14.先化简,后求值:
(1)4a3b﹣10b3﹣3a2b2+10b3﹣4a3b,其中a=﹣1,b=2.
(2)4(m﹣n)2﹣(m﹣n)﹣3(m﹣n)2+(m﹣n),其中m=3,n=﹣2.
15.先化简,再求值:
(1)5a2+[2a2+(5a2﹣2a)﹣2(a2﹣3a)],其中
(2),其中x=3,.
16.先化简,再求值:x﹣{y﹣2x+[3x﹣2(2x+y)+5y]},其中x=﹣1,y=2.
17.先化简,再求值:2a2﹣{﹣3a+5[4a2﹣(3a2﹣a﹣1)﹣3]﹣5},其中a=﹣1.
18.化简求值:2(x2﹣xy)﹣3(2x2﹣3xy)﹣2x2,其中x=2,y=3.
19.已知a=﹣2,b=﹣3,c=1,求代数式3a2b﹣2(a2b﹣a2c)﹣