内容正文:
: t:i ** 10]N,t30)
1. F4^ , BEAABCACihM ( )
A. B
C. D.
2. 5^FtAKEWhErM NŽMF$tABÉF$TANMAA(
-2 - 0 2
)
A. x<-3 Dt x>1
3.#3m-5x3+m
A. <-
B. -3<x<I C. -3Kx<I
> 4*tx#-Ji F$t, W
B. SAS
D. -3<x<1
(4tÁM
B. x> C. x<-2 D. x>-2
9WA ODCA OEC#RAA0F R0C, 4ÈSLAOB,4. tuB,
(
A. SSS C. AAS D. HL
B. X+TÁSOAI C. f01 D. ZJ, 0Rã
(
D. k>-4
)
A. In AIS
6, 11 +3y =3
A, -4< k<0 B.-1<k<0 C. 0<k<8
7. EAIEAiK K#W3, 8, X, #xf A Wx t(
A, 34 B. 4^
8.ATx -A$AAA
A. a1 B. a> 1
C. 54 D. 67
)
C. as-1
t4 , #1
D. a<-1
9. uA. D1AB = AC, AD = AE, ikE BA ABDRAACE, (
(A. ZB LC
C. L1= L2
B. ZD= LE
D. LCAD= LDAC
B
2
)
D
EA
10. Ftx, y, z W=3x+4y+Sz,witHRk m, Rts
n, Um +n=(
A. 45
)
B. 45
-, N(*k 10, 30)
11. BÄPE ABÉM #HYHSE, PA=6, 9 PB=
12. #FFAA AS2 <x<3,Ma: b =
13. .BAZB=ZC.sn-t#AABD2AACE(F#
), MA#
,FRNHA
C. 54 D. s4
B
(13) (18)
14. tAr "a4FISbiFI#MAIT1TaibAM4":
15.LMaABC2ADEF. BC=EF=6cm, aABC HiE118 cm², NEFDE K
Cm.
J6. m= , (m-2)xl-ml+2s7R*Txt-i F9t.
X-2
18.Ju, A ABC, LC=90°,&DAT 1E:
OEAA ,TACMK*46F, t AB,ACTE,F:
2WPAAE,F ,*T}EFIKR4I , AAFG;
SFRAG, BCiD TD.#LCAB = 52', 0WZADC
19.
#4Bi, #2 i
20.u FB,EA ABC#,ERBC EA-Â, EC=2BE, ADAC#I
+ABA ABC,A ADF,A BEFORANIS,ABC SAADESABEP
#SABC = 12, USAADF-SABEP=
E,# (*KM 4 , #404+)
21. -7-FA:
)(3-2x<5 2) (2x+453(:x+2)
22. tnfr, BA!AB=AC,AD=AE, 1=22
(1) $E: BD=CE
(2)#LB=30° , $C AM
#4,
23. tiT, B AB=DC,DB=AC.
*\E: ZABD=DCA;
D
B C
24. AEAH A IAIB MAAt T
A!
B
200
180
AH5trT)300
260
(1)#-E, KASAE H t 30, #T5600G,UNA#A,B %
(2)T# , #_ EA E#Tt 9560JGNARIAMA 50
(3)E(2) MAF, %HRDAII BKRAW, WSHKAAKAHAA*?#RH
F:
t4 , #4M
新八年级数学骨假作业质量检测
学校:
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班级:
考号:
·、选择题(木大题共10小题,共30分)
1.下列四个图形中,线段BE是△ABC中AC边的高的是(
C
2.两个不等式的解集在数轴上表示如图.则这两个不等式组成的不等式组的解集是(C)
322
A.x<-3或x>1
B.-3<x<1
C.-3<x≤1
D.-3≤x<1
3.若3m-5x3*m>4是关于x的一元一次不等式,则该不等式的解是(C)
人x<-司
Bx>-司
C.x<-2
D.x>-2
人上%韩
①如图,用直尺和圆规作射线0C,使它平分zA0B,则△ODC兰△0BC的理由是
(A)
A.SSS
B.SAS
C.AAS
D.HL
5.下列命题是假命题的是(
e
A.直角都相等
B.对顶角相等
C.同位角相等
D.两点之间,线段最短
6.若方程组xY=+1的解满足0<x+y<1,则k的取值范围是
x+3y=3
(丹
3升>个
A.-4<k<0
B.-1<k<0
C.0<k<8
D.k>-4
31X>9
?己知三角形的三边长分别为3,8,x,若x的值为偶数,则x的