内容正文:
27
!"#$
£¤¥¦§¨+
(
"
)
"
、
KLM
1.D 2.B 3.A 4.B 5.D 6.C 7.B
8.C
ܰ
:
y߻v�
:x+y-5=0,x-y-3=0,
∴x=4,y=1.
∴
�:
=42-12=15.
ðü
:C.
9.A
ܰ
:∵
a8³5%½¾¿;%�2(3
,
}´%�2
=a2-b2,̧
%�2
=(a+b)(a-b).
∴a2-b2=(a+b)(a-b).
?hÀÁ®f%`:S
:a2-b2=(a+b)(a-b).
ðü
:A.
10.D
ܰ
:①2Å(-2)=2×(1+2)=6,ð①/�;
②�a+b=0,aÅa=a(1-a),bÅb=b(1-b),
H
(a
Å
a)+(b
Å
b)=a-a2+b-b2=-a2-b2=-2a2=2ab,
ð
②/�;
③aÅb=a(1-b),bÅa=b(1-a),ðaÅb)7Â34bÅa,
ð③U_;
④�aÅb=0,}a(1-b)=0,Ha=0Éb=1,ð④/�,O5/
�%q①②④.ðü:D.
;
、
NOM
11.6x3y3 12.-12 13.a≠±1
14.5
ܰ
:
§S
3a+2b,
×S
a+b
%§1|%�2S
:(3a+2b)(a
+b)=3a2+5ab+2b2,
∵A
ÎÏÐ%�2S
a2,B
ÎÏÐ%�2S
ab,C
ÎÏÐ%�2
S
b2,
∴
ØÖ
A
ÎÏÐ
3
Ó
,B
ÎÏÐ
5
Ó
,C
ÎÏÐ
2
Ó
,
ðQRS
:5.
15.①②③ ܰ:∵2n=6=2×3=2×2m=21+m,∴n=1+m,
∵2p=12=22×3=22+m,
∴p=2+m,∴p=n+1,
①m+p=n-1+n+1=2n,ð①/�;②m+n=p-2+p-1=2p-
3,
ð②/�;
③n2-mp=(1+m)2-m(2+m)=1+m2+2m-2m-m2=1,ð③
/�
;
ðQRS
:①②③.
;
、
PQM
16.
Ü
:(1)
�:
=4a4b2c6;
(2)
�:
=-2x5÷(14x
2)+3x3÷(14x
2)-12x
2÷(14x
2)
=-8x3+12x-2
(3)
�:
=4x2-y2+2y2=4x2+y2
(4)
�:
=(9a2-b2)2=81a4-18a2b2+b4
17.
Ü
:(1)
�:
=4a2-b2+(4a2b4-8a2b3)÷4a2b2=4a2-b2+b2-
2b=4a2-2b,
~
a=12,b=2018
-1= 12018 ,�:=4×
1
4-2×
1
2018=
1008
1009;
(2)
�:
=4x2-4x-4x2+9-x2+4x-4=-x2+5,
~
x=(-1)2018+(-12)
-2-(3.14-π)0=1+4-1=4 ,�:
=-16+5=-11.
18.
Ü
:
9S
(x-2)2+|y+3|=0,
?h
x=2,y=-3,
.9S
(x+2y)2-(x-2y)2=x2+4xy+4y2-x2+4xy-4y2=8xy,
>
x=2,y=-3
ùW@
,
�:
=8×2×(-3)=-48.
19.
Ü
:(1)∵ab=2a×2b,
∴23=22×23=4×8=32;
(2)∵2(x+1)=16,∴22×2x+1=24,H2+x+1=4,Ü@:x=1.
20.
Ü
:(1)∵2x=3,2y=5,
∴2x+y=2x×2y=3×5=15;
(2)∵x-2y+1=0,∴x-2y=-1,
∴2x÷4y×8=2x-2y+3=22=4.
21.
Ü
:(1)
VWß»@
:(3a+b)(2a+b)-(a+b)2=6a2+3ab+2ab
+b2-a2-2ab-b2=(5a2+3ab)̂
1í
.
Hòt%�2.
(5a2+3ab)̂
1í
;
(2)
~
a=10,b=8
,
�:
=500+240=740(̂
1í
),
740×100=74000(
ý
).
ðòtØÖ
74000
ýþZ
.
22.(1)①x3+8;②8m3+n3;
(2)(a+b)(a2-ab+b2)=a3+b3;
(3)C;
(4)8a3+27b3.
23.
Ü
:(1)x6+x5+x4+x3+x2+x+1;xn-1+xn-2+…+x4+x3+x2+x
+1;
(2)22019-1.
£¤¥¦§¨+
(
;
)
"
、
KLM
1.A 2.D 3.D 4.C 5.A 6.C 7.D
8.D
ܰ
:
¼
C
R
CF∥AB,∵AB∥DE,
∴AB∥DE∥CF,
∴∠1=∠β,∠α=180°-∠2,
∴∠α-∠β=180°-∠2-∠1=180°-∠BCD=90°,ðü:D.
9.C
ܰ
:∵AB∥CD,∴∠AEF+∠CFE=180°,
∵∠AEF=∠BEM=55°,∴∠CFE=125°,